Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
The ratio of speed of boat in skill water and the current speed is 5:1 distance covered by boat in downstream speed and upstream speed is 120km. each find the speed of boat in skill water if total time taken boat in both downstream and upstream speed ids 10 hours.
Correct
Answer: A
Explanation
Let the speed of boat in skill water= 5x
current speed =x
downstream speed of boat =5x+x =6x
upstream speed of boat =5x-x =4x
120/6x+120/4x= 10
20/x+30/x =10
x=5
speed of boat in still water =5*5 =25 km/hrIncorrect
Answer: A
Explanation
Let the speed of boat in skill water= 5x
current speed =x
downstream speed of boat =5x+x =6x
upstream speed of boat =5x-x =4x
120/6x+120/4x= 10
20/x+30/x =10
x=5
speed of boat in still water =5*5 =25 km/hr -
Question 2 of 5
2. Question
A boat takes 20 hours to cover 400 km in upstream and 12 hours to cover 480 km in downstream. Speed of boat in still water is how much percent more than speed of stream ?
Correct
Answer: B
Explanation
upstream speed of boat=400/20=20 km/hr
downstream speed of boat=480/12=40 km/hr
speed of boat in still water=40+20/2=30 km/hr
speed of current=40-20/2=10 km/hr
percentage=30-10/10*100=200%Incorrect
Answer: B
Explanation
upstream speed of boat=400/20=20 km/hr
downstream speed of boat=480/12=40 km/hr
speed of boat in still water=40+20/2=30 km/hr
speed of current=40-20/2=10 km/hr
percentage=30-10/10*100=200% -
Question 3 of 5
3. Question
The speed of boat in still water is 18 km/hr and current speed is 6 km/hr. If time taken by boat to cover certain distance both downstream and upstream is 12 hours. Find the distance.
Correct
Answer: C
Explanation
speed of boat in still water=18
speed of current=6
downstream speed of boat=18+6=24
upstream speed of boat=18-6=12
let distance be D km
D/24+D/12=12
D=96 kmIncorrect
Answer: C
Explanation
speed of boat in still water=18
speed of current=6
downstream speed of boat=18+6=24
upstream speed of boat=18-6=12
let distance be D km
D/24+D/12=12
D=96 km -
Question 4 of 5
4. Question
Two stations P and Q are at a distance of 225 km. Train A starts running from station P and train B starts running from station Q respectively and meet each other after 3 hours. If the speed of train A is 5 km/hr more than the speed of train B, then find speed of train A ?
Correct
Answer: D
Explanation
Let speed of train B = x km/hr
speed of train A = (x + 5) km/hr
total distance = 225 km
225/(x + 5 + x) = 3
225 = 6x + 15
x = 35 km/hrIncorrect
Answer: D
Explanation
Let speed of train B = x km/hr
speed of train A = (x + 5) km/hr
total distance = 225 km
225/(x + 5 + x) = 3
225 = 6x + 15
x = 35 km/hr -
Question 5 of 5
5. Question
180m length of train crosses a platform at speed of 90 km/hr in 12 sec. Another train ar speed of 144 km/hr crosses same platform in 8 seconds. What is length of the other train ?
Correct
Answer: B
Explanation
Speed of train = 90 * 5 / 18 = 25 m/sec
let length of platform = x
x + 180/25 = 12
x = 300 – 180 = 120 m
let length another train = y
speed of other train = 144 * 5/18 = 40 m/sec
y + 120/40 = 8
y = 320 – 120 = 200mIncorrect
Answer: B
Explanation
Speed of train = 90 * 5 / 18 = 25 m/sec
let length of platform = x
x + 180/25 = 12
x = 300 – 180 = 120 m
let length another train = y
speed of other train = 144 * 5/18 = 40 m/sec
y + 120/40 = 8
y = 320 – 120 = 200m