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Question 1 of 5
1. Question
Anand went to Delhi on 5th Wednesday of April and returns to home on 5th Tuesday of June. He has to go back to Delhi to attend a meeting on International Youth Day. On which Day of the week International Youth Day falls?
Correct
Answer: B
Explanation:
June is a 30-day month.
In a 30-day month, all the seven days of week occur 4 times.
(7 × 4 = 28) and two days of the week occur 5 times.
These two days will be the first two or the last two days of the month.
It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June.
That means either 29 June is Tuesday or 30 November is Tuesday.
Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August
(1 + 31 + 12) = 44 => (7 × 6) + 2
Then 12th August is on Thursday. This is not given in the options.
Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August
(31 + 12) = 43 => (7 × 6) + 1
Thus, 12th August is on Wednesday.
Incorrect
Answer: B
Explanation:
June is a 30-day month.
In a 30-day month, all the seven days of week occur 4 times.
(7 × 4 = 28) and two days of the week occur 5 times.
These two days will be the first two or the last two days of the month.
It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June.
That means either 29 June is Tuesday or 30 November is Tuesday.
Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August
(1 + 31 + 12) = 44 => (7 × 6) + 2
Then 12th August is on Thursday. This is not given in the options.
Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August
(31 + 12) = 43 => (7 × 6) + 1
Thus, 12th August is on Wednesday.
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Question 2 of 5
2. Question
How many times does the 29th day of the month occur in 400 consecutive years?
Correct
Answer: C
Solution:
In 400 consecutive years there are 97 leap years.
Hence, in 400 consecutive years February has the 29th day 97 times and
the remaining eleven months have the 29th day 400 x 11 or 4400 times.
Thus the 29th day of the month occurs = 4400+97 = 4497 times
Incorrect
Answer: C
Solution:
In 400 consecutive years there are 97 leap years.
Hence, in 400 consecutive years February has the 29th day 97 times and
the remaining eleven months have the 29th day 400 x 11 or 4400 times.
Thus the 29th day of the month occurs = 4400+97 = 4497 times
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Question 3 of 5
3. Question
In the year 2015 the Republic day, i.e., 26th January fell on Monday. In which of the following year will it again fall on Monday?
Correct
Answer: D
Explanation:
In a non- leap year, the number of odd days = 1
And in a leap year the number of odd days = 2
26th January will fall on a Monday again when the sum of the number of odd days becomes a multiple of 7, i.e., 7, 14, 21……
2015 is a non-leap year, while 2016 is a leap year. Again 2017, 2018 and 2019 are non-leap years.
Thus, the sum of odd days till the end of 2019 = 1 + 2 + 1+ 1 + 1 = 6.
Now, 2020 is a leap year. Thus, the sum of odd days till the end of 2020 = 6 + 2 = 8 (or 1).
If we keep proceeding in the same manner, we will see that:
The number of odd days till the end of 2025 = 8 + 1 + 1 + 1 + 2 + 1 = 14, i.e., a multiple of 7.
Thus, the calendar of the year 2015 repeats itself in the year 2026, after 11 years.
Incorrect
Answer: D
Explanation:
In a non- leap year, the number of odd days = 1
And in a leap year the number of odd days = 2
26th January will fall on a Monday again when the sum of the number of odd days becomes a multiple of 7, i.e., 7, 14, 21……
2015 is a non-leap year, while 2016 is a leap year. Again 2017, 2018 and 2019 are non-leap years.
Thus, the sum of odd days till the end of 2019 = 1 + 2 + 1+ 1 + 1 = 6.
Now, 2020 is a leap year. Thus, the sum of odd days till the end of 2020 = 6 + 2 = 8 (or 1).
If we keep proceeding in the same manner, we will see that:
The number of odd days till the end of 2025 = 8 + 1 + 1 + 1 + 2 + 1 = 14, i.e., a multiple of 7.
Thus, the calendar of the year 2015 repeats itself in the year 2026, after 11 years.
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Question 4 of 5
4. Question
Which two months in a year have the same calendar?
Correct
Answer: D
Solution:
If the period between the two months is divisible by 7, then that two months will have the same calendar
(a) Oct Nov 31+30=61 (not divisible by 7)
(b). Apr May Jun Jul Aug Sep Oct 30+31+30+31+31+30+ 31214 (not divisible by 7)
(c) Jun July + Aug+Sep=30+31+31+30122 (not divisible by 7)
(d). Apr May June 30+31+3091 (divisible by 7) Hence, April and July months will have the same calendar
Incorrect
Answer: D
Solution:
If the period between the two months is divisible by 7, then that two months will have the same calendar
(a) Oct Nov 31+30=61 (not divisible by 7)
(b). Apr May Jun Jul Aug Sep Oct 30+31+30+31+31+30+ 31214 (not divisible by 7)
(c) Jun July + Aug+Sep=30+31+31+30122 (not divisible by 7)
(d). Apr May June 30+31+3091 (divisible by 7) Hence, April and July months will have the same calendar
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Question 5 of 5
5. Question
Jogindhar was born on 13 April 2001 and Rohit was born 3 days after Jogindhar. Republic Day of that year fell on Sunday. On which day was Rohit born?
Correct
Answer: B
Explanation:
Jogindhar was born on 13 April 2001.
Number of days between 26th January and 13 April = 77 days = 11 weeks
Hence Jogindhar was also born on Sunday.
We know that, Rohit was born 3 days after Jogindhar.
Hence, Rohit was born on = Sunday + 3 = Wednesday
Incorrect
Answer: B
Explanation:
Jogindhar was born on 13 April 2001.
Number of days between 26th January and 13 April = 77 days = 11 weeks
Hence Jogindhar was also born on Sunday.
We know that, Rohit was born 3 days after Jogindhar.
Hence, Rohit was born on = Sunday + 3 = Wednesday
