Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
A defective watch shows a weird behavior. It gains 3 seconds per 5 minutes in the first hour, looses 6 seconds per 5 minutes in the second hour, gains 9 seconds per 5 minutes in the next one hour, and so on. If the watch showed the correct time at 6:00 a.m. on Friday, then what was the time it indicated at 9:00 p.m. on Saturday?
Correct
Answer: A
Explanation
Total time from 6:00 a.m. on Friday to 9:00 p.m. on Saturday = 24 + 12 + 3 = 39 hours
In first hour, it gains 3 sec in 5 min. So, in first hour it gains (3/5)×60 = 36 sec.
In second hour, it loses 6 sec in 5 min. So, in second hour it loses (6/5)×60 = 72 sec.
So, in 2 hours it loses 72 – 36 = 36 sec.
So, in 38 hours it loses (36/2) × 38 = 684 sec.
In 39th hour, it will gain 36 + (39 – 1)36 = 36×39 = 1404 sec.
So, total gain in time = 1404 – 684 = 720 sec = 12 mins.
So, the time displayed by the clock at 9 p.m. on Saturday = 9:00 p.m. + 12 minutes = 9:12 p.m.
Incorrect
Answer: A
Explanation
Total time from 6:00 a.m. on Friday to 9:00 p.m. on Saturday = 24 + 12 + 3 = 39 hours
In first hour, it gains 3 sec in 5 min. So, in first hour it gains (3/5)×60 = 36 sec.
In second hour, it loses 6 sec in 5 min. So, in second hour it loses (6/5)×60 = 72 sec.
So, in 2 hours it loses 72 – 36 = 36 sec.
So, in 38 hours it loses (36/2) × 38 = 684 sec.
In 39th hour, it will gain 36 + (39 – 1)36 = 36×39 = 1404 sec.
So, total gain in time = 1404 – 684 = 720 sec = 12 mins.
So, the time displayed by the clock at 9 p.m. on Saturday = 9:00 p.m. + 12 minutes = 9:12 p.m.
-
Question 2 of 5
2. Question
Two clocks are set to show the correct time at 6 a.m. One clock gains 3 minutes in an hour, while the other gains 5 minutes in an hour. By how many minutes will the two clocks differ at 10 p.m. on the next day?
Correct
Answer: A
Explanation
Difference in minutes between the two clocks in one hour = 5 – 3 = 2 minutes
Total number of hours from 6 a.m. today to 10 p.m. on next day = 24 + 12 + 4 = 40 hours
Difference in minutes between the two clocks in 40 hours = 2 × 40 = 80 minutes
Incorrect
Answer: A
Explanation
Difference in minutes between the two clocks in one hour = 5 – 3 = 2 minutes
Total number of hours from 6 a.m. today to 10 p.m. on next day = 24 + 12 + 4 = 40 hours
Difference in minutes between the two clocks in 40 hours = 2 × 40 = 80 minutes
-
Question 3 of 5
3. Question
If the time shown by a clock is 4 hours 35 minutes, then what time does it show on the mirror image?
Correct
Answer: D
Explanation
The time shown by the mirror image of the clock = 12 hours – 4 hours 35 minutes = 7 hours 25 minutes
Incorrect
Answer: D
Explanation
The time shown by the mirror image of the clock = 12 hours – 4 hours 35 minutes = 7 hours 25 minutes
-
Question 4 of 5
4. Question
Consider the following statements:
- In a 12-hour clock the hour, the minute, and the second hands of the clock will coincide 11 times from 6 p.m. of present-day to 6 a.m. of next day.
- The minute hand and second hand of a clock cross each other 26 times between 6:15 to 6:41
Which of the above statements is/are correct?
Correct
Answer: C
Explanation
Statement 1: In 12 hours, all 3 hands will coincide 11 times. They will coincide only once between 11 p.m. and 1 a.m.
But in all other instances, they will meet once per hour. Hence, statement 1 is correct.
Statement 2: The minute hand and second hand of a clock cross each other 1 time every minute after 6:15. Thus, they will cross each other 26 times. Hence, statement 2 is correct.
Incorrect
Answer: C
Explanation
Statement 1: In 12 hours, all 3 hands will coincide 11 times. They will coincide only once between 11 p.m. and 1 a.m.
But in all other instances, they will meet once per hour. Hence, statement 1 is correct.
Statement 2: The minute hand and second hand of a clock cross each other 1 time every minute after 6:15. Thus, they will cross each other 26 times. Hence, statement 2 is correct.
-
Question 5 of 5
5. Question
At what angle are the hands of a clock inclined at 45 minutes past 7?
Correct
Answer: D
Explanation
Angle traced by hour hand in 1 hour = 360°/12 = 30°
Angle traced by hour hand in7 hours 45 minutes i.e. (31/4) hours = 30° × (31/4) = 232.5°
Angle traced by minute hand in 1 minute = 360°/60 = 6°
Angle traced by minute hand in 45 minutes = 6°×45 = 270°
Therefore, the required difference in angles = 270° – 232.5° = 37.5°
Incorrect
Answer: D
Explanation
Angle traced by hour hand in 1 hour = 360°/12 = 30°
Angle traced by hour hand in7 hours 45 minutes i.e. (31/4) hours = 30° × (31/4) = 232.5°
Angle traced by minute hand in 1 minute = 360°/60 = 6°
Angle traced by minute hand in 45 minutes = 6°×45 = 270°
Therefore, the required difference in angles = 270° – 232.5° = 37.5°
