
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
The average of 7 consecutive integers starting with P is Q. What is the average of 4 consecutive integers starting with (P+2)?
Correct
Answer: (a)
Explanation:
Let 7 consecutive integers be,
P, P+1, P+2, P+3, P+4, P+5, P+6
Average of these 7 consecutive integers =Q
Sum=7Q
7P+21=7Q
7(P+3)=7Q
P+3=Q
P=Q-3 —————-(equation1)
Now, the average of 4 consecutive numbers starting with (P+2)
(P+2+P+3+P+4+P+5)/4 =4P+14/4
(4P+14)/4 = (4(Q-3)+14)/4=(4Q-12+14)/4 =(4Q+2)/4=(2Q+1)/2
Incorrect
Answer: (a)
Explanation:
Let 7 consecutive integers be,
P, P+1, P+2, P+3, P+4, P+5, P+6
Average of these 7 consecutive integers =Q
Sum=7Q
7P+21=7Q
7(P+3)=7Q
P+3=Q
P=Q-3 —————-(equation1)
Now, the average of 4 consecutive numbers starting with (P+2)
(P+2+P+3+P+4+P+5)/4 =4P+14/4
(4P+14)/4 = (4(Q-3)+14)/4=(4Q-12+14)/4 =(4Q+2)/4=(2Q+1)/2
-
Question 2 of 5
2. Question
The average temperature at Bengaluru for Monday, Tuesday, and Wednesday was 500 c while for Tuesday, Wednesday and Thursday it was 520 c. if the temperature on Thursday was 540c, what was the temperature on Monday in Fahrenheit?
Correct
Answer: (a) 118.4
Explanation:
Monday +Tuesday + Wednesday =150
Tuesday +Wednesday +Thursday=156
Thursday=54
Then solving above
Wednesday + Tuesday=102
Monday=48
F=c*9/5 +32
F=48*9/5+32=118.4
Incorrect
Answer: (a) 118.4
Explanation:
Monday +Tuesday + Wednesday =150
Tuesday +Wednesday +Thursday=156
Thursday=54
Then solving above
Wednesday + Tuesday=102
Monday=48
F=c*9/5 +32
F=48*9/5+32=118.4
-
Question 3 of 5
3. Question
In a school the average age of 200 students was 46kg, later on it was discovered that, the weight of a student 32kg was mistakenly taken as 23kg it was also found that the another student weight 56kg was mistakenly taken as 65kg it was also found that the number of students was 180 not 200, then what is the correct average weight of total students?
Correct
Answer: (b)
Explanation:
Total number of students=200
Average=46
Sum =46*200=9200
32——-à23 we need to add 9
56——-à65 we need to subtract 9
9200-9+9 =9200
9200/180 = 51.1kg
Incorrect
Answer: (b)
Explanation:
Total number of students=200
Average=46
Sum =46*200=9200
32——-à23 we need to add 9
56——-à65 we need to subtract 9
9200-9+9 =9200
9200/180 = 51.1kg
-
Question 4 of 5
4. Question
A batsman has a certain average in 59 innings. If his average increased by 4 runs after scoring 281 in the last innings. What is his average after these 60 innings.
Correct
Answer: (b)
Explanation:
Let average at 59th inning=x
,x=runs/59
Runs=59*x
Then,
,x+4=(59x+281)/60
,60x+240=59x+281
,x=41
,x+4=45
Incorrect
Answer: (b)
Explanation:
Let average at 59th inning=x
,x=runs/59
Runs=59*x
Then,
,x+4=(59x+281)/60
,60x+240=59x+281
,x=41
,x+4=45
-
Question 5 of 5
5. Question
The average of collection of 40 measurements was calculated to be 112cm, but later it was found that a mistake had occurred in one of the measurements which was recorded as 128cm but should have been 122cm, the correct average must be?
Correct
Answer: (a)
Explanation:
Given average of 40 measurements=112
Sum=112*40 =4480cm
Correct average=(4480+122-128)/40
=4464/40
=111.85
Incorrect
Answer: (a)
Explanation:
Given average of 40 measurements=112
Sum=112*40 =4480cm
Correct average=(4480+122-128)/40
=4464/40
=111.85








