Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
The least number of five digits which is exactly divisible by 12, 15 and 18 is
Correct
Solution:
Least number of 5 digits is 10000.
L.C.M. of 12, 15 and 18 is 180.
On dividing 10000 by 180, the remainder is 100.
Required number = 10000 + (180 – 100) = 10080.
Incorrect
Solution:
Least number of 5 digits is 10000.
L.C.M. of 12, 15 and 18 is 180.
On dividing 10000 by 180, the remainder is 100.
Required number = 10000 + (180 – 100) = 10080.
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Question 2 of 5
2. Question
The number between 4000 and 5000 which is divisible by 12, 18, 21 and 32 is
Correct
Solution:
L.C.M. of 12, 18, 21 and 32
= 2 × 2 x 3 x 3 x 7 x 8= 2016.So, the required number is a multiple of 2016 and lies between 4000 and 5000. Hence, required number = 4032.
Incorrect
Solution:
L.C.M. of 12, 18, 21 and 32
= 2 × 2 x 3 x 3 x 7 x 8= 2016.So, the required number is a multiple of 2016 and lies between 4000 and 5000. Hence, required number = 4032.
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Question 3 of 5
3. Question
A milkman has 3 jars containing 57 litres, 129 litres and 177 litres of pure milk respectively. A measuring can, after a different number of exact measurements of milk in each jar, leaves the same amount of milk unmeasured in each jar. What is the volume of the largest such can?
Correct
Solution:
Required volume = [H.C.F. of (129 – 57), (177 – 129) and (177 – 57)] litres
= (H.C.F. of 72, 48 and 120) litres = 24 litres.
Incorrect
Solution:
Required volume = [H.C.F. of (129 – 57), (177 – 129) and (177 – 57)] litres
= (H.C.F. of 72, 48 and 120) litres = 24 litres.
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Question 4 of 5
4. Question
Three electronic devices make a beep sound after every 30, 60, and 105 minutes respectively. It is given that all the devices beeped together at 3:00PM. When will they beep together again?
Correct
Solution:
LCM of 30, 60, 105 = 420 minutes
420/60 =7 hours
Therefore They will beep again at 3 + 7 = 10 PM
Incorrect
Solution:
LCM of 30, 60, 105 = 420 minutes
420/60 =7 hours
Therefore They will beep again at 3 + 7 = 10 PM
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Question 5 of 5
5. Question
Three girls start jogging from the same point around a circular track and each one completes one round in 24 seconds, 36 seconds and 48 seconds respectively. After how much time will they meet at one point
Correct
Solution:
L.C.M. of 24, 36, 48 = 144.
So, the three girls will meet at one point in 144 seconds i.e., 2 min 24 sec.
Incorrect
Solution:
L.C.M. of 24, 36, 48 = 144.
So, the three girls will meet at one point in 144 seconds i.e., 2 min 24 sec.
