Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
A invested Rs. x in SI at 20% rate of interest for 8 years and B invested Rs.(x + y) in Cl at 25% rate of interest for 2 years. B invested Rs. y in SI at 30% rate of interest for 6 years. The interest obtained by B in Cl and SI is Rs.13500 and Rs.16200. find investment of A.
Correct
Answer: (a) 15000
Explanation:
Let B invested Rs. y in SI
,y*30/100 *6=16200
On solving we get, y=9000
B invested (x +y) in compound interest,
,(x+9000)(1+25/100)2 –(x+9000)=13500
On solving we get x=15000
Now A investment=15000
Incorrect
Answer: (a) 15000
Explanation:
Let B invested Rs. y in SI
,y*30/100 *6=16200
On solving we get, y=9000
B invested (x +y) in compound interest,
,(x+9000)(1+25/100)2 –(x+9000)=13500
On solving we get x=15000
Now A investment=15000
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Question 2 of 5
2. Question
Priya invested (3Z+4200) in a bank earning simple interest at 10% per annum, after 2.5 years he withdraws all amount from the bank and invested in a scheme earning compound interest of Rs. 3504 at 20% per annum compounded annually , find the value of (Z+200) , if his total time period of investment is 5 years.
Correct
Answer: (b) 400
Explanation:
(3Z+4200)+(3Z+4200)*2.5 *10/100 =5/4*(3Z+4200)
Total time period=5 years
For SI 2.5 years
Compound interest =2.5 years
5/4(3Z+4200) *(6/5*6/5*11/10 -1)= 3504
On solving we get z=200
Z+200=200+200=400
Incorrect
Answer: (b) 400
Explanation:
(3Z+4200)+(3Z+4200)*2.5 *10/100 =5/4*(3Z+4200)
Total time period=5 years
For SI 2.5 years
Compound interest =2.5 years
5/4(3Z+4200) *(6/5*6/5*11/10 -1)= 3504
On solving we get z=200
Z+200=200+200=400
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Question 3 of 5
3. Question
An amount of Rs. 40000 when invested at R% simple interest for 2 years becomes Rs. 48000. What will it become in 3 years if we invested at (R+2)% ?
Correct
Answer: (a) 54400
Explanation:
SI earned=48000-40000=8000
8000=40000*2*R/100
On solving we get, R=10%
Required amount =40000+40000*12*3/100=54400
Incorrect
Answer: (a) 54400
Explanation:
SI earned=48000-40000=8000
8000=40000*2*R/100
On solving we get, R=10%
Required amount =40000+40000*12*3/100=54400
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Question 4 of 5
4. Question
Pavan borrowed certain sum from Pratheesh for 2 years at Sl. Pavan lent this sum to Divya at the same rate for 2 years at Compound Interest. At the end of second year, Pavan received Rs 550 as compound interest but paid Rs 500 as simple interest. Find the rate of interest.
Correct
Answer: (b)
Explanation:
Let the sum and rate of interest be Rs P and R% respectively.
Second year CI=2 years S.I. + interest of one year on first year S.I.
2- year SI=Rs.500
1-year SI=Rs.250
So interest on first year SI=550-500=50
Rate of interest=50/250=*100 =20%
Incorrect
Answer: (b)
Explanation:
Let the sum and rate of interest be Rs P and R% respectively.
Second year CI=2 years S.I. + interest of one year on first year S.I.
2- year SI=Rs.500
1-year SI=Rs.250
So interest on first year SI=550-500=50
Rate of interest=50/250=*100 =20%
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Question 5 of 5
5. Question
An amount doubles in 5 years at a SI . in what time will it become 24 times of itself at same rate?
Correct
Answer: (b) 110
Explanation:
Rate of interest be R% and principal be Rs. P
SI=2P-P=P
P=P*R*5/100
R=20%
To become 24 times=24P-P=23P
23P=P*20*T/100
T=110 years.
Incorrect
Answer: (b) 110
Explanation:
Rate of interest be R% and principal be Rs. P
SI=2P-P=P
P=P*R*5/100
R=20%
To become 24 times=24P-P=23P
23P=P*20*T/100
T=110 years.
