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Question 1 of 5
1. Question
A Main Statement is followed by four Statements labelled P, Q, R and S. Choose the ordered pair of the Statements where the first Statement implies the second, and the two Statements are logically consistent with the Main Statement.
Main Statement: Riya joins either Marketing or Finance.
Statement P: Riya is in Marketing.
Statement Q: Riya is in Finance.
Statement R: Riya is not in Marketing.
Statement S: Riya is not in Finance.Select the correct answer.
Correct
Answer: C
Explanation:
Option c is the correct answer.
Main Statement: Riya joins either Marketing or Finance.
This implies that Riya must be in one of the two roles (not neither).Pair Analysis:
SP: If Riya is not in Finance (S), then she must be in Marketing (P). Consistent.
RQ: If Riya is not in Marketing (R), then she must be in Finance (Q). Consistent.Hence, both SP and RQ follow logically and are consistent with the main statement.
Incorrect
Answer: C
Explanation:
Option c is the correct answer.
Main Statement: Riya joins either Marketing or Finance.
This implies that Riya must be in one of the two roles (not neither).Pair Analysis:
SP: If Riya is not in Finance (S), then she must be in Marketing (P). Consistent.
RQ: If Riya is not in Marketing (R), then she must be in Finance (Q). Consistent.Hence, both SP and RQ follow logically and are consistent with the main statement.
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Question 2 of 5
2. Question
A Question is given followed by two Statements I and II. Consider the Question and the Statements.
A two-digit number has distinct digits.
Question: What is the number?
Statement-I: The number is even and the sum of its digits is 11.
Statement-II: The difference between the digits is 3.Which one of the following is correct in respect of the above Question and the Statements?
Correct
Answer: c
Explanation
From Statement-I (even; sum = 11): possible two‑digit candidates include 92, 74, 56… (distinct digits and even), so not unique ⇒ not sufficient.
From Statement-II (difference = 3): possible pairs (7,4), (4,7), (8,5), (5,2), (9,6), (6,3)… ⇒ many numbers ⇒ not sufficient.
Combining: sum 11 and difference 3 ⇒ the digit pair must be (7,4) (since 7+4=11 and 7−4=3). With distinct digits and even, the number is 74 (47 is odd).
Hence, both together are required; option (c) is correct.Incorrect
Answer: c
Explanation
From Statement-I (even; sum = 11): possible two‑digit candidates include 92, 74, 56… (distinct digits and even), so not unique ⇒ not sufficient.
From Statement-II (difference = 3): possible pairs (7,4), (4,7), (8,5), (5,2), (9,6), (6,3)… ⇒ many numbers ⇒ not sufficient.
Combining: sum 11 and difference 3 ⇒ the digit pair must be (7,4) (since 7+4=11 and 7−4=3). With distinct digits and even, the number is 74 (47 is odd).
Hence, both together are required; option (c) is correct. -
Question 3 of 5
3. Question
A Question is given followed by two Statements I and II. Consider the Question and the Statements.
A two-digit number has tens digit A and units digit B.
Question: What is the number?
Statement-I: The sum of its digits is 9.
Statement-II: The number exceeds the number formed by reversing its digits by 27.Which one of the following is correct in respect of the above Question and the Statements?
Correct
Ans) c
Exp) Option c is the correct answer.
Let the number be 10A + B, with A ≠ B and A,B ∈ {0,1,…,9}, A ≠ 0.
Statement I: A + B = 9 → Multiple possibilities (e.g., 18, 27, 36, 45, 54, 63, 72, 81). Not sufficient.
Statement II: (10A + B) − (10B + A) = 27 → 9(A − B) = 27 → A − B = 3 → Multiple possibilities (e.g., 41, 52, 63, 74, 85, 96). Not sufficient.
Combining both:
A + B = 9 and A − B = 3 → Adding: 2A = 12 → A = 6 → Then B = 3 → Number = 63 (unique).Hence, both statements together are sufficient; neither alone is sufficient.
Incorrect
Ans) c
Exp) Option c is the correct answer.
Let the number be 10A + B, with A ≠ B and A,B ∈ {0,1,…,9}, A ≠ 0.
Statement I: A + B = 9 → Multiple possibilities (e.g., 18, 27, 36, 45, 54, 63, 72, 81). Not sufficient.
Statement II: (10A + B) − (10B + A) = 27 → 9(A − B) = 27 → A − B = 3 → Multiple possibilities (e.g., 41, 52, 63, 74, 85, 96). Not sufficient.
Combining both:
A + B = 9 and A − B = 3 → Adding: 2A = 12 → A = 6 → Then B = 3 → Number = 63 (unique).Hence, both statements together are sufficient; neither alone is sufficient.
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Question 4 of 5
4. Question
There are six people playing Hockey, namely P, Q, R, S, T and U. P and T are brothers. U is the sister of T. R is the only son of P’s uncle. If Q and S are the daughters of the brother of R’s father, then consider the following statements:
Statement I: There are exactly three females playing hockey.
Statement II: There are exactly three males playing hockey.
Statement III: U is the sister of T.How many of the above mentioned statements is/are correct?
Correct
Answer: c
Explanation
Given:
- P and T are brothers ⇒ both are males.
- U is the sister of T ⇒ U is female. Since P and T are brothers, U is also P’s sister.
- R is the only son of P’s uncle ⇒ R is male.
- Q and S are daughters ⇒ both are females.
Now:
- Statement I: Females = Q, S, U ⇒ exactly three ⇒ Correct.
- Statement II: Males = P, T, R ⇒ exactly three ⇒ Correct.
- Statement III: U is the sister of T ⇒ directly given ⇒ Correct.
Thus, all three statements are correct ⇒ option (c) is correct.
Incorrect
Answer: c
Explanation
Given:
- P and T are brothers ⇒ both are males.
- U is the sister of T ⇒ U is female. Since P and T are brothers, U is also P’s sister.
- R is the only son of P’s uncle ⇒ R is male.
- Q and S are daughters ⇒ both are females.
Now:
- Statement I: Females = Q, S, U ⇒ exactly three ⇒ Correct.
- Statement II: Males = P, T, R ⇒ exactly three ⇒ Correct.
- Statement III: U is the sister of T ⇒ directly given ⇒ Correct.
Thus, all three statements are correct ⇒ option (c) is correct.
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Question 5 of 5
5. Question
Ten students are standing in a row. If Rajesh picked two students randomly from the row, then what is the probability that the selected students are standing adjacent to each other?
Correct
Answer: (b)
The total number of ways of selecting two students out of 10 students = 10C2 = (10 × 9)/2 = 45 The number of ways two adjacent students may get selected is 9, i.e. (1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7), (7, 8), (8, 9) and (9, 10).
So, the required probability = 9/45 = 1/5 Hence, option (b) is the right answer.
Incorrect
Answer: (b)
The total number of ways of selecting two students out of 10 students = 10C2 = (10 × 9)/2 = 45 The number of ways two adjacent students may get selected is 9, i.e. (1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7), (7, 8), (8, 9) and (9, 10).
So, the required probability = 9/45 = 1/5 Hence, option (b) is the right answer.
