Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
On a 150 cm track, points are marked from both ends. From the left end, first mark is at 5 cm, next 10 cm ahead, then 15 cm, etc. From the right end, same pattern starts. How many distinct points will be marked if overlapping ones are counted only once?
Correct
Solution: C
From left:
Marks at: 5, 15, 30, 50, 75, 105, 140
Next jump = 5 + 15 = 155 > 150 → stop
→ 7 pointsFrom right:
First mark at 5 cm from right ⇒ 145
Then:
145, 135, 120, 100, 75, 45, 10
→ 7 pointsLeft: 5, 15, 30, 50, 75, 105, 140
Right: 145, 135, 120, 100, 75, 45, 10Common point = 75
So total distinct = 7 + 7 – 1 = 13
Incorrect
Solution: C
From left:
Marks at: 5, 15, 30, 50, 75, 105, 140
Next jump = 5 + 15 = 155 > 150 → stop
→ 7 pointsFrom right:
First mark at 5 cm from right ⇒ 145
Then:
145, 135, 120, 100, 75, 45, 10
→ 7 pointsLeft: 5, 15, 30, 50, 75, 105, 140
Right: 145, 135, 120, 100, 75, 45, 10Common point = 75
So total distinct = 7 + 7 – 1 = 13
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Question 2 of 5
2. Question
A person bought 28 pens at Rs. x per pen. Later he found that with Rs. 168 more, he could have bought 4 more pens and reduced the average cost per pen by Rs. 1.50. What is the value of x?
Correct
Answer: (b)
Solution:
Total cost = 28x
New cost = 28x + 168
New pens = 32
New avg = x – 1.5⇒ 28x + 168 = 32(x – 1.5)
⇒ 28x + 168 = 32x – 48
⇒ 216 = 4x
⇒ x = 54Final Answer: Rs. 54
Incorrect
Answer: (b)
Solution:
Total cost = 28x
New cost = 28x + 168
New pens = 32
New avg = x – 1.5⇒ 28x + 168 = 32(x – 1.5)
⇒ 28x + 168 = 32x – 48
⇒ 216 = 4x
⇒ x = 54Final Answer: Rs. 54
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Question 3 of 5
3. Question
In a stadium, ticket prices for Platinum, Gold, and Silver are in the ratio 10 : 6 : 3. The spectators are in the ratio 1 : 2 : 5. If total revenue collected is ₹1,11,000, how much came from Silver ticket holders?
Correct
Answer – B
Solution:
Revenue parts:
Platinum: 10×1 = 10
Gold: 6×2 = 12
Silver: 3×5 = 15
Total = 10 + 12 + 15 = 37
Silver = 15
→ (15/37) × 1,11,000 = ₹45,000Incorrect
Answer – B
Solution:
Revenue parts:
Platinum: 10×1 = 10
Gold: 6×2 = 12
Silver: 3×5 = 15
Total = 10 + 12 + 15 = 37
Silver = 15
→ (15/37) × 1,11,000 = ₹45,000 -
Question 4 of 5
4. Question
A school employs 45 teachers and 30 support staff. The average salary of all employees is ₹40,000. Each support staff earns ₹10,000 less than a teacher. What is the monthly salary of a support staff member?
Correct
Answer – C
Solution:
Let support salary = ₹x → teacher = x + 10,000Total salary =
45(x + 10,000) + 30x = 45x + 4,50,000 + 30x = 75x + 4,50,000
Total employees = 75
Total = ₹40,000 × 75 = ₹30,00,00075x + 4,50,000 = 30,00,000
⇒ 75x = 25,50,000
⇒ x = ₹34,000Incorrect
Answer – C
Solution:
Let support salary = ₹x → teacher = x + 10,000Total salary =
45(x + 10,000) + 30x = 45x + 4,50,000 + 30x = 75x + 4,50,000
Total employees = 75
Total = ₹40,000 × 75 = ₹30,00,00075x + 4,50,000 = 30,00,000
⇒ 75x = 25,50,000
⇒ x = ₹34,000 -
Question 5 of 5
5. Question
Raj is rowing upstream from point A to point B, a distance of 40 km. He starts at a constant speed. Ten minutes later, a rescue boat leaves point A and overtakes him in 50 minutes.
Question: What is Raj’s rowing speed in still water?
Statement I: The speed of the current is 2 km/h.
Statement II: The rescue boat’s speed in still water is 10 km/h.Which one of the following is correct in respect of the Statements and the Question?
Correct
Answer: (c)
Explanation:
Let Raj’s speed = R, stream = x
Effective speed = R − x; Boat’s effective = 10 − 2 = 8
Time Raj rows = 60 min (10 + 50), Boat = 50 min
(R − 2)(1) = (8)(5/6) ⇒ R = 6.67 km/h
Need both x and boat speed ⇒ Answer: (c)Incorrect
Answer: (c)
Explanation:
Let Raj’s speed = R, stream = x
Effective speed = R − x; Boat’s effective = 10 − 2 = 8
Time Raj rows = 60 min (10 + 50), Boat = 50 min
(R − 2)(1) = (8)(5/6) ⇒ R = 6.67 km/h
Need both x and boat speed ⇒ Answer: (c)
