UPSC Static Quiz – Art and Culture : 12 October 2024 We will post 5 questions daily on static topics mentioned in the UPSC civil services preliminary examination syllabus. Each week will focus on a specific topic from the syllabus, such as History of India and Indian National Movement, Indian and World Geography, and more.We are excited to bring you our daily UPSC Static Quiz, designed to help you prepare for the UPSC Civil Services Preliminary Examination. Each day, we will post 5 questions on static topics mentioned in the UPSC syllabus. This week, we are focusing on Indian and World Geography.
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Question 1 of 5
1. Question
Raju has some amount of money and he invested 60% of that amount in simple interest at the rate of 24% per annum for 2 years and he invested the remaining amount in compound interest at the rate of 10% per annum for 2 years. From the given statement in the above question which of the following can be determined.
- Amount invested by Raju?
- If the difference between the simple and compound interest received by Raju is Rs.1530, then find the amount invested in simple interest?
- The amount invested in simple interest is Rs.1500 more than the amounts invested in compound interest, then find the interest received from simple interest?
- Overall interest received by Raju?
Correct
Answer: D
Expanation
Let the total amount invested by Raju = 5x
The amount invested in simple interest=5x*60/100=5x*3/5 = 3x
The amount invested in compound interest =5x3x=2x
Interest received by
Raju=3x*24*2/100+[2x*(1+10/100)2-2x]
From option (1)
The amount invested in simple interest=5x*60/100=5x*3/5=3x
The amount invested in compound interest=5x3x=2x This does not satisfy the given condition.
From option (2)
3x*24*2/100-[2x*(1+10/100)2-2x]=1530
1.44x-[2x*1.21-2x]=1530
1.44x-2.42x+2x=1530
1.02x=1530
x=1500
The amount invested in simple interest=3*1500=Rs.4500 This satisfies the given condition.
From option (3)
The amount invested in simple interest=1500*3x/(3x-2x)=Rs.4500
Interest received in simple interes t= 4500*24*2/100 =Rs.2160 This satisfies the given condition.
From option (4)
Interest received by Raju =3x*24*2/100+[2x*(1+10/100)2-2x] This does not satisfy the given condition.
Incorrect
Answer: D
Expanation
Let the total amount invested by Raju = 5x
The amount invested in simple interest=5x*60/100=5x*3/5 = 3x
The amount invested in compound interest =5x3x=2x
Interest received by
Raju=3x*24*2/100+[2x*(1+10/100)2-2x]
From option (1)
The amount invested in simple interest=5x*60/100=5x*3/5=3x
The amount invested in compound interest=5x3x=2x This does not satisfy the given condition.
From option (2)
3x*24*2/100-[2x*(1+10/100)2-2x]=1530
1.44x-[2x*1.21-2x]=1530
1.44x-2.42x+2x=1530
1.02x=1530
x=1500
The amount invested in simple interest=3*1500=Rs.4500 This satisfies the given condition.
From option (3)
The amount invested in simple interest=1500*3x/(3x-2x)=Rs.4500
Interest received in simple interes t= 4500*24*2/100 =Rs.2160 This satisfies the given condition.
From option (4)
Interest received by Raju =3x*24*2/100+[2x*(1+10/100)2-2x] This does not satisfy the given condition.
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Question 2 of 5
2. Question
Bhavana invested Rs.15000 in compound interest at the rate of x% per annum for 2 years is Rs.4837.5 If Bhavana invested Rs.25000 each in simple and compound interest at the rate of (x+9)% per annum for 2 years, then find the difference between the simple and compound interest received by Bhavana?
Correct
Answer: B
Explanation
15000*(1+x/100)2-15000=4837.5
(1+x/100)2-1=0.3225
1+x/100=1.3225
1+x/100=1.15
x=15
Required difference=[25000*(1+24/100)2-25000] –
25000*(15+9)*2/100=13440-12000=Rs.1440
Incorrect
Answer: B
Explanation
15000*(1+x/100)2-15000=4837.5
(1+x/100)2-1=0.3225
1+x/100=1.3225
1+x/100=1.15
x=15
Required difference=[25000*(1+24/100)2-25000] –
25000*(15+9)*2/100=13440-12000=Rs.1440
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Question 3 of 5
3. Question
A sum of money of Rs.2600 was lent out in two parts in such a way that the simple interest on the first part at 10% per annum for 5 years is the same as the interest of the second part at 9% per annum for 6 years. The part lent out at 10% is
Correct
Answer: C
Explanation
Principle=P=2600
First part = A : 10% x 5 years=50% of first part
Second part (P-A): 9% x 6 years=54% of the
second part
50% of A = 54% (P-A)
50/100 x A = 54/100 x (2600-A)
A/2 = (54 x 26) – (54/100 x A)
A/2 + (54/100 x A) = 1404
(50/100 x A) + (54/100 x A) = 1404
(104/100)A = 1404
104A = 140400
A = 1350
Incorrect
Answer: C
Explanation
Principle=P=2600
First part = A : 10% x 5 years=50% of first part
Second part (P-A): 9% x 6 years=54% of the
second part
50% of A = 54% (P-A)
50/100 x A = 54/100 x (2600-A)
A/2 = (54 x 26) – (54/100 x A)
A/2 + (54/100 x A) = 1404
(50/100 x A) + (54/100 x A) = 1404
(104/100)A = 1404
104A = 140400
A = 1350
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Question 4 of 5
4. Question
A sum of Rs 4,000 amounts to Rs 5,008 in three years at simple interest at the rate of x% per annum. If the interest rate becomes (x + 2.6)%, then the revised maturity amount will be?
Correct
Answer: C
Explanation
Simple interest in 3 years = 5008 – 4000 =Rs.1008
1008 = 4000 × 3 × (R/100)
R = 8.4%
Rate of interest is 8.4% per annum.
New rate of interest = 8.4 + 2.6 = 11% per annum
Maturity amount in 3 years = 4000 × 3 × (11/100) + 4000 = Rs. 5320
Incorrect
Answer: C
Explanation
Simple interest in 3 years = 5008 – 4000 =Rs.1008
1008 = 4000 × 3 × (R/100)
R = 8.4%
Rate of interest is 8.4% per annum.
New rate of interest = 8.4 + 2.6 = 11% per annum
Maturity amount in 3 years = 4000 × 3 × (11/100) + 4000 = Rs. 5320
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Question 5 of 5
5. Question
If the difference between the compound and simple interest on a sum for 3 years at the rate of 10% per annum is Rs. 77.5 then find the sum invested?
Correct
Answer: B
Explanation
Let Principle = 100% Rate = 10% Time =
3 years
Simple interest = 30% of principle
Compound interest = 33.1% of Principle
Difference = 3.1%
3.1% = Rs 77.5
1% = Rs. 25
100% = Rs. 2500
Incorrect
Answer: B
Explanation
Let Principle = 100% Rate = 10% Time =
3 years
Simple interest = 30% of principle
Compound interest = 33.1% of Principle
Difference = 3.1%
3.1% = Rs 77.5
1% = Rs. 25
100% = Rs. 2500
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