Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
When a number is divided by 15, 20 and 35 each time the remainder is 8.Then the smallest possible number is:
Correct
Answer: A
Solution
LCM of (15, 20, 35)
= 5*3*4*7 = 420
Required number = 420+8 = 428
Incorrect
Answer: A
Solution
LCM of (15, 20, 35)
= 5*3*4*7 = 420
Required number = 420+8 = 428
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Question 2 of 5
2. Question
The LCM and the HCF of the numbers 14 and 28 are in the ratio of:
Correct
Answer: B
Solution
Numbers, x= 14 and y = 28
HCF of (14, 28)
HCF = 14
Now,
LCM of (14, 28)
14*1*2 = 28
LCM : HCF = 28 : 14 = 2 : 1
Incorrect
Answer: B
Solution
Numbers, x= 14 and y = 28
HCF of (14, 28)
HCF = 14
Now,
LCM of (14, 28)
14*1*2 = 28
LCM : HCF = 28 : 14 = 2 : 1
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Question 3 of 5
3. Question
The HCF and LCM of two 2-digit numbers are 8 and 240 respectively. The numbers are
Correct
Answer: A
Solution
Let numbers are 8x and 8y.
8xy = 240
xy = 30
Possible pairs = (1, 30), (2, 15), (5, 6)
Possible numbers = (8, 240), (16, 120), (40, 48)
Answer = (40, 48)
Incorrect
Answer: A
Solution
Let numbers are 8x and 8y.
8xy = 240
xy = 30
Possible pairs = (1, 30), (2, 15), (5, 6)
Possible numbers = (8, 240), (16, 120), (40, 48)
Answer = (40, 48)
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Question 4 of 5
4. Question
The LCM of two numbers is 3640 and their HCF is 78.if one of the number is 156, the other number is
Correct
Answer: B
Solution
LCM*HCF = a*b
a = First number
b = Second number
3640*78 = 156*b
b = 1820
Incorrect
Answer: B
Solution
LCM*HCF = a*b
a = First number
b = Second number
3640*78 = 156*b
b = 1820
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Question 5 of 5
5. Question
If the product of two numbers is 2560 and their HCF is 16.The LCM of the numbers will be
Correct
Answer: B
Solution
LCM*HCF = a*b
a = First number
b = Second number
LCM*16 = 2560
LCM = 160
Incorrect
Answer: B
Solution
LCM*HCF = a*b
a = First number
b = Second number
LCM*16 = 2560
LCM = 160
