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Question 1 of 5
1. Question
Based on the above passage, the following assumptions have been made:
- Consumers prioritize fashion trends over environmental concerns in most purchasing decisions.
- Promoting sustainable fashion alone can reverse the environmental damage caused by the fashion industry.
Which of the assumptions given above is/are valid?
Correct
Answer: A
Explanation:
- Assumption 1 is valid. The passage criticizes fast-changing trends and short-term aesthetics, suggesting that most consumers value trends more than sustainability.
- Assumption 2 is invalid. The passage does not claim that promoting sustainable fashion alone will reverse the damage. In fact, it argues for systemic change, such as slower production cycles and aligned consumer behavior.
Thus, only Assumption 1 is valid → option (a) is correct.
Incorrect
Answer: A
Explanation:
- Assumption 1 is valid. The passage criticizes fast-changing trends and short-term aesthetics, suggesting that most consumers value trends more than sustainability.
- Assumption 2 is invalid. The passage does not claim that promoting sustainable fashion alone will reverse the damage. In fact, it argues for systemic change, such as slower production cycles and aligned consumer behavior.
Thus, only Assumption 1 is valid → option (a) is correct.
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Question 2 of 5
2. Question
12 persons are seated around a round table. What is the probability that two particular persons sit together?
Correct
Answer : A
Explanation :
In a circle of n different persons, the total number of arrangements possible = (n – 1)!
n(S) = (12 – 1) = 11 !
Taking two persons as a unit, total persons = 11
Therefore no. of ways for these 11 persons to around the circular table = (11 – 1)! = 10!
In any unit, 2 particular person can sit in 2! ways.
Hence total number of ways that any three person can sit,
=n(E) = 10! * 2!
Therefore P (E) = probability of three persons sitting together = n(E) / n(S)
= (10! * 2!)/11! = 2/11.
Incorrect
Answer : A
Explanation :
In a circle of n different persons, the total number of arrangements possible = (n – 1)!
n(S) = (12 – 1) = 11 !
Taking two persons as a unit, total persons = 11
Therefore no. of ways for these 11 persons to around the circular table = (11 – 1)! = 10!
In any unit, 2 particular person can sit in 2! ways.
Hence total number of ways that any three person can sit,
=n(E) = 10! * 2!
Therefore P (E) = probability of three persons sitting together = n(E) / n(S)
= (10! * 2!)/11! = 2/11.
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Question 3 of 5
3. Question
Find the sum of all the 4-digit numbers that can be formed with the digits 1, 1, 2, and 3.
Correct
Answer: D
Solution:
Given digits: 1, 1, 2, 3
Since 1 is repeated, total distinct permutations = 4! / 2! = 12
We calculate how many times each digit appears at each place (unit, tens, hundreds, thousands):
- Total positions = 12 numbers
- Each digit appears (12 × 1) / 4 = 3 times at each position
Now compute total sum:
- Digit sum at each place = (3 × 1) + (3 × 1) + (3 × 2) + (3 × 3) = 3 + 3 + 6 + 9 = 21
→ So, total sum =
= 21 × (1000 + 100 + 10 + 1) = 21 × 1111 = 23331Answer: (d) None of these
Incorrect
Answer: D
Solution:
Given digits: 1, 1, 2, 3
Since 1 is repeated, total distinct permutations = 4! / 2! = 12
We calculate how many times each digit appears at each place (unit, tens, hundreds, thousands):
- Total positions = 12 numbers
- Each digit appears (12 × 1) / 4 = 3 times at each position
Now compute total sum:
- Digit sum at each place = (3 × 1) + (3 × 1) + (3 × 2) + (3 × 3) = 3 + 3 + 6 + 9 = 21
→ So, total sum =
= 21 × (1000 + 100 + 10 + 1) = 21 × 1111 = 23331Answer: (d) None of these
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Question 4 of 5
4. Question
Anand went to Delhi on 5th Wednesday of April and returns to home on 5th Tuesday of June. He has to go back to Delhi to attend a meeting on International Youth Day. On which Day of the week International Youth Day falls?
Correct
Answer: B
Explanation:
June is a 30-day month.
In a 30-day month, all the seven days of week occur 4 times.
(7 × 4 = 28) and two days of the week occur 5 times.
These two days will be the first two or the last two days of the month.
It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June.
That means either 29 June is Tuesday or 30 November is Tuesday.
Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August
(1 + 31 + 12) = 44 => (7 × 6) + 2
Then 12th August is on Thursday. This is not given in the options.
Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August
(31 + 12) = 43 => (7 × 6) + 1
Thus, 12th August is on Wednesday.
Incorrect
Answer: B
Explanation:
June is a 30-day month.
In a 30-day month, all the seven days of week occur 4 times.
(7 × 4 = 28) and two days of the week occur 5 times.
These two days will be the first two or the last two days of the month.
It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June.
That means either 29 June is Tuesday or 30 November is Tuesday.
Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August
(1 + 31 + 12) = 44 => (7 × 6) + 2
Then 12th August is on Thursday. This is not given in the options.
Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August
(31 + 12) = 43 => (7 × 6) + 1
Thus, 12th August is on Wednesday.
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Question 5 of 5
5. Question
Consider the following statements and a question:
Question: In a test, who secured the highest marks among A, B, C, D, and E?
Statement I: A scored more than B and C but less than E.
Statement II: D scored more than E.
Statement III: C scored the least.
Which one of the following is correct in respect of the Statements and the Question?
Correct
Answer: A
Solution
From Statement I:
A > B, C; A < E ⇒ Order: B/C < A < E (Partial)From Statement II:
D > E ⇒ D is higher than ESo from I + II:
B/C < A < E < D ⇒ D is highest
→ I + II are sufficientStatement III: C is lowest → no new info about top scorer
Answer: (a) Statements I and II together are sufficient.
Incorrect
Answer: A
Solution
From Statement I:
A > B, C; A < E ⇒ Order: B/C < A < E (Partial)From Statement II:
D > E ⇒ D is higher than ESo from I + II:
B/C < A < E < D ⇒ D is highest
→ I + II are sufficientStatement III: C is lowest → no new info about top scorer
Answer: (a) Statements I and II together are sufficient.
