Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
The price of wheat increased by 50%. A family reduced its consumption so that the expenditure increased by only 20%. If earlier they consumed 60 kg per month, what is the new consumption?
Correct
Answer: (a)
Explanation:
Initial price = ₹100 per kg.
Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000.
New expenditure = 6,000 + 20% of 6,000 = ₹7,200.
New price = 100 + 50% of 100 = ₹150.
So, 150 × new consumption = 7,200.
New consumption = 7,200 ÷ 150 = 48 kg.Incorrect
Answer: (a)
Explanation:
Initial price = ₹100 per kg.
Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000.
New expenditure = 6,000 + 20% of 6,000 = ₹7,200.
New price = 100 + 50% of 100 = ₹150.
So, 150 × new consumption = 7,200.
New consumption = 7,200 ÷ 150 = 48 kg. -
Question 2 of 5
2. Question
X and Y invest in the ratio 3:4. After 9 months, X triples his capital for the last 3 months, while Y continues with the same capital for the whole year. If the total profit is ₹51,000, find Y’s share.
Correct
Answer: (c)
Solution:
Let initial capitals be X = 3k, Y = 4k.
For first 9 months:
• X = 3k × 9
• Y = 4k × 9
For last 3 months:
• X = (9k) × 3 (tripled)
• Y = 4k × 3 (unchanged)
Total:
• X = 27k + 27k = 54k
• Y = 36k + 12k = 48k
Ratio = 54 : 48 = 9 : 8
Total parts = 17
Y’s share = (8/17) × 51,000 = ₹24,000.
Hence, option (c).Incorrect
Answer: (c)
Solution:
Let initial capitals be X = 3k, Y = 4k.
For first 9 months:
• X = 3k × 9
• Y = 4k × 9
For last 3 months:
• X = (9k) × 3 (tripled)
• Y = 4k × 3 (unchanged)
Total:
• X = 27k + 27k = 54k
• Y = 36k + 12k = 48k
Ratio = 54 : 48 = 9 : 8
Total parts = 17
Y’s share = (8/17) × 51,000 = ₹24,000.
Hence, option (c). -
Question 3 of 5
3. Question
Two brothers buy bus tickets. The elder one has ₹8, which he realizes is 40% of the total fare for both. The younger one gives him ₹5. How much more money do they still need to buy the tickets?
Correct
Answer: (c)
Solution:
Let total fare = F.
40% of F = 8 ⇒ F = (8 × 100) / 40 = ₹20.
Total money = 8 + 5 = ₹13.
Still needed = 20 – 13 = ₹7.Incorrect
Answer: (c)
Solution:
Let total fare = F.
40% of F = 8 ⇒ F = (8 × 100) / 40 = ₹20.
Total money = 8 + 5 = ₹13.
Still needed = 20 – 13 = ₹7. -
Question 4 of 5
4. Question
In a recruitment test, 50% candidates were male and 50% female. 40% of males and 60% of females cleared the screening test. In the final, 60% of males and 50% of females succeeded. Which of the following statements is correct?
Correct
Answer: (d)
Solution:
Total = 1000.
Males = 500, Females = 500.Screening:
Males = 500 × 40% = 200.
Females = 500 × 60% = 300.Final success:
Males = 200 × 60% = 120.
Females = 300 × 50% = 150.Success rates:
Men = 120/500 = 24%.
Women = 150/500 = 30%.Overall = (120+150)/1000 = 270/1000 = 27%.
So, women’s rate is higher (30% vs 24%).
Incorrect
Answer: (d)
Solution:
Total = 1000.
Males = 500, Females = 500.Screening:
Males = 500 × 40% = 200.
Females = 500 × 60% = 300.Final success:
Males = 200 × 60% = 120.
Females = 300 × 50% = 150.Success rates:
Men = 120/500 = 24%.
Women = 150/500 = 30%.Overall = (120+150)/1000 = 270/1000 = 27%.
So, women’s rate is higher (30% vs 24%).
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Question 5 of 5
5. Question
A factory has to supply 50,000 units of a spare part. It produces 2,000 units/day, but 8% are defective. After 15 days, a new machine increases production to 2,500 units/day, but now 5% are defective. In how many days will the order be fulfilled?
Correct
Answer: (a)
Solution:
First 15 days:
Daily good units = 2,000 – 8% of 2,000 = 1,840.
In 15 days = 15 × 1,840 = 27,600.Remaining = 50,000 – 27,600 = 22,400.
After machine:
Daily good = 2,500 – 5% of 2,500 = 2,375.Days required = 22,400 ÷ 2,375 = 9.43 ≈ 10 days.
Total days = 15 + 10 = 25 days.
Incorrect
Answer: (a)
Solution:
First 15 days:
Daily good units = 2,000 – 8% of 2,000 = 1,840.
In 15 days = 15 × 1,840 = 27,600.Remaining = 50,000 – 27,600 = 22,400.
After machine:
Daily good = 2,500 – 5% of 2,500 = 2,375.Days required = 22,400 ÷ 2,375 = 9.43 ≈ 10 days.
Total days = 15 + 10 = 25 days.
