Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
The average price of 3 cars is 5 lakhs, where the average price of two costliest cars is double the price of the cheapest car. What is the price of the costliest car?
Correct
Solution: d) Can’t be determined
Explanation:
Let the prices of the 3 cars A, B and C be ‘a’, ‘b’ and ‘c’ respectively.
Let A be the cheapest.
Therefore, a+b+c = 3 × 5 lakhs = 15 lakhs …………(1)
Also,
(b+c)/2 = 2a
b+c = 4a …………..(2)
Substituting (2) in (1),
a + 4a = 15 lakhs
5a = 15 lakhs
a = 3 lakhs.
Since b + c = 12 lakhs, we can’t find which car is the costliest.
NOTE:
Since there are 3 variables and only 2 equations can be constructed, we can’t get the complete solution. There have to be 3 equations for 3 variables for complete solution.
Incorrect
Solution: d) Can’t be determined
Explanation:
Let the prices of the 3 cars A, B and C be ‘a’, ‘b’ and ‘c’ respectively.
Let A be the cheapest.
Therefore, a+b+c = 3 × 5 lakhs = 15 lakhs …………(1)
Also,
(b+c)/2 = 2a
b+c = 4a …………..(2)
Substituting (2) in (1),
a + 4a = 15 lakhs
5a = 15 lakhs
a = 3 lakhs.
Since b + c = 12 lakhs, we can’t find which car is the costliest.
NOTE:
Since there are 3 variables and only 2 equations can be constructed, we can’t get the complete solution. There have to be 3 equations for 3 variables for complete solution.
-
Question 2 of 5
2. Question
In a parking lot, there are 2-wheelers, 3-wheelers and 4-wheelers parked. On counting, there found 300 wheels and 95 vehicles. If the number of 3-wheelers is 10 less than the number of 4-wheelers, what is the difference between number of 2-wheelers and 3-wheelers?
Correct
Solution: a) 5
Explanation:
Let the number 2, 3, 4-wheelers be ‘x’, ‘y’ and ‘z’ respectively.
Therefore, number of vehicles = x + y + z = 95. ……….. (1)
Also, number of wheels = 2x + 3y + 4z = 300. ……….. (2)
Since the number of 3-wheelers is 10 less than number of 4-wheelers,
z – y = 10 ……….. (3)
From (2) – 2 × (1)
2x + 3y + 4z – 2x – 2y – 2z = 300 – 2 × 95
y + 2z = 110 ………… (4)
Adding (3) and (4),
z – y + y + 2z = 10 + 110
3z = 120
z = 40.
Substituting for z in (3),
y = 30.
Incorrect
Solution: a) 5
Explanation:
Let the number 2, 3, 4-wheelers be ‘x’, ‘y’ and ‘z’ respectively.
Therefore, number of vehicles = x + y + z = 95. ……….. (1)
Also, number of wheels = 2x + 3y + 4z = 300. ……….. (2)
Since the number of 3-wheelers is 10 less than number of 4-wheelers,
z – y = 10 ……….. (3)
From (2) – 2 × (1)
2x + 3y + 4z – 2x – 2y – 2z = 300 – 2 × 95
y + 2z = 110 ………… (4)
Adding (3) and (4),
z – y + y + 2z = 10 + 110
3z = 120
z = 40.
Substituting for z in (3),
y = 30.
-
Question 3 of 5
3. Question
The number of mangoes in three baskets are in the ratio of 3:4:5. In which ratio the number of mangoes in first two baskets must be increased so that the new ratio becomes 5:4:3?
Correct
Solution: b
Explanation:
The number of mangoes in the third basket are unchanged.
The number of mangoes is multiple of both 3 and 5. So, we have to take LCM of 3 and 5 i.e. 15.
If we assume the number of mangoes in the third basket as 15, the old ratio will be
9:12:15.
New ratio will be 25:20:15.
Thus, the mangoes to be increased in first and second basket respectively will be 16 and 8.
So, the required ratio is 16:8 i.e. 2:1.
Incorrect
Solution: b
Explanation:
The number of mangoes in the third basket are unchanged.
The number of mangoes is multiple of both 3 and 5. So, we have to take LCM of 3 and 5 i.e. 15.
If we assume the number of mangoes in the third basket as 15, the old ratio will be
9:12:15.
New ratio will be 25:20:15.
Thus, the mangoes to be increased in first and second basket respectively will be 16 and 8.
So, the required ratio is 16:8 i.e. 2:1.
-
Question 4 of 5
4. Question
In a library, 20% of the books are in in French. 50% of the remaining books are in Mandarin. The remaining 900 books are in various other languages. What is the number of books which are in Mandarin?
Correct
Solution: C) 900
Explanation:
The number of books is 100%.
Therefore, the number of French books = 20% of total books
The remaining books = 80% of total books
The number of books in Mandarin language is 50% of 80% i.e. 40%.
The number of books in various other languages = 100% – 20% – 40% = 40%
So, percentage of books in Mandarin is equal to the percentage of books in other languages i.e. 900.
Incorrect
Solution: C) 900
Explanation:
The number of books is 100%.
Therefore, the number of French books = 20% of total books
The remaining books = 80% of total books
The number of books in Mandarin language is 50% of 80% i.e. 40%.
The number of books in various other languages = 100% – 20% – 40% = 40%
So, percentage of books in Mandarin is equal to the percentage of books in other languages i.e. 900.
-
Question 5 of 5
5. Question
Due to reduction of 25% in price of oranges a customer can purchase 4 oranges more for Rs.24. What is the original price of an orange?
Correct
Solution: D) 2rs
Explanation:
Shortcut:
If the price of oranges fall by (1/x), then (1/(x-1)) more oranges can be purchased with the same amount.
The price of oranges has fallen by 25% or ¼.
Therefore, the number oranges that can be purchased more is (1/(4-1)) i.e. 1/3.
Also, 1/3 of the oranges is equal to 4 oranges.
Thus, the original number of oranges is 12.
The original price of an orange = Rs.24/12 = Rs.2
Incorrect
Solution: D) 2rs
Explanation:
Shortcut:
If the price of oranges fall by (1/x), then (1/(x-1)) more oranges can be purchased with the same amount.
The price of oranges has fallen by 25% or ¼.
Therefore, the number oranges that can be purchased more is (1/(4-1)) i.e. 1/3.
Also, 1/3 of the oranges is equal to 4 oranges.
Thus, the original number of oranges is 12.
The original price of an orange = Rs.24/12 = Rs.2








