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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
The ages of five friends Amit, Bhuvan, Chinmay, Devdas and Eric, with an age difference of 2 years each in given order, add up to 60. What is the
age of Chinmay if Amit is the youngest of among all?Correct
Solution: D
Let age of Amit be x years
As we know that ages of Amit, Bhuvan, Chinmay, Devdas and Eric, with an age difference of 2 years each, add to 60.
Therefore,
Age of Bhuvan = x + 2
Age of Chinmay = x + 4
Age of Devdas = x + 6
Age of Eric = x + 8
It is given that: x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 60
è 5x + 20 = 60è x = 8
Therefore, the age of Chinmay = x + 4 = 8 + 4 = 12 years
Hence, option (d) is the correctIncorrect
Solution: D
Let age of Amit be x years
As we know that ages of Amit, Bhuvan, Chinmay, Devdas and Eric, with an age difference of 2 years each, add to 60.
Therefore,
Age of Bhuvan = x + 2
Age of Chinmay = x + 4
Age of Devdas = x + 6
Age of Eric = x + 8
It is given that: x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 60
è 5x + 20 = 60è x = 8
Therefore, the age of Chinmay = x + 4 = 8 + 4 = 12 years
Hence, option (d) is the correct -
Question 2 of 5
2. Question
Pointing to a woman in a photograph, a man says – “She is the only daughter of the mother-in law of my only son.” How is the woman related
to the man?Correct
Solution: C
It is better to go from reverse side to solve this kind of problem.
Therefore, it can be translated as she is that man’s only son’s mother-in law’s only daughter.
Thus, she is wife of man’s only son or daughter-in law of that man.
Therefore, “Only daughter of the mother-in-law of one’s son” implies one’s daughter-in-law.
Hence, option (c), correct.
Incorrect
Solution: C
It is better to go from reverse side to solve this kind of problem.
Therefore, it can be translated as she is that man’s only son’s mother-in law’s only daughter.
Thus, she is wife of man’s only son or daughter-in law of that man.
Therefore, “Only daughter of the mother-in-law of one’s son” implies one’s daughter-in-law.
Hence, option (c), correct.
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Question 3 of 5
3. Question
If an amount doubles itself in 5 years, then in how many years will it be 8 times of the original amount, if it grows with an interest rate compounded annually?
Correct
Solution: B
Let the initial amount be x.
In 5 years the amount gets doubled, i.e. total amount=2x
In the next 5 years, i.e 10 years amount gets doubled again, i.e. total amount=4x
Similarly, in the next 5 years, i.e 15 years the total amount= 2 × 4x = 8x.Hence, option (b) is correct.
Incorrect
Solution: B
Let the initial amount be x.
In 5 years the amount gets doubled, i.e. total amount=2x
In the next 5 years, i.e 10 years amount gets doubled again, i.e. total amount=4x
Similarly, in the next 5 years, i.e 15 years the total amount= 2 × 4x = 8x.Hence, option (b) is correct.
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Question 4 of 5
4. Question
In an examination if total boys and total girls appear in the ratio
11:13, then which of the following can be the total number of students appearing in the examination?Correct
Solution: C
Let the total number of boys be 11x and total number of girls be 13x.
Therefore, total students will be 24x.
Therefore, total number of students appearing in the examination must be a multiple of 24.
Looking at the options, option (b) and option (d) can be directly eliminated as they are odd numbers.
By looking at remaining options, it can be clearly seen that 240 is completely divisible by 24.
Hence, option (c) is correct.
Incorrect
Solution: C
Let the total number of boys be 11x and total number of girls be 13x.
Therefore, total students will be 24x.
Therefore, total number of students appearing in the examination must be a multiple of 24.
Looking at the options, option (b) and option (d) can be directly eliminated as they are odd numbers.
By looking at remaining options, it can be clearly seen that 240 is completely divisible by 24.
Hence, option (c) is correct.
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Question 5 of 5
5. Question
There are 60 students in a class. Each student gets chocolates that are 20% of the total number of students in the class. If 30% of the total number of chocolates is distributed among one tenth of the students, how many chocolates will each student get?
Correct
Solution: A
It is given that there are 60 students in the class.
Each student gets chocolates that are 20% of the total number of students in the class. So, each student gets (20/100) * 60 chocolates = 12 chocolates.
Therefore, total chocolates will be 12 * 60 = 720.
It is given that, 30% of the total number of chocolates is distributed among one tenth of the students. Therefore, 30% of 720 chocolates are distributed among one tenth of the total students i.e among 6 students.
So, (30/100)*720 = 216 chocolates are distributed among 6 students.
Therefore, each student gets 216/6 = 36 chocolates.
Hence, option (a) is correct.
Incorrect
Solution: A
It is given that there are 60 students in the class.
Each student gets chocolates that are 20% of the total number of students in the class. So, each student gets (20/100) * 60 chocolates = 12 chocolates.
Therefore, total chocolates will be 12 * 60 = 720.
It is given that, 30% of the total number of chocolates is distributed among one tenth of the students. Therefore, 30% of 720 chocolates are distributed among one tenth of the total students i.e among 6 students.
So, (30/100)*720 = 216 chocolates are distributed among 6 students.
Therefore, each student gets 216/6 = 36 chocolates.
Hence, option (a) is correct.
