Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
A survey was conducted on a group of students. It was found that 24 students like Cricket, 18 students like Football and 16 students like Hockey. If 7 students like exactly two of these games, and 2 students like all three, then the total number of students in the group must be:
Correct
Answer: (c)
Explanation:
Let Cricket = C, Football = F, Hockey = H.|C| = 24, |F| = 18, |H| = 16
All three = 2
Exactly two = 7Sum of pairwise intersections
= exactly two + 3 × (all three)
= 7 + 3 × 2 = 13Total students
= 24 + 18 + 16 − 13 + 2
= 58 − 13 + 2
= 47Hence, total number of students = 47.
Incorrect
Answer: (c)
Explanation:
Let Cricket = C, Football = F, Hockey = H.|C| = 24, |F| = 18, |H| = 16
All three = 2
Exactly two = 7Sum of pairwise intersections
= exactly two + 3 × (all three)
= 7 + 3 × 2 = 13Total students
= 24 + 18 + 16 − 13 + 2
= 58 − 13 + 2
= 47Hence, total number of students = 47.
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Question 2 of 5
2. Question
In a row of 55 students, P is 13th from the left and Q is 28th from the right. If they interchange their positions, P becomes 28th from the left. What is Q’s new position from the right?
Correct
Answer: (c)
Explanation:
After interchange, P becomes 28th from the left.
So Q’s original position from the left = 28.Now Q goes to P’s original position, that is 13th from the left.
Convert 13th from left into position from right:
= 55 − 13 + 1
= 43rdHence, option (c).
Incorrect
Answer: (c)
Explanation:
After interchange, P becomes 28th from the left.
So Q’s original position from the left = 28.Now Q goes to P’s original position, that is 13th from the left.
Convert 13th from left into position from right:
= 55 − 13 + 1
= 43rdHence, option (c).
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Question 3 of 5
3. Question
P and Q can finish a piece of work in 20 days and 12 days respectively. If they work together, they will receive Rs. 2500. With the help of R, they finish the work in 6 days. How much should R receive?
Correct
Answer: (a)
Explanation:
P’s 1-day work = 1/20
Q’s 1-day work = 1/12So, (P + Q)’s 1-day work = 1/20 + 1/12 = (3 + 5)/60 = 2/15
In 6 days, P + Q do = 6 × 2/15 = 12/15 = 4/5
So, R does the remaining 1/5 work.Work done in 6 days:
P = 6/20 = 3/10
Q = 6/12 = 1/2
R = 1/5Ratio = 3/10 : 1/2 : 1/5 = 3 : 5 : 2
Total parts = 10
R’s share = 2/10 of 2500 = Rs. 500Now, 20% of the total amount = 20/100 × 2500 = Rs. 500
Hence, option (a) is correct.
Incorrect
Answer: (a)
Explanation:
P’s 1-day work = 1/20
Q’s 1-day work = 1/12So, (P + Q)’s 1-day work = 1/20 + 1/12 = (3 + 5)/60 = 2/15
In 6 days, P + Q do = 6 × 2/15 = 12/15 = 4/5
So, R does the remaining 1/5 work.Work done in 6 days:
P = 6/20 = 3/10
Q = 6/12 = 1/2
R = 1/5Ratio = 3/10 : 1/2 : 1/5 = 3 : 5 : 2
Total parts = 10
R’s share = 2/10 of 2500 = Rs. 500Now, 20% of the total amount = 20/100 × 2500 = Rs. 500
Hence, option (a) is correct.
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Question 4 of 5
4. Question
A player gets a maximum of 4 attempts to score. Probabilities in 1st, 2nd, 3rd and 4th attempts are 0.2, 0.2, 0.1 and 0.1 respectively. Find the probability of scoring at least once.
Correct
Answer: (c)
Explanation:
Probability of not scoring in the 1st attempt = 1 − 0.2 = 0.8
Probability of not scoring in the 2nd attempt = 1 − 0.2 = 0.8
Probability of not scoring in the 3rd attempt = 1 − 0.1 = 0.9
Probability of not scoring in the 4th attempt = 1 − 0.1 = 0.9So, probability of not scoring at all
= 0.8 × 0.8 × 0.9 × 0.9
= 0.5184Therefore, probability of scoring at least once
= 1 − 0.5184
= 0.4816Hence, the correct answer is (c).
Incorrect
Answer: (c)
Explanation:
Probability of not scoring in the 1st attempt = 1 − 0.2 = 0.8
Probability of not scoring in the 2nd attempt = 1 − 0.2 = 0.8
Probability of not scoring in the 3rd attempt = 1 − 0.1 = 0.9
Probability of not scoring in the 4th attempt = 1 − 0.1 = 0.9So, probability of not scoring at all
= 0.8 × 0.8 × 0.9 × 0.9
= 0.5184Therefore, probability of scoring at least once
= 1 − 0.5184
= 0.4816Hence, the correct answer is (c).
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Question 5 of 5
5. Question
A shopkeeper sells 3 notebooks and 5 pens for ₹180. What will be the cost of 6 notebooks and 10 pens?
Correct
Answer: (c)
Explanation:
Cost of 3 notebooks and 5 pens = ₹180Required: cost of 6 notebooks and 10 pens
Since 6 notebooks and 10 pens is exactly double of 3 notebooks and 5 pens, the cost will also be double.
So, required cost = 2 × 180 = ₹360
Hence, the correct answer is (c).
Incorrect
Answer: (c)
Explanation:
Cost of 3 notebooks and 5 pens = ₹180Required: cost of 6 notebooks and 10 pens
Since 6 notebooks and 10 pens is exactly double of 3 notebooks and 5 pens, the cost will also be double.
So, required cost = 2 × 180 = ₹360
Hence, the correct answer is (c).
