Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
The length of the base of a right-angled triangle is 40 cm and its hypotenuse is 41 cm long. What is its area and perimeter respectively?
Correct
Answer: C
Explanation
9,40,41 is a triplet pair.
Area of triangle = ½ bh = ½ *9*40 =180
Perimeter of triangle=9+40+41=90
Incorrect
Answer: C
Explanation
9,40,41 is a triplet pair.
Area of triangle = ½ bh = ½ *9*40 =180
Perimeter of triangle=9+40+41=90
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Question 2 of 5
2. Question
The lengths of three sides of a triangle are in the ratio 3:4:5. Among three sides, the difference between the largest side and the smallest side of this triangle is 3.6 cm. The area of this triangle is:
Correct
Answer: A
Explanation
Let the sides of a triangle are 3x, 4x and 5x respectively. (right angle triangle)
5x-3x = 3.6;
x = 1.8 cm ;
Area of triangle = ½ bh => ½ ×3x *4x
=>6 *1.8*1.8 =19.44
Incorrect
Answer: A
Explanation
Let the sides of a triangle are 3x, 4x and 5x respectively. (right angle triangle)
5x-3x = 3.6;
x = 1.8 cm ;
Area of triangle = ½ bh => ½ ×3x *4x
=>6 *1.8*1.8 =19.44
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Question 3 of 5
3. Question
One side of a rectangular field is 39cm and its diagonal is 89m. What is the area of the field?
Correct
Answer: B
Explanation
Breadth2 = Diagonal2 – Length2
=>892 – 392
=>6400 =>80
Required area = length * Breadth =80 *39 = 3120
Incorrect
Answer: B
Explanation
Breadth2 = Diagonal2 – Length2
=>892 – 392
=>6400 =>80
Required area = length * Breadth =80 *39 = 3120
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Question 4 of 5
4. Question
Which of the following migratory birds is commonly found in Bordoibam-Bilmukh Bird Sanctuary?
Correct
Solution: a)
The Spot-billed Pelican (Pelecanus philippensis), a migratory bird, is one of the prominent species found in the sanctuary, along with the Lesser Adjutant.
The Bordoibam-Bilmukh Bird Sanctuary (BBBS) in Assam has recorded a significant 72% decline in bird species over 27 years, primarily due to anthropogenic activities.
About Bordoibam-Bilmukh Bird Sanctuary:
- Location:Located on the border of Dhemaji and Lakhimpur districts in Assam.
- Established in:Declared a wildlife sanctuary in 1996.
- Habitat:Covers 11.25 sq. km of wetlands; experiences a moist tropical climate. Vegetation includes flooded valley grasslands and wetlands.
Major Flora and Fauna:
- Flora:Aquatic plants and grassland species.
Fauna: Migratory birds like Spot-billed Pelican (Pelecanus philippensis) and Lesser Adjutant (Leptoptilos javanicus); resident birds like the Indian Pond Heron and Fulvous Whistling Duck.
Incorrect
Solution: a)
The Spot-billed Pelican (Pelecanus philippensis), a migratory bird, is one of the prominent species found in the sanctuary, along with the Lesser Adjutant.
The Bordoibam-Bilmukh Bird Sanctuary (BBBS) in Assam has recorded a significant 72% decline in bird species over 27 years, primarily due to anthropogenic activities.
About Bordoibam-Bilmukh Bird Sanctuary:
- Location:Located on the border of Dhemaji and Lakhimpur districts in Assam.
- Established in:Declared a wildlife sanctuary in 1996.
- Habitat:Covers 11.25 sq. km of wetlands; experiences a moist tropical climate. Vegetation includes flooded valley grasslands and wetlands.
Major Flora and Fauna:
- Flora:Aquatic plants and grassland species.
Fauna: Migratory birds like Spot-billed Pelican (Pelecanus philippensis) and Lesser Adjutant (Leptoptilos javanicus); resident birds like the Indian Pond Heron and Fulvous Whistling Duck.
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Question 5 of 5
5. Question
A solid metallic sphere of radius 10 cm is melted and recast into spheres of radius 2 cm each. How many such spheres can be made?
Correct
Answer: D
Explanation
Radius of big sphere = R = 10 cm
Radius of small sphere = r = 2 cm
Number of small sphere = N
Volume of sphere = N × Volume of small sphere
4/3 π R3 = N * 4/3 π r3
103 = N *23
N=1000/8 =125
Incorrect
Answer: D
Explanation
Radius of big sphere = R = 10 cm
Radius of small sphere = r = 2 cm
Number of small sphere = N
Volume of sphere = N × Volume of small sphere
4/3 π R3 = N * 4/3 π r3
103 = N *23
N=1000/8 =125
