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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
If p% of Rs. x is equal to t times q% of Rs. y, then what is the ratio of x to y?
Correct
Sol. (c)
By given condition, p% of x = t (q % of y)
⇒xp/100 = (yq × t)/100
⇒x/y = qt/p
Hence, x : y = =qt : p
Incorrect
Sol. (c)
By given condition, p% of x = t (q % of y)
⇒xp/100 = (yq × t)/100
⇒x/y = qt/p
Hence, x : y = =qt : p
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Question 2 of 5
2. Question
A bag contains Rs. 112 in the form of Rs. 1, 50 paise and 10 paise coins in the ratio 3 : 8 : 10. What is the number of 50 paise coins?
Correct
Sol. (a)
Convert ratios in paise-
100 paise:50 paise:10paise
Divide by 10
We ll get-10 : 5 : 1 and new as per given ratio we get new ratio as
10 × 3 : 5 × 8 : 1 × 8 = 30 : 40 : 10 = 3 : 4 : 1
⇒3x + 4x + x = 112
⇒x = 112/8 = 14
Hence, Number of 50 paise coins = 14 x 8 = 112.
Incorrect
Sol. (a)
Convert ratios in paise-
100 paise:50 paise:10paise
Divide by 10
We ll get-10 : 5 : 1 and new as per given ratio we get new ratio as
10 × 3 : 5 × 8 : 1 × 8 = 30 : 40 : 10 = 3 : 4 : 1
⇒3x + 4x + x = 112
⇒x = 112/8 = 14
Hence, Number of 50 paise coins = 14 x 8 = 112.
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Question 3 of 5
3. Question
The speeds of three cars are in the ratio 4 : 3 : 2. What is the ratio between the time taken by the cars to cover the same distance?
Correct
Sol. (b)
Speed ∞ 1/Time
Hence, Required ratio = 1/4 : 1/3 : 1/2 = 3 : 4 : 6
Incorrect
Sol. (b)
Speed ∞ 1/Time
Hence, Required ratio = 1/4 : 1/3 : 1/2 = 3 : 4 : 6
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Question 4 of 5
4. Question
What is the ratio between times taken by a train 240 m long to cross an electric pole and a bridge of 80 m length?
Correct
Sol. (b)
Since, the speed of train is constant, then
D1/T1 = D2/T2
240/T1 = (240 + 80)/T2
T1/T2 = 240/320
⇒T1 : T2 = 3 : 4
Incorrect
Sol. (b)
Since, the speed of train is constant, then
D1/T1 = D2/T2
240/T1 = (240 + 80)/T2
T1/T2 = 240/320
⇒T1 : T2 = 3 : 4
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Question 5 of 5
5. Question
‘X’ is twice as old as ‘Y’ 3 yr ago, when ‘X’ was as old as ‘Y’ today. If the difference between their ages at present is 3 yr, how old is ‘X’ at present?
Correct
Sol. (c)
Let present age of X = x yr
and present age of Y = (x – 3) yr
3 yr ago, age of X = (x – 3) yr
and age of Y = (x – 6) yr
According to the question, x – 3 = 2(x – 6)
⇒x – 3 = 2x – 12
⇒12 – 3 = 2x – x
⇒x = 9yr
Incorrect
Sol. (c)
Let present age of X = x yr
and present age of Y = (x – 3) yr
3 yr ago, age of X = (x – 3) yr
and age of Y = (x – 6) yr
According to the question, x – 3 = 2(x – 6)
⇒x – 3 = 2x – 12
⇒12 – 3 = 2x – x
⇒x = 9yr
