Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
If the fourth day of a month is Tuesday, then which one of the following will be the fifth day from 19th of that month?
Correct
Solution: Option (c)
Explanation:
Fifth day from 19th will be 24th.
Tuesdays of the month will be: 4 11 18 25
Hence, 24th of the month will be a Monday.
Incorrect
Solution: Option (c)
Explanation:
Fifth day from 19th will be 24th.
Tuesdays of the month will be: 4 11 18 25
Hence, 24th of the month will be a Monday.
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Question 2 of 5
2. Question
What will be the day of the week on 15 August 2021 ?
Correct
Solution: Option (a)
Explanation:
15th August, 2021 = (2020 years + Period 1.1.2021 to 15.8.2021)
Odd days in 1600 years = 0
Odd days in 400 years = 0
20 years = (5 leap years + 15 ordinary years) = (5 x 2 + 15 x 1) = 25 = 4 odd days
Jan. Feb. March April May June July Aug
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) = 3 odd days
Total number of odd days = (0 + 0 + 7 + 3) = 7 = 0 odd days
Given day is Sunday
Incorrect
Solution: Option (a)
Explanation:
15th August, 2021 = (2020 years + Period 1.1.2021 to 15.8.2021)
Odd days in 1600 years = 0
Odd days in 400 years = 0
20 years = (5 leap years + 15 ordinary years) = (5 x 2 + 15 x 1) = 25 = 4 odd days
Jan. Feb. March April May June July Aug
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) = 3 odd days
Total number of odd days = (0 + 0 + 7 + 3) = 7 = 0 odd days
Given day is Sunday
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Question 3 of 5
3. Question
If the fourth day of a month is Wednesday, then which day will come on the third day after the 19th day of the same month?
Correct
Solution: Option (c)
Explanation:
The fourth day of the month is Wednesday
so, the first day of the month = Sunday
The third day after the 19th day of the month = the 22nd day of the month
1st day of the month = 8th day of the month = 15th day of the month = 22nd day of the month = Sunday.
Incorrect
Solution: Option (c)
Explanation:
The fourth day of the month is Wednesday
so, the first day of the month = Sunday
The third day after the 19th day of the month = the 22nd day of the month
1st day of the month = 8th day of the month = 15th day of the month = 22nd day of the month = Sunday.
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Question 4 of 5
4. Question
On what dates of April, 2001 did Wednesday fall?
Correct
Solution: Option (d)
Explanation:
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan Feb March April (31+28+31+1) = 91 days = 0 odd days.
Total number of odd days = (0+0+0)=0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th
Incorrect
Solution: Option (d)
Explanation:
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan Feb March April (31+28+31+1) = 91 days = 0 odd days.
Total number of odd days = (0+0+0)=0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th
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Question 5 of 5
5. Question
The last day of a century will not be –
Correct
Solution: Option (d)
Explanation:
100 years contain 5 odd days. (so, the last day of the 1st century is Friday.)
200 years contain (5 × 2) = 3 odd days. (so, the last day of the 2nd century is Wednesday.)
300 years contain (5 × 3) = 15 = 1 odd day(so, Last day of 3rd century is Monday.)
400 years contain 0 odd days. (Last day of the 4th century is Sunday.)
This cycle is repeated.
Therefore, the last day of a century cannot be Tuesday or Thursday, or Saturday.
Incorrect
Solution: Option (d)
Explanation:
100 years contain 5 odd days. (so, the last day of the 1st century is Friday.)
200 years contain (5 × 2) = 3 odd days. (so, the last day of the 2nd century is Wednesday.)
300 years contain (5 × 3) = 15 = 1 odd day(so, Last day of 3rd century is Monday.)
400 years contain 0 odd days. (Last day of the 4th century is Sunday.)
This cycle is repeated.
Therefore, the last day of a century cannot be Tuesday or Thursday, or Saturday.
