Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
Length of each side of a rhombus is 13 cm and one of the diagonals is 24 cm. What is the area (in cm²) of the rhombus?
Correct
Answer: D
Explanation
Other diagonal (d2)= √ (4a2 –d12) => √ (4(13)2 – 242 ) =>√676−576 = 10
Area of Rhombus = ½ *d1 *d2 => ½ *10 *24 =>120
Incorrect
Answer: D
Explanation
Other diagonal (d2)= √ (4a2 –d12) => √ (4(13)2 – 242 ) =>√676−576 = 10
Area of Rhombus = ½ *d1 *d2 => ½ *10 *24 =>120
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Question 2 of 5
2. Question
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
Correct
Answer: C
Explanation
Old length: new length = x: 3x
Old breadth: new breadth = 2y: y
Area of rectangle = Length * Breadth
Old area: new area = 2xy: 3xy = 2:3
Incorrect
Answer: C
Explanation
Old length: new length = x: 3x
Old breadth: new breadth = 2y: y
Area of rectangle = Length * Breadth
Old area: new area = 2xy: 3xy = 2:3
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Question 3 of 5
3. Question
The length of a rectangle is five times of its breadth. If the area of the rectangle is 3125, then what is the length of the rectangle?
Correct
Answer: C
Explanation
Length l = 5b;
Area =l*b=5b*b = 5b2 = 3125
b2=625; b=25; l=5b=125;
Incorrect
Answer: C
Explanation
Length l = 5b;
Area =l*b=5b*b = 5b2 = 3125
b2=625; b=25; l=5b=125;
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Question 4 of 5
4. Question
The perimeter of a rhombus is 148 cm and one of its diagonals is 24 cm. The area of the rhombus is:
Correct
Answer: B
Explanation
Perimeter 4a=148; a=37;
Other diagonal (d2)= √ (4a2 –d12) => √ (4(37)2 – 242 ) =>√5476−576 = 70
Area of Rhombus = ½ *24 *70 => 840
Incorrect
Answer: B
Explanation
Perimeter 4a=148; a=37;
Other diagonal (d2)= √ (4a2 –d12) => √ (4(37)2 – 242 ) =>√5476−576 = 70
Area of Rhombus = ½ *24 *70 => 840
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Question 5 of 5
5. Question
The lengths of three sides of a triangle are in the ratio 3:4:5. Among three sides, the difference between the largest side and the smallest side of this triangle is 3.6 cm. The area of this triangle is:
Correct
Answer: A
Explanation
Let the sides of a triangle are 3x, 4x and 5x respectively. (right angle triangle)
5x-3x = 3.6;
x = 1.8 cm ;
Area of triangle = ½ bh => ½ ×3x *4x
=>6 *1.8*1.8 =19.44
Incorrect
Answer: A
Explanation
Let the sides of a triangle are 3x, 4x and 5x respectively. (right angle triangle)
5x-3x = 3.6;
x = 1.8 cm ;
Area of triangle = ½ bh => ½ ×3x *4x
=>6 *1.8*1.8 =19.44
