Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
Two buses start towards each other at the same time from two cities that are 280 km apart. After 2 hours, the buses are still 40 km apart. If the average speed of the faster bus is 10 km per hour more than the average speed of the slower bus, what is the average speed, in km per hour, of the slower bus?
Correct
Answer: C
Solution:
Let x be the speed of the slower bus.Speed Time Distance
x 2 hrs 2x
x + 10 2 hrs 2(x + 10)Total distance covered in 2 hours = 280 − 40 = 240 km
So,
2x + 2(x + 10) = 240
2x + 2x + 20 = 240
4x + 20 = 240
4x = 220
x = 220/4 = 55 km/hrHence, option (c) is the correct answer.
Incorrect
Answer: C
Solution:
Let x be the speed of the slower bus.Speed Time Distance
x 2 hrs 2x
x + 10 2 hrs 2(x + 10)Total distance covered in 2 hours = 280 − 40 = 240 km
So,
2x + 2(x + 10) = 240
2x + 2x + 20 = 240
4x + 20 = 240
4x = 220
x = 220/4 = 55 km/hrHence, option (c) is the correct answer.
-
Question 2 of 5
2. Question
A car travels 150 km from City A to City B at an average speed of v km/h. Due to traffic, the car returns from City B to City A at a speed that is 10 km/h less than its onward speed. If the return journey takes 30 minutes (i.e. 1/2 hour) longer than the onward journey, which equation can be used to find v?
Correct
Answer: B
Solution:
Distance each way = 150 km
Onward speed = v km/h
Return speed = (v – 10) km/h
Time onward = 150/v
Time return = 150/(v – 10)
Given: return takes 1/2 hour more than onward
So, 150/(v – 10) = 150/v + 1/2
Hence, option (b) is the correct answer.Incorrect
Answer: B
Solution:
Distance each way = 150 km
Onward speed = v km/h
Return speed = (v – 10) km/h
Time onward = 150/v
Time return = 150/(v – 10)
Given: return takes 1/2 hour more than onward
So, 150/(v – 10) = 150/v + 1/2
Hence, option (b) is the correct answer. -
Question 3 of 5
3. Question
A bus and a car start from the same town towards the same destination 180 km away at the same time. The car runs 20% faster than the bus, but the car has to stop for 15 minutes on the way. Still, both reach the destination at the same time. What is the speed of the car?
Correct
Answer: C
Solution:
Time = Distance/Speed
Let the speed of the bus be X km/hr.
Distance = 180 km
Time taken by bus = 180/X hoursSpeed of car = 20% faster = 1.2X km/hr
Time taken by car (running time) = 180/(1.2X) = 180/(6X/5) = 150/X hoursAccording to the question, the car stopped for 15 minutes = 15/60 = 1/4 hour.
So,
Time taken by bus = Time taken by car + stoppage
180/X = 150/X + 1/4
180/X – 150/X = 1/4
30/X = 1/4
X = 30 × 4 = 120 km/hrSpeed of car = 1.2X = 1.2 × 120 = 144 km/hr
Hence, option (c) is the correct answer.Incorrect
Answer: C
Solution:
Time = Distance/Speed
Let the speed of the bus be X km/hr.
Distance = 180 km
Time taken by bus = 180/X hoursSpeed of car = 20% faster = 1.2X km/hr
Time taken by car (running time) = 180/(1.2X) = 180/(6X/5) = 150/X hoursAccording to the question, the car stopped for 15 minutes = 15/60 = 1/4 hour.
So,
Time taken by bus = Time taken by car + stoppage
180/X = 150/X + 1/4
180/X – 150/X = 1/4
30/X = 1/4
X = 30 × 4 = 120 km/hrSpeed of car = 1.2X = 1.2 × 120 = 144 km/hr
Hence, option (c) is the correct answer. -
Question 4 of 5
4. Question
Ravi goes to his coaching centre at a speed of 4 km/hour and reaches 20 minutes late. The next day he walks at 5 km/hour on the same route and reaches 10 minutes early. What is the distance between his home and the coaching centre?
Correct
Answer: B
Solution:
Let the required distance be x km.
Time taken at 4 km/hr = x/4 hours
Time taken at 5 km/hr = x/5 hoursAccording to the question, in the first case he is 20 minutes late and in the second case he is 10 minutes early.
So, the difference between the two times = 20 min + 10 min = 30 min = 30/60 = 1/2 hourSo,
x/4 – x/5 = 1/2
(5x – 4x)/20 = 1/2
x/20 = 1/2
x = 1/2 × 20 = 10 kmHence, the distance is 10 km.
So, option (b) is the correct answer.Incorrect
Answer: B
Solution:
Let the required distance be x km.
Time taken at 4 km/hr = x/4 hours
Time taken at 5 km/hr = x/5 hoursAccording to the question, in the first case he is 20 minutes late and in the second case he is 10 minutes early.
So, the difference between the two times = 20 min + 10 min = 30 min = 30/60 = 1/2 hourSo,
x/4 – x/5 = 1/2
(5x – 4x)/20 = 1/2
x/20 = 1/2
x = 1/2 × 20 = 10 kmHence, the distance is 10 km.
So, option (b) is the correct answer. -
Question 5 of 5
5. Question
Two friends start from Town A and Town B towards each other on the same road at 8:00 am. Ramesh takes 30 minutes to travel from A to B, while Suresh takes 60 minutes to travel from B to A. At what time will they meet?
Correct
Answer: C
Solution:
Let the distance between A and B be d.
Speed of Ramesh = d/30
Speed of Suresh = d/60
When they move towards each other, their relative speed = d/30 + d/60
Time to meet = d ÷ (d/30 + d/60)
= 1 ÷ (1/30 + 1/60)
= 1 ÷ (2/60 + 1/60)
= 1 ÷ (3/60)
= 60/3
= 20 minutes
They started at 8:00 am, so they will meet at 8:20 am.
Hence, option (c) is the correct answer.Incorrect
Answer: C
Solution:
Let the distance between A and B be d.
Speed of Ramesh = d/30
Speed of Suresh = d/60
When they move towards each other, their relative speed = d/30 + d/60
Time to meet = d ÷ (d/30 + d/60)
= 1 ÷ (1/30 + 1/60)
= 1 ÷ (2/60 + 1/60)
= 1 ÷ (3/60)
= 60/3
= 20 minutes
They started at 8:00 am, so they will meet at 8:20 am.
Hence, option (c) is the correct answer.
