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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 10
1. Question
Speech is a great blessing but it can also be a great curse, for while it helps us to make our intentions and desires known to our fellows, it can also if we use it carelessly, make our attitude completely misunderstood. A slip of the tongue, the use of unusual words, or of an ambiguous word, and so on, may create an enemy where we had hoped to win a friend. Again, different classes of people use different vocabularies, and the ordinary speech of an educated may strike an uneducated listener as pompous. Unwittingly, we may use a word which bears a different meaning to our listener from what it does to men of our own class. Thus speech is not a gift to use lightly without thought, but one which demands careful handling. Only a fool will express himself alike to all kinds and conditions to men.
The best way to win a friend is to avoid
Correct
Correct Answer: D
Explanation:
As mentioned clearly in the passage, “A slip of the tongue, the use of unusual words, or of an ambiguous word, and so on, may create an enemy where we had hoped to win a friend”. Ambiguity of the speech should be avoided with ambiguous words in the speech.
Hence the correct answer is D.
Incorrect
Correct Answer: D
Explanation:
As mentioned clearly in the passage, “A slip of the tongue, the use of unusual words, or of an ambiguous word, and so on, may create an enemy where we had hoped to win a friend”. Ambiguity of the speech should be avoided with ambiguous words in the speech.
Hence the correct answer is D.
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Question 2 of 10
2. Question
While talking to an uneducated person, we should use
Correct
Correct Answer: B
Explanation:
According to the passage line “Only a fool will express himself alike to all kinds and conditions to men”, we can say that the people should use the vocabulary or the talking style and condition of the people whom they are talking to.
Hence the correct answer is B.
Incorrect
Correct Answer: B
Explanation:
According to the passage line “Only a fool will express himself alike to all kinds and conditions to men”, we can say that the people should use the vocabulary or the talking style and condition of the people whom they are talking to.
Hence the correct answer is B.
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Question 3 of 10
3. Question
A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visiters per day in a month of 30 days begining with a Sunday is?
Correct
Solution: C
Since the month begins with a Sunday, so there will be five Sundays in the month
Therefore Required average = ( 510 x 5 + 240 x 25)/30
= 8550/30 = 285
Hence, option (c) is correct.
Incorrect
Solution: C
Since the month begins with a Sunday, so there will be five Sundays in the month
Therefore Required average = ( 510 x 5 + 240 x 25)/30
= 8550/30 = 285
Hence, option (c) is correct.
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Question 4 of 10
4. Question
By selling 33 meters of cloth, one gains the selling price of 11 meters. Find the gain percent.
Correct
Solution: A
(Selling Price of 33m) – (Cost Price of 33m) = Gain = Selling Price of 11m
∴ SP of 22m = CP of 33m
Let CP of each meter be Re 1. Then, CP of 22m = Re 22.
Hence SP of 22m = Re 33.
∴ %Gain = 11/22 * 100
= 50%
Hence, option (a) is correct.
Incorrect
Solution: A
(Selling Price of 33m) – (Cost Price of 33m) = Gain = Selling Price of 11m
∴ SP of 22m = CP of 33m
Let CP of each meter be Re 1. Then, CP of 22m = Re 22.
Hence SP of 22m = Re 33.
∴ %Gain = 11/22 * 100
= 50%
Hence, option (a) is correct.
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Question 5 of 10
5. Question
Anil buys a calculator for Rs 600 and sells it to Vikash at 10% profit. Vikash sells it to Chandan for 5 % profit. Chandan after using it for certain time sells it to Dinesh at a loss of 20%. For how much price Chandan sell the calculator to Dinesh.
Correct
Solution:- C
Selling Price for Chandan = 600 * (110/100) * (105/100) * (80/100)
= 600 * 924/1000
= Rs 554.40
Hence, option (c) is correct
Incorrect
Solution:- C
Selling Price for Chandan = 600 * (110/100) * (105/100) * (80/100)
= 600 * 924/1000
= Rs 554.40
Hence, option (c) is correct
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Question 6 of 10
6. Question
The length of a rectangle is thrice its breadth. If its length is decreased by 9 cm and breadth is increased by 9 cm, the area of the rectangle is increased by 81 sq. cm. Find the length of the rectangle.
Correct
Solution: A
Let breadth = X. Then, length = 3X.
Then, (3X – 9) (X + 9) = 3X * X + 81
⇒3X2+27X-9X-81=3X2+81
18X=162
⇒X=9 cm
∴ Length of the rectangle = 9 cm
Hence, option (a) is correct.
Incorrect
Solution: A
Let breadth = X. Then, length = 3X.
Then, (3X – 9) (X + 9) = 3X * X + 81
⇒3X2+27X-9X-81=3X2+81
18X=162
⇒X=9 cm
∴ Length of the rectangle = 9 cm
Hence, option (a) is correct.
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Question 7 of 10
7. Question
Find the length of the longest pole that can be placed in a room 24 m long 16 m broad and 18 m high.
Correct
Solution: A
Length of the longest pole= Diagonal of the cube.
Length of the longest pole=√(242+162+182)=34 m
Hence, option (a) is correct.
Incorrect
Solution: A
Length of the longest pole= Diagonal of the cube.
Length of the longest pole=√(242+162+182)=34 m
Hence, option (a) is correct.
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Question 8 of 10
8. Question
Reema took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of loan period, what was the rate of interest?
Correct
Solution:- C
Let Rate = R% and time also R years. Then,
(1200 x R x R⁄100) = 432
= 12R2 = 432
R2 = 36
R=6
Hence, option (c) is correct.
Incorrect
Solution:- C
Let Rate = R% and time also R years. Then,
(1200 x R x R⁄100) = 432
= 12R2 = 432
R2 = 36
R=6
Hence, option (c) is correct.
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Question 9 of 10
9. Question
Nitin borrowed some money at 6% for the first three years, 9% for the next 5 years and 13% for the period beyond 8 years. If the total interest paid by him at the end of eleven years is Rs 8160, how much money did he borrow?
Correct
Solution:- A
Let the sum be Z. Then,
(Zx6x3⁄100) + (Zx9x5⁄100) + (Zx13x3⁄100) = 8160
= 18Z + 45Z + 39Z = (8160 x 100)
102Z = 816000
Z = 8000
Hence, option (a) is correct.
Incorrect
Solution:- A
Let the sum be Z. Then,
(Zx6x3⁄100) + (Zx9x5⁄100) + (Zx13x3⁄100) = 8160
= 18Z + 45Z + 39Z = (8160 x 100)
102Z = 816000
Z = 8000
Hence, option (a) is correct.
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Question 10 of 10
10. Question
With an amount of Rs. 21000 ‘A’ started a business. After some time , B joined the business by investing amount of Rs. 36000. If profit of the firm divided equally between them then find out how many months after B join the business?
Correct
Solution:- B
We assume that after the period of x month B joined the business.
Capital of A = (21000*12)= Rs. 252000
Capital of B = {36000* (12-x) }= Rs. (432000-36000x)
252000= 432000- 36000x ⇒ 36000x= 180000 ⇒ x= 5
Hence, B joined after 5 months.
Hence, option (b) is correct.
Incorrect
Solution:- B
We assume that after the period of x month B joined the business.
Capital of A = (21000*12)= Rs. 252000
Capital of B = {36000* (12-x) }= Rs. (432000-36000x)
252000= 432000- 36000x ⇒ 36000x= 180000 ⇒ x= 5
Hence, B joined after 5 months.
Hence, option (b) is correct.