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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
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Question 1 of 5
1. Question
By selling a pen at a profit of 60% a man got Rs 38 more than one third of its cost price. What is the cost price of pen?
Correct
Solution: D) 30
Let the cost price = x
Therefore selling price with 60% profit = 160/100 x =8/5 x
It is given that selling price is 38 more than one-third of cost price
è (8/5) * x = x/3 + 38
- (8/5 – 1/3) * x = 38
- ((24 – 5)/15) * x = 38
- x = 38 * 15/19
- x = 30
Therefore, cost price = Rs 30
Incorrect
Solution: D) 30
Let the cost price = x
Therefore selling price with 60% profit = 160/100 x =8/5 x
It is given that selling price is 38 more than one-third of cost price
è (8/5) * x = x/3 + 38
- (8/5 – 1/3) * x = 38
- ((24 – 5)/15) * x = 38
- x = 38 * 15/19
- x = 30
Therefore, cost price = Rs 30
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Question 2 of 5
2. Question
The number obtained by interchanging the digits of a two digit number is less than the original number by 18. If sum of the digits is 6, what was the original two digit number?
Correct
Solution: C) 42
Let the original number be 10x + y.
Number obtained by interchanging the digits = 10y + x
∴ (10x + y) – (10y + x) = 18
Or, x – y = 2 … (i)
Also, x + y = 6 … (ii)
From equations (i) and (ii),
x = 4 and y = 2.
∴ Original number = (10 x 4) + 2 = 42
Incorrect
Solution: C) 42
Let the original number be 10x + y.
Number obtained by interchanging the digits = 10y + x
∴ (10x + y) – (10y + x) = 18
Or, x – y = 2 … (i)
Also, x + y = 6 … (ii)
From equations (i) and (ii),
x = 4 and y = 2.
∴ Original number = (10 x 4) + 2 = 42
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Question 3 of 5
3. Question
Present average of age of A and B is 6x – 15 years. Present average age of A, B and C is 4x + 6 years. If present age of B is 20% less than the present age of C and 20% more than the present age of A, then find the present age of A.
Correct
» Explain it
Correct Option: A) 32 years
Sum of the present age of A and B = 2 × (6x – 15) = 12x – 30 years
Sum of the present age of A, B and C = 3 × (4x + 6) = 12x + 18 years
So, the present age of C = 12x + 18 – 12x + 30 = 48 years
Present age of B = 48 × 0.80 = 38.4 years
Present age of A = 38.4/1.2 = 32 years
Hence, option A is correct.
Incorrect
» Explain it
Correct Option: A) 32 years
Sum of the present age of A and B = 2 × (6x – 15) = 12x – 30 years
Sum of the present age of A, B and C = 3 × (4x + 6) = 12x + 18 years
So, the present age of C = 12x + 18 – 12x + 30 = 48 years
Present age of B = 48 × 0.80 = 38.4 years
Present age of A = 38.4/1.2 = 32 years
Hence, option A is correct.
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Question 4 of 5
4. Question
In a factory there are three types of Machines A, B and C which produces 25%, 35% and 40% of the total products respectively. A, B and C produces 2%, 4% and 5% defective products, respectively. What is the percentage of non-defective products?
Correct
Correct Answer : C) 96.1%
Answer Justification :
Justification:
Defective products of machine A = 2% of 25% = 0.5%
Defective products of machine B = 4% of 35% = 1.4%
Defective products of machine A = 5% of 40% = 2%
Percentage of total defective products = 0.5% + 1.4% + 2% = 3.9%
Percentage of total non-defective products = 100% – 3.9% = 96.1%
Incorrect
Correct Answer : C) 96.1%
Answer Justification :
Justification:
Defective products of machine A = 2% of 25% = 0.5%
Defective products of machine B = 4% of 35% = 1.4%
Defective products of machine A = 5% of 40% = 2%
Percentage of total defective products = 0.5% + 1.4% + 2% = 3.9%
Percentage of total non-defective products = 100% – 3.9% = 96.1%
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Question 5 of 5
5. Question
The cost of a car is 400% greater than the cost of a bike. If there is an increase in the cost of the car by 15% and that of bike by 20%. Then the total increase in the cost of 5 cars and 10 bikes is:
Correct
Correct Answer : B) 16.42%
Answer Justification :
Justification:
Let the cost of a bike be Rs.100
Then the cost of a car is Rs.500
New cost of a bike = 100 + 20% of 100 = 100 + 20 = Rs.120
New cost of a car = 500 + 15% of 500 = 500 + 75 = Rs.575
Total new cost of 5 cars and 10 bikes = 10 × 120 + 5 ×575 = 1200 + 2875 = Rs.4075
Total old cost of 5 cars and 10 bikes = 10 × 100 + 5 × 500 = 1000 + 2500 = Rs.3500
Then the total increase in the cost of 5 cars and 10 bikes = 4075 – 3500 = Rs.575
Increase % = (575/3500) × 100 = (115/7) % = 16.42%
Incorrect
Correct Answer : B) 16.42%
Answer Justification :
Justification:
Let the cost of a bike be Rs.100
Then the cost of a car is Rs.500
New cost of a bike = 100 + 20% of 100 = 100 + 20 = Rs.120
New cost of a car = 500 + 15% of 500 = 500 + 75 = Rs.575
Total new cost of 5 cars and 10 bikes = 10 × 120 + 5 ×575 = 1200 + 2875 = Rs.4075
Total old cost of 5 cars and 10 bikes = 10 × 100 + 5 × 500 = 1000 + 2500 = Rs.3500
Then the total increase in the cost of 5 cars and 10 bikes = 4075 – 3500 = Rs.575
Increase % = (575/3500) × 100 = (115/7) % = 16.42%
