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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 10
1. Question
Abhi and Dairya started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Dairya’s share is :
Correct
Answer: A) 8400
Explanation:
Ratio of their shares = 22500 : 35000 = 9 : 14.
Dairya’s share = Rs. (13800 * 14/23) = Rs. 8400.
Incorrect
Answer: A) 8400
Explanation:
Ratio of their shares = 22500 : 35000 = 9 : 14.
Dairya’s share = Rs. (13800 * 14/23) = Rs. 8400.
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Question 2 of 10
2. Question
How many of the following numbers are divisible by 132?
264,396,462,792,968,2178,5184,6336
Correct
Answer: A) 4
Explanation:
132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.
264 => 4,3,11(/)
396 => 4,3,11(/)
462 => 11,3
792 => 4,3,11(/)
968 => 11,4
2178 => 11,3
5184 => 3,4
6336 => 4,3,11(/)
Required number of numbers=4.
Incorrect
Answer: A) 4
Explanation:
132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.
264 => 4,3,11(/)
396 => 4,3,11(/)
462 => 11,3
792 => 4,3,11(/)
968 => 11,4
2178 => 11,3
5184 => 3,4
6336 => 4,3,11(/)
Required number of numbers=4.
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Question 3 of 10
3. Question
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:
Correct
Answer: Option C)
Explanation:
Other number =(11 x 7700)/ 275= 308.
Incorrect
Answer: Option C)
Explanation:
Other number =(11 x 7700)/ 275= 308.
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Question 4 of 10
4. Question
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Correct
Correct Answer: A) 4years
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.Incorrect
Correct Answer: A) 4years
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years. -
Question 5 of 10
5. Question
A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B’s share?
Correct
Correct Answer: C) 2000rs
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x – 3x = 1000
x = 1000.
B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.Incorrect
Correct Answer: C) 2000rs
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x – 3x = 1000
x = 1000.
B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000. -
Question 6 of 10
6. Question
The average weight of 12 sailors in a boat decreases by 2kg when one of the sailors who weighs 80kgs is replaced by a new sailor. What is the weight of the new sailor?
Correct
Correct Answer : D) None of the above
Answer Justification :
Due to the replacement of a sailor weighing 80kgs, the change in the average weight is -2kgs.
Since the number of sailors remain the same i.e. 12,
The total change in the weight = 12 × -2 = -24kgs.
This change has happened due to the replacement.
Hence, the weight of new sailor = 80 – 24 = 56kgs.
Incorrect
Correct Answer : D) None of the above
Answer Justification :
Due to the replacement of a sailor weighing 80kgs, the change in the average weight is -2kgs.
Since the number of sailors remain the same i.e. 12,
The total change in the weight = 12 × -2 = -24kgs.
This change has happened due to the replacement.
Hence, the weight of new sailor = 80 – 24 = 56kgs.
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Question 7 of 10
7. Question
The difference between Compound Interest and Simple Interest on a certain sum of money at 10 % per annum for 3 years is Rs. 930. Find the principal if it is known that the interest is compounded annually.
Correct
Correct Answer: B) 30000
The Simple after three years for 10% is 30%.
The Compound Interest after three years for 10% is 1.1*1.1*1.1=1.331
Cumulative rate of compound interest = 33.1%
Difference between SI and CI= 3.1%
Principal = 930*100/3.1= 30000
Incorrect
Correct Answer: B) 30000
The Simple after three years for 10% is 30%.
The Compound Interest after three years for 10% is 1.1*1.1*1.1=1.331
Cumulative rate of compound interest = 33.1%
Difference between SI and CI= 3.1%
Principal = 930*100/3.1= 30000
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Question 8 of 10
8. Question
Kalmesh, Pragathi and Tabhu started a business by investing Rs X, Rs (X+400) and Rs (X-200). If after the end of year, total share of profit of Kalmesh and Tabhu is Rs 8100 out of a total profit of Rs 13,500, find the profit share of Pragathi.
Correct
Correct Answer: B) 5400rs
Kalmesh : Pragathi : Tabhu
X : (X+400) : (X-200)
So (X+X-200)/(X + X+400 + X-200) * 13500 = 8100
Solve, X = 1600
So ratio of profit share is
1600 : 2000 : 1400 = 8 : 10 : 7
So profit share of Pragathi = 10/25 * 13500 = Rs 5400.
Incorrect
Correct Answer: B) 5400rs
Kalmesh : Pragathi : Tabhu
X : (X+400) : (X-200)
So (X+X-200)/(X + X+400 + X-200) * 13500 = 8100
Solve, X = 1600
So ratio of profit share is
1600 : 2000 : 1400 = 8 : 10 : 7
So profit share of Pragathi = 10/25 * 13500 = Rs 5400.
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Question 9 of 10
9. Question
A bell rings every 18 minutes. A second bell rings every 24 minutes. A third bell rings every 32 minutes. If all the three bells ring at the same time at 8 o’clock in the morning, at what other time will they all ring together?
Correct
Correct Answer: B) 12:48 hrs
Take the LCM of 18, 24 and 32 which comes out to be 288 minutes i.e. 4 hours and 48 minutes. Add to 8’o clock. The time is 12:48 hours.
Incorrect
Correct Answer: B) 12:48 hrs
Take the LCM of 18, 24 and 32 which comes out to be 288 minutes i.e. 4 hours and 48 minutes. Add to 8’o clock. The time is 12:48 hours.
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Question 10 of 10
10. Question
There are four routes to travel from city A to city B and six routes from city B to city C. How many routes are possible to travel from the city A to city C?
Correct
Correct Answer: A) 24
For every one route, you will have six routes to take. So, total number of routes is 6 X 4 = 24.
Incorrect
Correct Answer: A) 24
For every one route, you will have six routes to take. So, total number of routes is 6 X 4 = 24.
