Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
Consider the following question and the statement that follows:
Question: In a circus, rabbits and parrots are kept together in cages. How many rabbits are there?
Statement 1: The total number of heads is 35.
Statement 2: The total number of legs is 94.
Statement 3: The number of parrots is more than the number of rabbits.Which of the following is correct with respect to the above?
Correct
Answer: (a)
Explanation:
Let parrots = P (2 legs), rabbits = R (4 legs)
Each animal has one head, so:From Statement 1:
P + R = 35 → (Equation 1)From Statement 2:
2P + 4R = 94 → divide by 2:
P + 2R = 47 → (Equation 2)Subtract (1) from (2):
(P + 2R) − (P + R) = 47 − 35
R = 12 ⇒ rabbits = 12
P = 35 − 12 = 23So, we get a unique solution from Statement 1 and 2.
Statement 3 is not required.Incorrect
Answer: (a)
Explanation:
Let parrots = P (2 legs), rabbits = R (4 legs)
Each animal has one head, so:From Statement 1:
P + R = 35 → (Equation 1)From Statement 2:
2P + 4R = 94 → divide by 2:
P + 2R = 47 → (Equation 2)Subtract (1) from (2):
(P + 2R) − (P + R) = 47 − 35
R = 12 ⇒ rabbits = 12
P = 35 − 12 = 23So, we get a unique solution from Statement 1 and 2.
Statement 3 is not required. -
Question 2 of 5
2. Question
A question is given followed by two statements:
Question: What is the percentage loss on selling a bicycle?
Statement I. The selling price was ₹840.
Statement II. The cost price was ₹1050.Options:
Correct
Answer: (d)
Explanation:
Statement I alone:
SP = ₹840, but CP is unknown → not sufficientStatement II alone:
CP = ₹1050, but SP is unknown → not sufficientTogether:
CP = ₹1050, SP = ₹840
Loss = ₹1050 − ₹840 = ₹210
Loss % = (210 / 1050) × 100 = 20%
So, both statements together are sufficientIncorrect
Answer: (d)
Explanation:
Statement I alone:
SP = ₹840, but CP is unknown → not sufficientStatement II alone:
CP = ₹1050, but SP is unknown → not sufficientTogether:
CP = ₹1050, SP = ₹840
Loss = ₹1050 − ₹840 = ₹210
Loss % = (210 / 1050) × 100 = 20%
So, both statements together are sufficient -
Question 3 of 5
3. Question
In a survey, people were asked if they preferred tea over coffee.
Question: How many people preferred coffee?
Statement I: 60% of the people preferred tea.
Statement II: 120 people preferred coffee.Which one of the following is correct in respect of the above Statements and the Question?
Correct
Answer: (b)
Solution:
- Statement I:
60% preferred tea ⇒ 40% preferred coffee
But total number of people is unknown ⇒ Not sufficient alone - Statement II:
120 people preferred coffee ⇒ Directly answers the question
⇒ Sufficient alone - Combining both:
Not needed. Statement II alone is enough.
Incorrect
Answer: (b)
Solution:
- Statement I:
60% preferred tea ⇒ 40% preferred coffee
But total number of people is unknown ⇒ Not sufficient alone - Statement II:
120 people preferred coffee ⇒ Directly answers the question
⇒ Sufficient alone - Combining both:
Not needed. Statement II alone is enough.
-
Question 4 of 5
4. Question
On a product, a store offers:
- Three successive discounts of 12%, 12%, and 5%, then GST of 10%.
- GST of 10% first, then three successive discounts of 12%, 12%, and 5%.
- Reordering the three discounts (any order), then GST of 10%.
Which statement is correct?
Correct
Answer: (d)
Solution:
Let the marked price be . Three successive discounts of multiply the price by . A 10% GST multiplies by .- Option 1 (discounts then GST): final factor .
- Option 2 (GST then discounts): final factor .
- Option 3 (any order of the three discounts, then GST): discounts commute, so the discount product is still ; applying GST gives .
Because multiplication is commutative, the overall factor is identical in all three cases. Thus, every option yields the same final price, .
Incorrect
Answer: (d)
Solution:
Let the marked price be . Three successive discounts of multiply the price by . A 10% GST multiplies by .- Option 1 (discounts then GST): final factor .
- Option 2 (GST then discounts): final factor .
- Option 3 (any order of the three discounts, then GST): discounts commute, so the discount product is still ; applying GST gives .
Because multiplication is commutative, the overall factor is identical in all three cases. Thus, every option yields the same final price, .
-
Question 5 of 5
5. Question
In an eligibility test, 50% were boys and 50% were girls. 60% of both boys and girls cleared prelims. In the final, 50% of both boys and girls (who cleared prelim) were successful. Which of the following is correct?
Correct
Answer: (c)
Solution:
Let total = 1000 ⇒ Boys = 500, Girls = 500.
Prelim: Boys = 500×0.60 = 300; Girls = 300.
Final: Boys = 300×0.50 = 150; Girls = 150.
Success rates: Boys = 150/500 = 30%; Girls = 150/500 = 30% (equal).
Overall = (150+150)/1000 = 300/1000 = 30% (<35%).
Hence only (c) is true.Incorrect
Answer: (c)
Solution:
Let total = 1000 ⇒ Boys = 500, Girls = 500.
Prelim: Boys = 500×0.60 = 300; Girls = 300.
Final: Boys = 300×0.50 = 150; Girls = 150.
Success rates: Boys = 150/500 = 30%; Girls = 150/500 = 30% (equal).
Overall = (150+150)/1000 = 300/1000 = 30% (<35%).
Hence only (c) is true.
