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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
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Question 1 of 5
1. Question
A certain amount of money has been divided between two persons P and Q in the ratio 3 : 5. But it was divided in the ratio of 2 : 3 and thereby Q loses Rs. 10. What was the amount?
Correct
Sol. (d)
Let the amount be Rs. x.
In first condition, Q’s part = 5x/(5+3) = 5x/8
In second condition, Q’s part = 3x/(2+3) = 3x/5
By given condition, 5x/8 – 3x/5 = 10
⇒x/40 = 10
⇒x = Rs. 400
Incorrect
Sol. (d)
Let the amount be Rs. x.
In first condition, Q’s part = 5x/(5+3) = 5x/8
In second condition, Q’s part = 3x/(2+3) = 3x/5
By given condition, 5x/8 – 3x/5 = 10
⇒x/40 = 10
⇒x = Rs. 400
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Question 2 of 5
2. Question
If x varies as the mth power of y, y varies as nth power of z and x varies as the pth power of z, then which one of the following is correct?
Correct
Sol. (c)
x ∝ym ……(i)
y ∝zn ……(ii)
x ∝zp ……(iii)
On putting the values of x and y from Eqs. (ii) and (iii) in Eq. (i),
we get zp ∝ (zn)m
⇒z p ∝zmn
⇒p = mn
Incorrect
Sol. (c)
x ∝ym ……(i)
y ∝zn ……(ii)
x ∝zp ……(iii)
On putting the values of x and y from Eqs. (ii) and (iii) in Eq. (i),
we get zp ∝ (zn)m
⇒z p ∝zmn
⇒p = mn
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Question 3 of 5
3. Question
The ratio between the ages of A and B is 2 : 5. After 8 yr, their ages will be in the ratio 1 : 2. What is the difference between their present ages?
Correct
Sol. (c)
Let the ages of A and B be 2x and 5x yr respectively.
By given condition, (2x + 8)/(5x + 8)=1/2
= 4x + 16 = 5x + 8 x => 8
Hence, Difference between their present ages = 5x – 2x = 3x
= 3 × 8 = 24 yr.
Incorrect
Sol. (c)
Let the ages of A and B be 2x and 5x yr respectively.
By given condition, (2x + 8)/(5x + 8)=1/2
= 4x + 16 = 5x + 8 x => 8
Hence, Difference between their present ages = 5x – 2x = 3x
= 3 × 8 = 24 yr.
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Question 4 of 5
4. Question
A mixture contains milk and water in the ratio 5 : 1. On adding 5 L of water, the ratio of milk and water becomes 5 : 2. What is the quantity of milk in the original mixture?
Correct
Sol. (b)
Let quantities of milk and water be 5x and x L respectively.
By given condition,
5x/(x + 5) = 5/2
⇒10x = 5x + 25
⇒5x = 25
⇒X = 5
Hence, the quantity of milk in the original mixture = 5 × 5 = 25 L.
Incorrect
Sol. (b)
Let quantities of milk and water be 5x and x L respectively.
By given condition,
5x/(x + 5) = 5/2
⇒10x = 5x + 25
⇒5x = 25
⇒X = 5
Hence, the quantity of milk in the original mixture = 5 × 5 = 25 L.
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Question 5 of 5
5. Question
The wages of labourers in a factory has increased in the ratio 22 : 25 and their number decreased in the ratio 3 : 2. What was the original wage bill of the factory, if the present bill is Rs. 5000?
Correct
Sol.(d)
Let initial salary = Rs. 22x
and final salary = Rs. 25x
Let initial number of employees = 3y
and final number of employees = 2y
Hence, Present bill = Final salary × Final number of employees
⇒5000 = 25x × 2y
⇒5000/50 = xy
⇒xy = 100.
Hence, Original bill = Initial salary × Initial number of employees
⇒22x × 3y = 66xy
⇒66 × 100 = Rs. 6600
Incorrect
Sol.(d)
Let initial salary = Rs. 22x
and final salary = Rs. 25x
Let initial number of employees = 3y
and final number of employees = 2y
Hence, Present bill = Final salary × Final number of employees
⇒5000 = 25x × 2y
⇒5000/50 = xy
⇒xy = 100.
Hence, Original bill = Initial salary × Initial number of employees
⇒22x × 3y = 66xy
⇒66 × 100 = Rs. 6600
