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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
Study the following information carefully and answer the questions given below:
A, B, C, D, E, F, G and H are sitting around a circle facing the center.D is fourth to the right of H and second to the left of B.
F is fourth to the right of B.
C is fourth to the right of E, who is not an immediate neighbor of B or D.
A is not an immediate neighbor of D.
In which of the following combinations is the third person sitting in between the first and the second persons?
Correct
Solution: b) GCD
Justification:
Inference from statement 1: Clockwise: H _ B _ D
Inference from statement 2: Clockwise: F _ H _ B _ D
Inference from statement 3: Clockwise: F E H _ B C D _
Inference from statement 3: Clockwise: F E H A B C D G
Final arrangement:
Among the given options, D is sitting between G and C.
Hence, option (b) is correct.
Incorrect
Solution: b) GCD
Justification:
Inference from statement 1: Clockwise: H _ B _ D
Inference from statement 2: Clockwise: F _ H _ B _ D
Inference from statement 3: Clockwise: F E H _ B C D _
Inference from statement 3: Clockwise: F E H A B C D G
Final arrangement:
Among the given options, D is sitting between G and C.
Hence, option (b) is correct.
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Question 2 of 5
2. Question
Study the following information carefully and answer the questions given below:
A, B, C, D, E, F, G and H are sitting around a circle facing the center.D is fourth to the right of H and second to the left of B.
F is fourth to the right of B.
C is fourth to the right of E, who is not an immediate neighbor of B or D.
A is not an immediate neighbor of D.
What is B’s position with respect to G?
Correct
Solution: a) Third to the right
Justification:
Refer the explanation for the previous question.
B sits third to the right of G or fifth to the left of G.
Hence, option (a) is correct.
Incorrect
Solution: a) Third to the right
Justification:
Refer the explanation for the previous question.
B sits third to the right of G or fifth to the left of G.
Hence, option (a) is correct.
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Question 3 of 5
3. Question
A team of 11 is to be selected from 7 batsmen and 6 bowlers available. The team must have at least 5 bowlers. In how many ways can it be done?
Correct
Solution: D) 63
As the team must have at least 5 bowlers, two cases are possible:
Case I: Team has 5 bowlers out of 6 bowlers and 6 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 and 6 batsmen out of 7 = 6C5 * 7C6 = 6 * 7 = 42.
OR
Case II: Team has 6 bowlers out of 6 bowlers and 5 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 and 5 batsmen out of 7 = 6C6 * 7C5 = 1 * 21 = 21.
Hence, total ways possible = 42 + 21 = 63.Hence, option (d) is correct.
Incorrect
Solution: D) 63
As the team must have at least 5 bowlers, two cases are possible:
Case I: Team has 5 bowlers out of 6 bowlers and 6 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 and 6 batsmen out of 7 = 6C5 * 7C6 = 6 * 7 = 42.
OR
Case II: Team has 6 bowlers out of 6 bowlers and 5 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 and 5 batsmen out of 7 = 6C6 * 7C5 = 1 * 21 = 21.
Hence, total ways possible = 42 + 21 = 63.Hence, option (d) is correct.
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Question 4 of 5
4. Question
The monthly income of Ramesh and Suresh are in the ratio 4:3 and the ratio of their expenditure is 3:2. If each of them saves Rs. 6000 then by what percentage is Ramesh income more than that of Suresh income?
Correct
Solution: B) 33.33%
Let the income of Ramesh and Suresh be 4x and 3x respectively
And the Expenses of Ramesh and Suresh are 3y and 2y respectively.
As it is given that each of them saves Rs. 6000 monthly.Therefore,
Savings of Ramesh = 4x – 3y = 6000 ……(Eq 1)
Saving of Suresh = 3x -2y = 6000 …….(Eq 2)
Subtracting (2) from (1) gives
x –y = 0, i.e. x = y …………….(Eq 3)
Using (Eq 3) in (Eq 1) we get, x = 6000.
So, Ramesh’s Income = 4x = 24000
Suresh’s income = 3x =18000
Net difference = 24000 – 18000 = 6000
Required percentage = 6000/18000 × 100% = 33.33%
Hence, option (b) is the correctIncorrect
Solution: B) 33.33%
Let the income of Ramesh and Suresh be 4x and 3x respectively
And the Expenses of Ramesh and Suresh are 3y and 2y respectively.
As it is given that each of them saves Rs. 6000 monthly.Therefore,
Savings of Ramesh = 4x – 3y = 6000 ……(Eq 1)
Saving of Suresh = 3x -2y = 6000 …….(Eq 2)
Subtracting (2) from (1) gives
x –y = 0, i.e. x = y …………….(Eq 3)
Using (Eq 3) in (Eq 1) we get, x = 6000.
So, Ramesh’s Income = 4x = 24000
Suresh’s income = 3x =18000
Net difference = 24000 – 18000 = 6000
Required percentage = 6000/18000 × 100% = 33.33%
Hence, option (b) is the correct -
Question 5 of 5
5. Question
To five liter of 20% sulfuric acid, seven and half liter of 80% sulfuric acid is added. What is the strength of the acid in the mixture now?
Correct
Solution: A) 56%
Percentage strength of the acid in the mixture = Quantity (volume) of the acid in the mixture/Total volume × 100
= [(5*20/100) + (7.5*80/100)/(5+7.5)] *100 = (5*20+7.5*80) /(5+7.5) = 56%.Hence, option (a) is correct.
Incorrect
Solution: A) 56%
Percentage strength of the acid in the mixture = Quantity (volume) of the acid in the mixture/Total volume × 100
= [(5*20/100) + (7.5*80/100)/(5+7.5)] *100 = (5*20+7.5*80) /(5+7.5) = 56%.Hence, option (a) is correct.
