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Question 1 of 5
1. Question
Two statements are given below followed by a question:
S1: The number is greater than one.
S2: The number has 3 factors.
Question: What is the number if it is a positive integer < 11?
Which one of the following is correct with respect to above?
Correct
Answer: D
Solution
The number is greater than one. So, possible numbers will be: 2, 3……10
Thus, there is no unique solution. Therefore, S1 alone is not sufficient to answer the question.
From S2: The number has 3 Factors. 4 and 9 are such numbers, which have only 3 factors. Thus, there is no unique solution.
Therefore, S2 alone is not sufficient to answer the question.
From S1 and S2: Even on combining S1 and S2, we are not able to find a unique solution.
Therefore, S1 and S2 together are not sufficient to answer the question
Incorrect
Answer: D
Solution
The number is greater than one. So, possible numbers will be: 2, 3……10
Thus, there is no unique solution. Therefore, S1 alone is not sufficient to answer the question.
From S2: The number has 3 Factors. 4 and 9 are such numbers, which have only 3 factors. Thus, there is no unique solution.
Therefore, S2 alone is not sufficient to answer the question.
From S1 and S2: Even on combining S1 and S2, we are not able to find a unique solution.
Therefore, S1 and S2 together are not sufficient to answer the question
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Question 2 of 5
2. Question
A Salesman charges sales tax of x% up to Rs.4,000 and above it he charges y%. A customer pays a total tax of Rs 400 when he purchases goods worth Rs. 6,000 and he pays the total tax of Rs. 2200 for the goods worth Rs. 24,000. The value of x and y is:
Correct
Answer: C
Let the tax slab be:
- x% on the first ₹4,000
- y% on the amount above ₹4,000
For a purchase of ₹6,000:
For a purchase of ₹24,000:
Subtract (1) from (2): 9y=90⇒y=10.
From (1): 2x+10=20⇒2x=10⇒x=5Hence, x=5%, y=10%
Incorrect
Answer: C
Let the tax slab be:
- x% on the first ₹4,000
- y% on the amount above ₹4,000
For a purchase of ₹6,000:
For a purchase of ₹24,000:
Subtract (1) from (2): 9y=90⇒y=10.
From (1): 2x+10=20⇒2x=10⇒x=5Hence, x=5%, y=10%
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Question 3 of 5
3. Question
Five people M, N, O, P, and Q are sitting in a row. M is sitting next to N, and O is sitting next to P.
Now consider:- Statement I: Q is sitting at one end of the bench.
- Statement II: M is sitting at the second position from the right, and Q is not sitting next to N.
- Statement III: P is sitting to the immediate left of O.
Question: What is the position of Q?
How many of the given statements are required to answer the question?Correct
Answer: (d)
Solution:
Number seats 1–5 (left→right). From Stmt II, M = 4, and NNN is 3 or 5; also QQQ not next to NNN. From Stmt III, P immediately left of O ⇒ (P,O)(P,O)(P,O) is (1,2)(1,2)(1,2) or (2,3)(2,3)(2,3). From Stmt I, Q is at an end.
Two valid arrangements that satisfy I, II, III:
P O N M Q ⇒ Q=5Q=5Q=5 (with N=3N=3N=3)
Q P O M N ⇒ Q=1Q=1Q=1 (with N=5N=5N=5)
Since QQQ can be 1 or 5, the position isn’t unique.
Answer: (d) None of the above.Incorrect
Answer: (d)
Solution:
Number seats 1–5 (left→right). From Stmt II, M = 4, and NNN is 3 or 5; also QQQ not next to NNN. From Stmt III, P immediately left of O ⇒ (P,O)(P,O)(P,O) is (1,2)(1,2)(1,2) or (2,3)(2,3)(2,3). From Stmt I, Q is at an end.
Two valid arrangements that satisfy I, II, III:
P O N M Q ⇒ Q=5Q=5Q=5 (with N=3N=3N=3)
Q P O M N ⇒ Q=1Q=1Q=1 (with N=5N=5N=5)
Since QQQ can be 1 or 5, the position isn’t unique.
Answer: (d) None of the above. -
Question 4 of 5
4. Question
The average age of 60 students is 20 years. When 15 new students are admitted, the average increases by 0.4 years. What must be the average age of the new students?
Correct
Answer: (a)
Explanation:
Let the average age of the newly admitted 15 students be x years.
So, total age of the 15 new students = 15xGiven:
Average age of existing 60 students = 20
⇒ Total age of 60 students = 60 × 20 = 1200After 15 new students join, total students = 75
New average = 20 + 0.4 = 20.4
⇒ Total age of 75 students = 75 × 20.4 = 1530Now set up the equation:
1200 + 15x = 1530
⇒ 15x = 1530 − 1200 = 330
⇒ x = 330 ÷ 15 = 22Hence, the average age of the 15 new students is 22 years
Correct option: (a)Incorrect
Answer: (a)
Explanation:
Let the average age of the newly admitted 15 students be x years.
So, total age of the 15 new students = 15xGiven:
Average age of existing 60 students = 20
⇒ Total age of 60 students = 60 × 20 = 1200After 15 new students join, total students = 75
New average = 20 + 0.4 = 20.4
⇒ Total age of 75 students = 75 × 20.4 = 1530Now set up the equation:
1200 + 15x = 1530
⇒ 15x = 1530 − 1200 = 330
⇒ x = 330 ÷ 15 = 22Hence, the average age of the 15 new students is 22 years
Correct option: (a) -
Question 5 of 5
5. Question
Rahul walks from his home to the market at a speed of 4 km/hr and returns by bicycle at a speed of 12 km/hr. If the total time taken for the entire trip is 4 hours, what is the distance between his home and the market?
Correct
Answer: D
Solution:
Let the distance be x km.Time taken while walking = x/4
Time taken while cycling = x/12
Total time = 4 hours
So,
Take LCM:
Incorrect
Answer: D
Solution:
Let the distance be x km.Time taken while walking = x/4
Time taken while cycling = x/12
Total time = 4 hours
So,
Take LCM:
