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Question 1 of 10
1. Question
Directions for the following items: (1-5)
Read the following passage and answer the items that follow. Your answers to these items should be based on the passage only.
Mahatma Gandhi believed that industrialization was no answer to the problems that plague the mass of India’s poor and that villagers should be taught to be self-sufficient in food, weave their own cloth from cotton and eschew the glittering prizes that the 20th century so temptingly offers. Such an idyllic and rural paradise did not appear to those who inherited the reins of political power.
Mahatma Gandhi’s views opposed industrialization of villages because
Correct
Correct Answer: D
Explanation:
According to the passage, Gandhiji always believed in self-sufficiency and opposed
Industrialization. Passage compared the village life to rural-paradise and extremely
happier if it is not industrialized. So industrialization destroys the beauty of villagers
and undermines the advantages of self-sufficiency.
Hence the correct answer is D.
Incorrect
Correct Answer: D
Explanation:
According to the passage, Gandhiji always believed in self-sufficiency and opposed
Industrialization. Passage compared the village life to rural-paradise and extremely
happier if it is not industrialized. So industrialization destroys the beauty of villagers
and undermines the advantages of self-sufficiency.
Hence the correct answer is D.
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Question 2 of 10
2. Question
A can do a bit of work in 25 days which B can complete in 20 days. Both together labor for 5 days and afterward A leaves off. How long will B take to complete the remaining work?
Correct
Solution:- D
(A+B)’s 5 days work = 5(1/25+1/20) = (5*9/100) = 9/20
Remaining work = (1-9/20) = 11/20
1/20 work is finished by B in 1 day
11/20 work is finished by B in (1*20*11/20) = 11 days
Hence, option (d) is correct.
Incorrect
Solution:- D
(A+B)’s 5 days work = 5(1/25+1/20) = (5*9/100) = 9/20
Remaining work = (1-9/20) = 11/20
1/20 work is finished by B in 1 day
11/20 work is finished by B in (1*20*11/20) = 11 days
Hence, option (d) is correct.
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Question 3 of 10
3. Question
In a race of 600m, A can beat B by 60m and in a race of 500m, B can beat C by 50m. By how many meters will A beat C in a race of 400m?
Correct
Solution- D
If A runs 600m, B runs 540 m.
If A runs 400m, B runs (540/600*400) m = 360m
When B runs 500m, C runs 450m.
When B runs 360 m, C runs (450/500*360) m = 324 m.
∴ A beats C by (400-324) m =76 m.
Hence, option (d) is correct.
Incorrect
Solution- D
If A runs 600m, B runs 540 m.
If A runs 400m, B runs (540/600*400) m = 360m
When B runs 500m, C runs 450m.
When B runs 360 m, C runs (450/500*360) m = 324 m.
∴ A beats C by (400-324) m =76 m.
Hence, option (d) is correct.
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Question 4 of 10
4. Question
A boat travels 32 km upstream and 60 km downstream in 9 hr. Also it travels 40 km upstream and 84 km downstream in 12 hrs. Find the speed of the boat in still water and rate of the current (in Km/hr).
Correct
Solution: A
Let, upstream speed = u km/hr
Downstream speed = d km/hr
32/u + 60/d = 9 (Time = Distance/Speed)
Simlarly,
40/u + 84/d = 12
32x + 60y = 9 …(i) (Assuming 1/u = x and 1/d = y)
40x + 84y = 12 …(ii)
(Equation(ii) * 4) – (Equation (i)*5), we get,
y = 1/12. So, x = 1/8
Hence, downstream speed = 12 km/hr
Upstream speed = 8 km/hr
So,
Speed of the boat in still water = 1/2*(12+8) = 10 km/hr
Speed of the current = 1/2*(12 – 8) = 2 km/hr
Hence, option (a) is correct.
Incorrect
Solution: A
Let, upstream speed = u km/hr
Downstream speed = d km/hr
32/u + 60/d = 9 (Time = Distance/Speed)
Simlarly,
40/u + 84/d = 12
32x + 60y = 9 …(i) (Assuming 1/u = x and 1/d = y)
40x + 84y = 12 …(ii)
(Equation(ii) * 4) – (Equation (i)*5), we get,
y = 1/12. So, x = 1/8
Hence, downstream speed = 12 km/hr
Upstream speed = 8 km/hr
So,
Speed of the boat in still water = 1/2*(12+8) = 10 km/hr
Speed of the current = 1/2*(12 – 8) = 2 km/hr
Hence, option (a) is correct.
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Question 5 of 10
5. Question
If the sum of the ages of father and son is 100years. The ratio of father and son before the period of 5 years is 2:1. Find out the ratio of ages which would be after the period 10 year.
Correct
Solution: D
If the age of father at the present time = x years
His son age at the present time = (100-x) years.
x-5 / (100-x-5) = 2/1 ⇒ (x-5) = 2(95-x) ⇒ 3x = 195 ⇒ x = 65
Ratio of the ages of man and son after 10 years = (65+10)/(35+10)= 75/45 = 5/3 = 5:3
Hence, option (d) is correct.
Incorrect
Solution: D
If the age of father at the present time = x years
His son age at the present time = (100-x) years.
x-5 / (100-x-5) = 2/1 ⇒ (x-5) = 2(95-x) ⇒ 3x = 195 ⇒ x = 65
Ratio of the ages of man and son after 10 years = (65+10)/(35+10)= 75/45 = 5/3 = 5:3
Hence, option (d) is correct.
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Question 6 of 10
6. Question
Directions for the following items: 6- 10
Read the following passage and answer the items that follow. Your answers to these items should be based on the passage only
It is difficult to reconcile the ideas of different schools of thought on the question of education. Some people maintain that pupils of school should concentrate on a narrow range of subjects which will benefit them directly in their subsequent careers. Others contend that they should study a wide range of subjects so that they not only have the specialized knowledge necessary for their chosen careers but also sound general knowledge about the world they will have to work and live in. Supporters of the first theory state that the greatest contributions to civilization are made by those who are experts in their trade or profession. Those on the other side say that, unless they have a broad general education, the experts will be too narrow in their outlook to have sympathy with their fellows or a proper sense of responsibility towards humanity as a whole.
Supporters of the first theory would not agree with?
Correct
Correct Answer: D
Explanation:
First theory talks about a few subjects and specialized knowledge. And they agreed that greatest contributions to civilization are made by those who are experts in their trade or profession and not from the one who believed in second theory.
Hence the correct answer is D.
Incorrect
Correct Answer: D
Explanation:
First theory talks about a few subjects and specialized knowledge. And they agreed that greatest contributions to civilization are made by those who are experts in their trade or profession and not from the one who believed in second theory.
Hence the correct answer is D.
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Question 7 of 10
7. Question
‘School of thought’ can best be explained as
Correct
Correct Answer: B
Explanation
School means a particular stream of thinking. According to the passage there are two schools of thinking who believe in different theories towards teaching students
Hence the correct answer is B
Incorrect
Correct Answer: B
Explanation
School means a particular stream of thinking. According to the passage there are two schools of thinking who believe in different theories towards teaching students
Hence the correct answer is B
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Question 8 of 10
8. Question
A train travelling with a constant speed crosses a 96m long platform in 12 seconds and another 141m long platform in 15 seconds. The length of the train and speed respectively is
Correct
Solution: C
Let the length of the train be x m.
(96+x)/12 =(141+x)/15 ⇒ 15* (96+x) =12*(141+x)
⇒ 3x =(1692-1440)= 252 ⇒x = 84 m
Speed of the train =(96+84)/12 m/sec. = 15m/sec. =(15*18/5)kmph = 54kmph
Incorrect
Solution: C
Let the length of the train be x m.
(96+x)/12 =(141+x)/15 ⇒ 15* (96+x) =12*(141+x)
⇒ 3x =(1692-1440)= 252 ⇒x = 84 m
Speed of the train =(96+84)/12 m/sec. = 15m/sec. =(15*18/5)kmph = 54kmph
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Question 9 of 10
9. Question
Distance between two stations A and B is 390 km. A train begins from A at 10 am and move towards B at 65 kmph. Another train begins from B at 11 am and move towards A at 35 kmph. At what time they meet each other?
Correct
Solution:- A
Assume they meet x hours after 10 am then,
(Distance moved by first train in x hrs.) + (Distance moved by second train in (x-1) hrs) = 390
∴ 65x+ 35(x-1) = 390
=> 100x =425
=> x= 17/4
In this way, they meet 4 hrs 15 min after 10 am at 2.15 pm
Hence, option (a) is correct.
Incorrect
Solution:- A
Assume they meet x hours after 10 am then,
(Distance moved by first train in x hrs.) + (Distance moved by second train in (x-1) hrs) = 390
∴ 65x+ 35(x-1) = 390
=> 100x =425
=> x= 17/4
In this way, they meet 4 hrs 15 min after 10 am at 2.15 pm
Hence, option (a) is correct.
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Question 10 of 10
10. Question
A criminal is spotted by a policeman from a distance of 100 meters. At the point when the policeman begins the chase, the criminal likewise begin s running. In the event that the pace of the criminal be 8km/hr and that of the policeman 10 km/hr, how far the criminal will have keep running before he is caught?
Correct
Solution: C
Relative pace of the policeman = (10-8) km/hr = 2 km/hr
Time taken by policeman to cover 100 m = (100/1000*1/2) hr = 1/20 hr
In 1/20 hr, the criminal covers a separation of (8*1/20) km= (2/5 km) = (2/5*1000) m = 400 m
Hence, option (c) is correct.
Incorrect
Solution: C
Relative pace of the policeman = (10-8) km/hr = 2 km/hr
Time taken by policeman to cover 100 m = (100/1000*1/2) hr = 1/20 hr
In 1/20 hr, the criminal covers a separation of (8*1/20) km= (2/5 km) = (2/5*1000) m = 400 m
Hence, option (c) is correct.
