Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
X and Y start a business with capitals in the ratio 6:5. After 4 months, X withdraws one-third of his capital for the remaining 8 months, while Y increases his capital by 50% for the remaining 8 months. If the total profit at year end is ₹34,000, what is Y’s share?
Correct
Answer: (c)
Solution:
Let initial capitals be X = 6k, Y = 5k.
For first 4 months:
• X = 6k × 4
• Y = 5k × 4
For next 8 months:
• X = (6k − ⅓·6k) = 4k ⇒ 4k × 8
• Y = (5k + 50%) = 7.5k ⇒ 7.5k × 8
Total:
• X = 24k + 32k = 56k
• Y = 20k + 60k = 80k
Ratio = 56 : 80 = 7 : 10
Total parts = 17
Y’s share = (10/17) × 34,000 = ₹20,000.
Hence, option (c).Incorrect
Answer: (c)
Solution:
Let initial capitals be X = 6k, Y = 5k.
For first 4 months:
• X = 6k × 4
• Y = 5k × 4
For next 8 months:
• X = (6k − ⅓·6k) = 4k ⇒ 4k × 8
• Y = (5k + 50%) = 7.5k ⇒ 7.5k × 8
Total:
• X = 24k + 32k = 56k
• Y = 20k + 60k = 80k
Ratio = 56 : 80 = 7 : 10
Total parts = 17
Y’s share = (10/17) × 34,000 = ₹20,000.
Hence, option (c). -
Question 2 of 5
2. Question
Two persons plan to hire a taxi. Person A has ₹9, which he finds is 60% of the taxi fare for both. His friend B gives him ₹7. Will the combined money be enough to pay the fare, and how much will be left or still needed?
Correct
Answer: (b)
Solution:
Let taxi fare for both = F.
60% of F = 9 ⇒ F = (9 × 100) / 60 = ₹15.
Total money = 9 + 7 = ₹16.
Balance = 16 – 15 = ₹1 left.
Hence, option (b) is correct.Incorrect
Answer: (b)
Solution:
Let taxi fare for both = F.
60% of F = 9 ⇒ F = (9 × 100) / 60 = ₹15.
Total money = 9 + 7 = ₹16.
Balance = 16 – 15 = ₹1 left.
Hence, option (b) is correct. -
Question 3 of 5
3. Question
A shopkeeper marks an item 40% above its cost price and offers a discount of 25% on the marked price. What is the shopkeeper’s profit percentage approximately?
Correct
Answer: (a)
Explanation:
Let cost price = 100.
Marked price = 100 × 1.40 = 140
Discount = 25%, so selling price = 140 × 0.75 = 105.
Profit = 105 – 100 = 5.
Profit % = 5%.Incorrect
Answer: (a)
Explanation:
Let cost price = 100.
Marked price = 100 × 1.40 = 140
Discount = 25%, so selling price = 140 × 0.75 = 105.
Profit = 105 – 100 = 5.
Profit % = 5%. -
Question 4 of 5
4. Question
A person sells two items at the same selling price of Rs. 1200 each. On one he gains 20%, and on the other he loses 20%. What is the overall percentage gain/loss?
Correct
Answer: (b)
Explanation:
Let the cost price of first item (with 20% gain) = x
⇒ SP = 1200 ⇒ x = 1200 / 1.20 = 1000Second item sold at 20% loss:
⇒ SP = 1200 ⇒ CP = 1200 / 0.80 = 1500Total CP = 1000 + 1500 = 2500
Total SP = 1200 + 1200 = 2400Loss = 2500 − 2400 = 100
Loss% = 100/2500*100=4%Incorrect
Answer: (b)
Explanation:
Let the cost price of first item (with 20% gain) = x
⇒ SP = 1200 ⇒ x = 1200 / 1.20 = 1000Second item sold at 20% loss:
⇒ SP = 1200 ⇒ CP = 1200 / 0.80 = 1500Total CP = 1000 + 1500 = 2500
Total SP = 1200 + 1200 = 2400Loss = 2500 − 2400 = 100
Loss% = 100/2500*100=4% -
Question 5 of 5
5. Question
A trader mixes 26 kg of rice at ₹20/kg with 30 kg of another variety at ₹36/kg. He sells the mixture at ₹30/kg. What is his profit percentage?
Correct
Answer: (b)
Explanation:
Step 1: Calculate total cost price (CP):- Cost of 26 kg @ ₹20 = 26 × 20 = ₹520
- Cost of 30 kg @ ₹36 = 30 × 36 = ₹1080
- Total quantity = 26 + 30 = 56 kg
- Total CP = ₹520 + ₹1080 = ₹1600
Step 2: Selling Price (SP):
- Mixture sold @ ₹30 per kg
→ SP = 56 × 30 = ₹1680
Step 3: Profit = SP − CP = 1680 − 1600 = ₹80
Profit % = (80 / 1600) × 100 = 5%Incorrect
Answer: (b)
Explanation:
Step 1: Calculate total cost price (CP):- Cost of 26 kg @ ₹20 = 26 × 20 = ₹520
- Cost of 30 kg @ ₹36 = 30 × 36 = ₹1080
- Total quantity = 26 + 30 = 56 kg
- Total CP = ₹520 + ₹1080 = ₹1600
Step 2: Selling Price (SP):
- Mixture sold @ ₹30 per kg
→ SP = 56 × 30 = ₹1680
Step 3: Profit = SP − CP = 1680 − 1600 = ₹80
Profit % = (80 / 1600) × 100 = 5%
