Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
With reference to the above passage, the following assumptions have been made:
I. Trust enhances cooperation among different stakeholders and lowers the cost of doing business.
II. Countries with weak institutions cannot achieve entrepreneurial growth even if they provide financial incentives.Which of the above assumptions is/are valid?
Correct
Answer: (a)
Explanation:
Assumption I is correct: The passage explicitly states that “trust reduces the cost of transactions, speeds up decision-making, and encourages collaboration,” directly validating this assumption.
Assumption II is incorrect: Although weak institutions hinder trust, the passage does not assert that entrepreneurial growth is impossible in such settings—only that it becomes opportunistic or stagnant. The word “cannot” makes the assumption too absolute.
Therefore, only Assumption I is valid, making option (a) correct.Incorrect
Answer: (a)
Explanation:
Assumption I is correct: The passage explicitly states that “trust reduces the cost of transactions, speeds up decision-making, and encourages collaboration,” directly validating this assumption.
Assumption II is incorrect: Although weak institutions hinder trust, the passage does not assert that entrepreneurial growth is impossible in such settings—only that it becomes opportunistic or stagnant. The word “cannot” makes the assumption too absolute.
Therefore, only Assumption I is valid, making option (a) correct. -
Question 2 of 5
2. Question
A container is formed by surmounting a hemisphere on a right circular cylinder of the same radius as that of the hemisphere. If the volume of the container is 1863π m3 and the radius of the cylinder is 9 m, then find the height of the container.
Correct
Answer: c
Volume of the container = Volume of the cylinder + Volume of the hemisphere Volume of the container = π 92h + (2/3) π 93 = 1863π
= 81π (h + 6) = 1863π
Solving we get h = 17
So the height of the container = 17 + 9 = 26 m
Incorrect
Answer: c
Volume of the container = Volume of the cylinder + Volume of the hemisphere Volume of the container = π 92h + (2/3) π 93 = 1863π
= 81π (h + 6) = 1863π
Solving we get h = 17
So the height of the container = 17 + 9 = 26 m
-
Question 3 of 5
3. Question
In an 800 metre race, A beats B by 80 metres. In a 1000 metre race, B can give a start of 200 metres to C. By how much distance should A give a start to C so that A beats C by 160 metres in an 800 metre race?
Correct
Answer: (c)
Solution:
From 800 metres: A:B = 800:720 = 10:9.
From 1000 metres: B:C = 1000:800 = 5:4.
So A:B:C = 50:45:36.
When A runs 800, C runs (36/50) × 800 = 576.
To beat by 160, C should be at 640.
Required start = 640 − 576 = 64 metres.Incorrect
Answer: (c)
Solution:
From 800 metres: A:B = 800:720 = 10:9.
From 1000 metres: B:C = 1000:800 = 5:4.
So A:B:C = 50:45:36.
When A runs 800, C runs (36/50) × 800 = 576.
To beat by 160, C should be at 640.
Required start = 640 − 576 = 64 metres. -
Question 4 of 5
4. Question
By what least number should 392 be multiplied to obtain a perfect cube?
Correct
Answer: (b)
Solution:
Prime factorization of 392 = 2³ × 7².
For a perfect cube, powers of all primes must be multiples of 3.
Here, 2³ is already a cube, but 7² needs one more 7 to make 7³.
Hence, multiply by 7.
392 × 7 = 2744 = 14³.Incorrect
Answer: (b)
Solution:
Prime factorization of 392 = 2³ × 7².
For a perfect cube, powers of all primes must be multiples of 3.
Here, 2³ is already a cube, but 7² needs one more 7 to make 7³.
Hence, multiply by 7.
392 × 7 = 2744 = 14³. -
Question 5 of 5
5. Question
Choose the group which is different from the others:
Correct
Answer: (c)
Solution:
Each group seems to represent cubes of natural numbers, check each:
(a) 4³, 5³, 6³, 7³ → all perfect cubes.
(b) 2³, 3³, 4³, 5³ → all perfect cubes.
(c) 1³, 2³, 3³, 81 (not a cube, 81 = 3⁴) → one term not a cube.
(d) 3³, 4³, 5³, 6³ → all perfect cubes.
Hence, group (c) is different because 81 is not a perfect cube.Incorrect
Answer: (c)
Solution:
Each group seems to represent cubes of natural numbers, check each:
(a) 4³, 5³, 6³, 7³ → all perfect cubes.
(b) 2³, 3³, 4³, 5³ → all perfect cubes.
(c) 1³, 2³, 3³, 81 (not a cube, 81 = 3⁴) → one term not a cube.
(d) 3³, 4³, 5³, 6³ → all perfect cubes.
Hence, group (c) is different because 81 is not a perfect cube.
