Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
In a certain code language “EASY” is written as “5117”. In the same code language, how will “BEAM” be written as?
Correct
Answer: D
Explanation
EASY → E is the 5th alphabet in the series
A is the first alphabet in the series
S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1)
Y is the 25th alphabet, which makes it (2+5 = 7)
Hence, EASY = 5117
Similarly,
BEAM → B is the 2nd alphabet in the series
E is the 5th alphabet in the series
A is the 1st alphabet in the series
M is the 13th alphabet, which makes it (1+3 = 4)
Hence BEAM = 2514
Incorrect
Answer: D
Explanation
EASY → E is the 5th alphabet in the series
A is the first alphabet in the series
S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1)
Y is the 25th alphabet, which makes it (2+5 = 7)
Hence, EASY = 5117
Similarly,
BEAM → B is the 2nd alphabet in the series
E is the 5th alphabet in the series
A is the 1st alphabet in the series
M is the 13th alphabet, which makes it (1+3 = 4)
Hence BEAM = 2514
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Question 2 of 5
2. Question
“SPECIAL” is written as “65” in a certain code language what will “CONNECT” be coded as?
Correct
Answer: D
Explanation
SPECIAL → Sum of the place value of each alphabet in the alphabetical order
SPECIAL = 19+16+5+3+9+1+12 = 65
So, CONNECT = 3+15+14+14+5+3+20 = 74
Incorrect
Answer: D
Explanation
SPECIAL → Sum of the place value of each alphabet in the alphabetical order
SPECIAL = 19+16+5+3+9+1+12 = 65
So, CONNECT = 3+15+14+14+5+3+20 = 74
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Question 3 of 5
3. Question
If ‘BEAUTIFUL’ is coded as ‘97’ in a code language, then what will be the code for ‘WONDERFUL’?
Correct
Answer: C
Explanation
Given code:
BEAUTIFUL → 97
The alphabetical position of letter as follows
Sum of these numbers = 2 + 5 + 1 + 21 + 20 + 9 + 6 + 21 + 12 = 97
So, word ‘BEAUTIFUL’ will be coded as ‘97’.
Applying the similar concept in ‘WONDERFUL
So, sum of these numbers = 23 + 15 + 14 + 4 + 5 + 18 + 6 + 21 + 12 = 118
So, word ‘WONDERFUL’ will be coded as ‘118’.
Incorrect
Answer: C
Explanation
Given code:
BEAUTIFUL → 97
The alphabetical position of letter as follows
Sum of these numbers = 2 + 5 + 1 + 21 + 20 + 9 + 6 + 21 + 12 = 97
So, word ‘BEAUTIFUL’ will be coded as ‘97’.
Applying the similar concept in ‘WONDERFUL
So, sum of these numbers = 23 + 15 + 14 + 4 + 5 + 18 + 6 + 21 + 12 = 118
So, word ‘WONDERFUL’ will be coded as ‘118’.
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Question 4 of 5
4. Question
Directions for the following 2 (two) items: The digits from 0 to 9 are coded as shown below.
- Condition I. If a number begins and ends with zero or an even number, then the first and last digits are to be coded as A and λ (lamda) respectively.
- Condition II. If a number begins with one and ends with zero, then the first and last digits are to be coded as γ (gamma) and E respectively.
What is the code for 379150?
Correct
Answer: B
Explanation
For the given number none of the above two conditions are applicable. Hence code for ‘379150’ can simply
be derived from the chart given in the question.
379150 → ØE U⋆θZ
Incorrect
Answer: B
Explanation
For the given number none of the above two conditions are applicable. Hence code for ‘379150’ can simply
be derived from the chart given in the question.
379150 → ØE U⋆θZ
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Question 5 of 5
5. Question
What will be the code for 147689020?
Correct
Answer: D
Explanation
Here, the 2nd condition is applicable as the number begins with 1 and ends with 0. So, the first and last digits are to be coded as γ (gamma) and E respectively. Rest of the digits will be coded as per the chart given in the question. 147689020 → γMEcRUZXE
Incorrect
Answer: D
Explanation
Here, the 2nd condition is applicable as the number begins with 1 and ends with 0. So, the first and last digits are to be coded as γ (gamma) and E respectively. Rest of the digits will be coded as per the chart given in the question. 147689020 → γMEcRUZXE
