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Question 1 of 5
1. Question
Vessel-A contains 160 liters of mixture of petrol and kerosene oil in the ratio 3:1 and vessel-B contains mixture of diesel, petrol and kerosene oil in the ratio 1:3:5. Mixture of both vessels are mixed in another vessel-C and quantity of petrol in vessel-C is 20 liters more than the quantity of kerosene oil in vessel-C, then find the capacity of vessel B.
Correct
Answer: (a) 135L
Explanation:
Vessel-A contains 160L mixture of petrol and kerosene
Petrol : kerosene
3:1
120L : 40L
Vessel-B contains
Diesel : petrol : kerosene
1y : 3y : 5y
ATQ,
(120+1y)-(40+5y)=20
80-4y=20
60=4y
15=y
Required capacity=y+3y+5y=9y=9*15=135liters.
Incorrect
Answer: (a) 135L
Explanation:
Vessel-A contains 160L mixture of petrol and kerosene
Petrol : kerosene
3:1
120L : 40L
Vessel-B contains
Diesel : petrol : kerosene
1y : 3y : 5y
ATQ,
(120+1y)-(40+5y)=20
80-4y=20
60=4y
15=y
Required capacity=y+3y+5y=9y=9*15=135liters.
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Question 2 of 5
2. Question
There are three vessels P,Q and R. vessel P and Q filled with mixture of milk and water in the ratio of 5:4 and 5:3 respectively.25% of mixture from vessel P taken out and mixed in vessel R, which contains 90L pure milk. If in resulting mixture milk is 250% more than water in vessel R and initial quantity of mixture in vessel Q is 40L less than that of mixture in vessel P, then find the quantity of milk in vessel Q.
Correct
Answer: (b)
Explanation:
P : Q : R
Milk :water : milk: water : milk=90L
5 : 4 5 : 3
Let total mixture in vessel P =9x liters
And total mixture in vessel Q= 8y liters
ATQ,
(9x*25/100 *5/9 +90)/(9x*25/100*4/9) =7/2
On solving we get x=40
Initial mixture in vessel P =9x=9*40=360 liters
Mixture in vessel Q=360-40=320
Quantity of milk in vessel Q=320*5/8=200L
Incorrect
Answer: (b)
Explanation:
P : Q : R
Milk :water : milk: water : milk=90L
5 : 4 5 : 3
Let total mixture in vessel P =9x liters
And total mixture in vessel Q= 8y liters
ATQ,
(9x*25/100 *5/9 +90)/(9x*25/100*4/9) =7/2
On solving we get x=40
Initial mixture in vessel P =9x=9*40=360 liters
Mixture in vessel Q=360-40=320
Quantity of milk in vessel Q=320*5/8=200L
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Question 3 of 5
3. Question
Bottle ‘A’ contains 200ml juice and bottle ‘B’ contains 220ml of water . 4xml of juice taken out from ‘A’ and mixed in ‘B’ and then 3x ml mixture from ‘B’ taken out and poured into a vacant bottle ‘C’. if the ratio of water to juice in glass C is 11:4 then find remaining Quantity of juice in bottle ‘B’ ?
Correct
Answer: (d) 64ml
Explanation:
Given,
Juice taken out from bottle ‘A’ =4x ml
Total mixture in bottle ‘B’ = (220+4x) ml
Ratio of water/ juice in bottle B 220/4x=55/x
Now the mixture taken out from bottle B and poured in glass ‘C’ =3x ml.
In bottle C= water/juice=11/4
( 3x*55/55+x ) / (3x*x/55x+x) =11/4
55/x=11/4
X=20ml.
4x-3x*x/55+x
80-60*20/75=80-16=64ml
Incorrect
Answer: (d) 64ml
Explanation:
Given,
Juice taken out from bottle ‘A’ =4x ml
Total mixture in bottle ‘B’ = (220+4x) ml
Ratio of water/ juice in bottle B 220/4x=55/x
Now the mixture taken out from bottle B and poured in glass ‘C’ =3x ml.
In bottle C= water/juice=11/4
( 3x*55/55+x ) / (3x*x/55x+x) =11/4
55/x=11/4
X=20ml.
4x-3x*x/55+x
80-60*20/75=80-16=64ml
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Question 4 of 5
4. Question
In a mixture of milk and water, the proportion of milk by weight is 60% if from the 160 gm mixture , 40gm of mixture is taken out and 12gm of pure water is added to the mixture, then find the ratio of milk and water in the new mixture.
Correct
Answer: (a) 6:5
Explanation:
Mixture(160 gm )
Milk: water
60%:40%
3:2
96gm :64gm
-12gm -16gm
We get
72gm : 60gm
On solving we get required ratio
6:5
Incorrect
Answer: (a) 6:5
Explanation:
Mixture(160 gm )
Milk: water
60%:40%
3:2
96gm :64gm
-12gm -16gm
We get
72gm : 60gm
On solving we get required ratio
6:5
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Question 5 of 5
5. Question
Two vessels P and Q contain water and milk mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 69(3/13) % water is