Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
Four people—Arun, Meena, Karan, and Seema—each wear a different color shirt: red, green, blue, and yellow. They attend meetings in four cities: Jaipur, Bhopal, Lucknow, and Hyderabad.
Clues:
- Meena didn’t go to Jaipur and didn’t wear red.
- The person wearing blue went to Lucknow.
- Seema went to Hyderabad.
- Karan wore green.
- The red shirt wasn’t worn in Jaipur.
Who wore what colour and visited which city?
Correct
Answer: (c)
Solution:
Clue (2): Blue → Lucknow ⇒ Arun: blue, Lucknow
Clue (4): Karan → green
Clue (3): Seema → Hyderabad
Clue (1): Meena ≠ Jaipur, ≠ red
Clue (5): Red ≠ JaipurTry option (c):
- Arun: blue, Lucknow
- Meena: yellow, Bhopal (≠ red, ≠ Jaipur)
- Karan: green, Jaipur
- Seema: red, Hyderabad
All clues satisfied
Incorrect
Answer: (c)
Solution:
Clue (2): Blue → Lucknow ⇒ Arun: blue, Lucknow
Clue (4): Karan → green
Clue (3): Seema → Hyderabad
Clue (1): Meena ≠ Jaipur, ≠ red
Clue (5): Red ≠ JaipurTry option (c):
- Arun: blue, Lucknow
- Meena: yellow, Bhopal (≠ red, ≠ Jaipur)
- Karan: green, Jaipur
- Seema: red, Hyderabad
All clues satisfied
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Question 2 of 5
2. Question
Consider the following question and the statements:
Question: What is the value of y?
Statement I: 5y−3=2y+6
Statement II: y+4=3y−2Which one of the following is correct?
Correct
Answer: B
Solution
- From Statement I:
5y−3=2y+6⇒3y=9⇒y=3 - From Statement II:
y+4=3y−2⇒−2y=−6⇒y=3 - → Both statements independently give the same value.
Answer: (b) The question can be answered by using either statement alone.
Incorrect
Answer: B
Solution
- From Statement I:
5y−3=2y+6⇒3y=9⇒y=3 - From Statement II:
y+4=3y−2⇒−2y=−6⇒y=3 - → Both statements independently give the same value.
Answer: (b) The question can be answered by using either statement alone.
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Question 3 of 5
3. Question
Consider the following question and the statements that follows:
Question: What is the value of z?
Statement I: 2z+5=3z−1
Statement II: 4z−3=2z+7Which one of the following is correct?
Correct
Answer: D
Solution
- From I: 2z+5=3z−1⇒z=6
- From II: 4z−3=2z+7⇒2z=10⇒z=5
→ Different values → contradiction.
Hence, neither statement alone gives a consistent answer, and together they contradict.
Incorrect
Answer: D
Solution
- From I: 2z+5=3z−1⇒z=6
- From II: 4z−3=2z+7⇒2z=10⇒z=5
→ Different values → contradiction.
Hence, neither statement alone gives a consistent answer, and together they contradict.
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Question 4 of 5
4. Question
One-fifth of a number is 10 less than one-third of the same number. What is the number?
Correct
Answer: C
Solution:
Let the number be x1/5x=1/3x−10
Multiply both sides by 15:
3x=5x−150⇒2x=150⇒x=75
Incorrect
Answer: C
Solution:
Let the number be x1/5x=1/3x−10
Multiply both sides by 15:
3x=5x−150⇒2x=150⇒x=75
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Question 5 of 5
5. Question
The ratio of the first to the second number is 2:5, and the ratio of the second to the third number is 5:3. If the product of the first and third numbers is 96, find the sum of the three numbers.
Correct
Answer: C
Solution:
First : Second = 2:5
Second : Third = 5:3
→ Combine to get: First : Second : Third = 2 : 5 : 3Let numbers be: 2x, 5x, 3x
Product of first and third = 2x×3x=6×2=96x2=16⇒x=4x^2 = 16 ⇒ x = 4 x2=16⇒x=4
So:
- First = 8
- Second = 20
- Third = 12
Sum = 8 + 20 + 12 = 40
Incorrect
Answer: C
Solution:
First : Second = 2:5
Second : Third = 5:3
→ Combine to get: First : Second : Third = 2 : 5 : 3Let numbers be: 2x, 5x, 3x
Product of first and third = 2x×3x=6×2=96x2=16⇒x=4x^2 = 16 ⇒ x = 4 x2=16⇒x=4
So:
- First = 8
- Second = 20
- Third = 12
Sum = 8 + 20 + 12 = 40
