
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
Two articles A and B are sold at 25% profit and 40% profit respectively. If total profit is Rs. 89 and cost price of A is Rs 60 less than B. find cost price of B.
Correct
Answer: (a) 160
Explanation:
Let cost price of A=x
Cost price of B=x+60
X*1/4 +2/5 (x+60) =89
On solving we get x=100
CP of B=x+60=100+60=160
Incorrect
Answer: (a) 160
Explanation:
Let cost price of A=x
Cost price of B=x+60
X*1/4 +2/5 (x+60) =89
On solving we get x=100
CP of B=x+60=100+60=160
-
Question 2 of 5
2. Question
When an article is sold at 40% discount, a loss of 10% occurs but when it sold at 20% discount then there is a profit of Rs. 15 what is the cost price of the article?
Correct
Answer: (a)
Explanation: 75
Let MP =100x
Discount=40%
SP=60x
90/100 * CP=60x
CP=200x/3
When discount=20%
SP=80x
80x-15=CP
200x/3=80x-15
On solving we get
x=9/8
CP=200/3 *9/8=75
Incorrect
Answer: (a)
Explanation: 75
Let MP =100x
Discount=40%
SP=60x
90/100 * CP=60x
CP=200x/3
When discount=20%
SP=80x
80x-15=CP
200x/3=80x-15
On solving we get
x=9/8
CP=200/3 *9/8=75
-
Question 3 of 5
3. Question
A marked price of a ball is Rs. 700. A shopkeeper gives a discount of Rs x and makes a profit of 12.5%. if manufacturing cost of ball is Rs 560, then find the discount percent given by shopkeeper on ball?
Correct
Answer: (a) 10%
Explanation:
MP of ball is =700
MP=700
9/8 * (CP)=SP
9/8 * 560=630=SP
Discount%= MP-SP/MP *100=(700-630)/700%=10%
Incorrect
Answer: (a) 10%
Explanation:
MP of ball is =700
MP=700
9/8 * (CP)=SP
9/8 * 560=630=SP
Discount%= MP-SP/MP *100=(700-630)/700%=10%
-
Question 4 of 5
4. Question
There is some profit when an article is sold for 420. However , when the same article is sold for Rs. 240, there is some loss. If the value of profit is two times the value of loss, then find the selling price when article is sold at profit of 50%.
Correct
Answer: (b) 450
Explanation:
Let
420-CP=2(CP-240)
On solving we get
CP=300
SP=300*150/100=450
Incorrect
Answer: (b) 450
Explanation:
Let
420-CP=2(CP-240)
On solving we get
CP=300
SP=300*150/100=450
-
Question 5 of 5
5. Question
Marked price is 25% more than the selling price of the product and the profit earned on selling is also 25%. if the difference between profit and the difference between cost price and marked price is Rs 400, then find the cost price of the article.
Correct
Answer: (b) 1280
Explanation:
Let the SP be Rs=100x
MP=125x
CP=100x/1.25 = Rs 80x
ATQ
45x-20x=400
X=160
CP=1280
Incorrect
Answer: (b) 1280
Explanation:
Let the SP be Rs=100x
MP=125x
CP=100x/1.25 = Rs 80x
ATQ
45x-20x=400
X=160
CP=1280








