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Question 1 of 5
1. Question
A vessel A mixture , petrol and kerosene oil are in the ratio of 7:5 and in vessel B it is in the ratio of 8:5. P liter of mixture from vessel A and Q liter of mixture from vessel B are taken out and poured into vessel C. if vessel C contains total 300 liter mixture with 40% kerosene oil, then find the value of Q/P ?
Correct
Answer: (a) 13/12
Explanation:
For vessel A-
Petrol taken out=7P/12 liters
Kerosene oil taken out=5P/12 liters
For vessel B-
Petrol taken out=8Q/13 liters
Kerosene oil taken out=5Q/13 liters
In vessel C-
Kerosene oil
5P/12 +5Q/13=300*2/5
On solving we get
13P+12Q=3744 —àequation(1)
Petrol in vessel C
7P/12+8Q/13=300*3/5
91P+96Q=28080—àequation(2)
From 1 and 2 we get Q=156, P=144
Q/P=156/144
Q/P=13/12
Incorrect
Answer: (a) 13/12
Explanation:
For vessel A-
Petrol taken out=7P/12 liters
Kerosene oil taken out=5P/12 liters
For vessel B-
Petrol taken out=8Q/13 liters
Kerosene oil taken out=5Q/13 liters
In vessel C-
Kerosene oil
5P/12 +5Q/13=300*2/5
On solving we get
13P+12Q=3744 —àequation(1)
Petrol in vessel C
7P/12+8Q/13=300*3/5
91P+96Q=28080—àequation(2)
From 1 and 2 we get Q=156, P=144
Q/P=156/144
Q/P=13/12
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Question 2 of 5
2. Question
From container P containing 216 liters of mixture of milk and water , water is 12.5% of milk in a container. 72 liters of the mixture is taken out and poured into container Q in which ratio of milk to water is 3:1. If difference between total milk and total water in container Q is 120 liters, then find difference between the quantity of initial mixture in a container Q and final mixture in P?
Correct
Answer: (a) 16 liters
Explanation:
Let initially milk and water in container Q is ‘3a’ liters and ‘a’ respectively
ATQ,
3a+8/9*72-a-1/9*72 =120
On solving e get a=32liters
Initial quantity in container Q=32*(3+1)=128 liters
Required difference=(216-72)-128=16liters
Incorrect
Answer: (a) 16 liters
Explanation:
Let initially milk and water in container Q is ‘3a’ liters and ‘a’ respectively
ATQ,
3a+8/9*72-a-1/9*72 =120
On solving e get a=32liters
Initial quantity in container Q=32*(3+1)=128 liters
Required difference=(216-72)-128=16liters
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Question 3 of 5
3. Question
A container contain 96L mixture of milk and water out of which 35% of water. 20L of mixture is taken out and 10L milk and 16L water are added in remaining mixture. Find the difference between quantity of milk and water in final mixture after replacement.
Correct
Answer: (b) 16.8L
Explanation:
Milk remained after 20lit mixture is taken out
=(96-20)*65/100=49.4L
Water remained after 20lit mixture is taken out
=(96-20)*35/100=26.6L
Required difference=(49.4+10)-(26.6+16)=16.8liter
Incorrect
Answer: (b) 16.8L
Explanation:
Milk remained after 20lit mixture is taken out
=(96-20)*65/100=49.4L
Water remained after 20lit mixture is taken out
=(96-20)*35/100=26.6L
Required difference=(49.4+10)-(26.6+16)=16.8liter
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Question 4 of 5
4. Question
A container contains mixture of milk and water in the ratio 5:3 respectively. If 16liter milk is added in it then ratio of milk to water becomes 11:5. Find difference between initial quantity of milk and that of water.
Correct
Answer: (a) 10L
Explanation:
Let the initial quantity of milk and water be 5x and 3x liter respectively.
ATQ,
5x+8/3x =11/5
25x+40=33x
X=5
5x-3x=2x=2*5=10L
Incorrect
Answer: (a) 10L
Explanation:
Let the initial quantity of milk and water be 5x and 3x liter respectively.
ATQ,
5x+8/3x =11/5
25x+40=33x
X=5
5x-3x=2x=2*5=10L
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Question 5 of 5
5. Question
A container contains a mixture of two liquid P and Q in the ratio 5:3 . if 8 liter of the mixture is taken out and replaced with liquid Q, then the new ratio of liquid P to Q becomes 1:1. Find the initial quantity of mixture in the container.
Correct
Answer: (b) 40L
Explanation:
Let
P:Q
5x : 3x
(5x-5/8 *8)/(3x-3/8 *8 +8)=1/1
5x-5=3x+5
X=10/2=5
5x+3x=8x=8*5=40L
Incorrect
Answer: (b) 40L
Explanation:
Let
P:Q
5x : 3x
(5x-5/8 *8)/(3x-3/8 *8 +8)=1/1
5x-5=3x+5
X=10/2=5
5x+3x=8x=8*5=40L