Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
If 4 ≤ x ≤ 8 and 2 ≤ y ≤ 7, then what is the ratio of maximum value of (x + y) to minimum value of (x − y)?
Correct
Answer:(d)
Given: 4 ≤ x ≤ 8 and 2 ≤ y ≤ 7
So, the maximum value of x = 8 and maximum value of y = 7 Therefore, the maximum value of x + y = 8 + 7 = 15
For minimum value of x – y, we should minimize x and maximize y. So, we will take x = 4 and y = 7
Therefore, the minimum value of x – y = 4 – 7 = – 3
Hence, the required ratio = 15 / (-3) = -5
Incorrect
Answer:(d)
Given: 4 ≤ x ≤ 8 and 2 ≤ y ≤ 7
So, the maximum value of x = 8 and maximum value of y = 7 Therefore, the maximum value of x + y = 8 + 7 = 15
For minimum value of x – y, we should minimize x and maximize y. So, we will take x = 4 and y = 7
Therefore, the minimum value of x – y = 4 – 7 = – 3
Hence, the required ratio = 15 / (-3) = -5
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Question 2 of 5
2. Question
Consider the sequence
AB_CC_A_BCCC_BBC_C that follows a certain pattern. Which one of the following completes the sequence?
Correct
Answer:(c)
Given: AB_CC_A_BCCC_BBC_C
Since, there are 18 letters in the series, we can divide them in groups of 6 or 3. Dividing them in groups of 6, we get:
[ A B _ C C _ ] ; [ A _ B C C C ] ; [ _ B B C _ C ]
The pattern being repeated is ABBCCC. So, we can fill in the blanks as follows:
[ A B B C C C ] ; [ A B B C C C ] ; [ A B B C C C ]
Therefore, the required letters to complete the sequence are: B, C, B, A, C
Incorrect
Answer:(c)
Given: AB_CC_A_BCCC_BBC_C
Since, there are 18 letters in the series, we can divide them in groups of 6 or 3. Dividing them in groups of 6, we get:
[ A B _ C C _ ] ; [ A _ B C C C ] ; [ _ B B C _ C ]
The pattern being repeated is ABBCCC. So, we can fill in the blanks as follows:
[ A B B C C C ] ; [ A B B C C C ] ; [ A B B C C C ]
Therefore, the required letters to complete the sequence are: B, C, B, A, C
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Question 3 of 5
3. Question
Three friends — A, B, and C — invested in a business.
Question: Who invested the highest amount?Statement I: A’s investment was 4/5 of the total investment of B and C together.
Statement II: B’s investment was 2/3 of the total investment of A and C together.Correct
Answer: (c)
Solution:
From Statement I: A = (4/5) × (B + C) …(i)
From Statement II: B = (2/3) × (A + C) …(ii)Substituting (ii) into (i):
A = (4/5) × [(2/3)(A + C) + C]
A = (4/5) × [(2/3)A + (5/3)C] = (8/15)A + (20/15)C
Multiply both sides by 15: 15A = 8A + 20C
7A = 20C → A = (20/7)CNow from (ii):
B = (2/3) × (A + C) = (2/3) × [(20/7)C + C] = (2/3) × (27/7)C = (18/7)CThus, A = (20/7)C, B = (18/7)C, and C = C.
Hence, A > B > C, so A invested the highest amount.
Both statements were needed; neither alone was sufficient.
Hence, the correct answer is (c).Incorrect
Answer: (c)
Solution:
From Statement I: A = (4/5) × (B + C) …(i)
From Statement II: B = (2/3) × (A + C) …(ii)Substituting (ii) into (i):
A = (4/5) × [(2/3)(A + C) + C]
A = (4/5) × [(2/3)A + (5/3)C] = (8/15)A + (20/15)C
Multiply both sides by 15: 15A = 8A + 20C
7A = 20C → A = (20/7)CNow from (ii):
B = (2/3) × (A + C) = (2/3) × [(20/7)C + C] = (2/3) × (27/7)C = (18/7)CThus, A = (20/7)C, B = (18/7)C, and C = C.
Hence, A > B > C, so A invested the highest amount.
Both statements were needed; neither alone was sufficient.
Hence, the correct answer is (c). -
Question 4 of 5
4. Question
Consider the following statements:
I. If A=B>C<D=E, then B is always greater than C.
II. If K>L≤M<N, then K is always greater than N.Correct
Answer: (a)
Explanation:
- Statement I:
From B>C, it follows directly that B is greater than C, regardless of the equality with A or E. Thus, Statement I is correct. - Statement II:
From K>L and M<N, there is no direct comparison between K and N because the inequality directions change in the middle. Thus, Statement II is incorrect.
Therefore, only Statement I is correct
Incorrect
Answer: (a)
Explanation:
- Statement I:
From B>C, it follows directly that B is greater than C, regardless of the equality with A or E. Thus, Statement I is correct. - Statement II:
From K>L and M<N, there is no direct comparison between K and N because the inequality directions change in the middle. Thus, Statement II is incorrect.
Therefore, only Statement I is correct
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Question 5 of 5
5. Question
In a row, A is 7th from the left. B is 10th from the right. C sits exactly midway between A and B and is 12th from the left. How many persons are there in the row?
Correct
Answer: (b)
Solution:Let total be N. p(A)=7; p(B) from left = N−10+1 = N−9.
Midpoint p(C) = (7 + (N−9))/2 = (N−2)/2.
Given p(C)=12 ⇒ (N−2)/2=12 ⇒ N−2=24 ⇒ N=2
Incorrect
Answer: (b)
Solution:Let total be N. p(A)=7; p(B) from left = N−10+1 = N−9.
Midpoint p(C) = (7 + (N−9))/2 = (N−2)/2.
Given p(C)=12 ⇒ (N−2)/2=12 ⇒ N−2=24 ⇒ N=2
