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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Which of the following is a married couple?
Correct
Solution: B
As the observations made in the previous problem it is clear that married couple are B and F as well as D and E.
Hence, option (b) is correct.
Incorrect
Solution: B
As the observations made in the previous problem it is clear that married couple are B and F as well as D and E.
Hence, option (b) is correct.
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Question 2 of 5
2. Question
Who is the wife of D?
Correct
Solution: A
As the observations made in the previous problem it is clear that married couple are B and F as well as D and E.
Hence, option (a) is correct.
Incorrect
Solution: A
As the observations made in the previous problem it is clear that married couple are B and F as well as D and E.
Hence, option (a) is correct.
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Question 3 of 5
3. Question
Ramesh sold an article for Rs. 6,750 after giving a discount of 10% on the labeled price. He would have earned a profit of 50%, had there been no discount. What was the actual percentage of profit earned?
Correct
Solution: C
Let the marked price of the article be Rs. xDiscount = 10%
Then, the selling price = – 10% of = (9x/10)
Now,= (9x/10)= 6750 Or x = Rs. 7,500
As per the question, if the selling price is Rs. 7,500, then the profit earned by the Ramesh is 50%.
So, the cost price = Rs. 5,000
Therefore, the actual percentage of profit earned by selling the article for Rs. 6,750 = (Profit/CP) × 100 =(1750/5000)× 100 = 35%
Hence, option (c) is the correct.Incorrect
Solution: C
Let the marked price of the article be Rs. xDiscount = 10%
Then, the selling price = – 10% of = (9x/10)
Now,= (9x/10)= 6750 Or x = Rs. 7,500
As per the question, if the selling price is Rs. 7,500, then the profit earned by the Ramesh is 50%.
So, the cost price = Rs. 5,000
Therefore, the actual percentage of profit earned by selling the article for Rs. 6,750 = (Profit/CP) × 100 =(1750/5000)× 100 = 35%
Hence, option (c) is the correct. -
Question 4 of 5
4. Question
What can be the maximum sum of Sundays and Mondays in a leap year?
Correct
Solution: A
A leap year has 366 days, that is exactly 52 full weeks and 2 extra days.
For maximum Sundays and Mondays , year has to be started with Sunday.
So maximum required days = 52 * 2 + 2 = 106.Hence, option (a) is correct.
Incorrect
Solution: A
A leap year has 366 days, that is exactly 52 full weeks and 2 extra days.
For maximum Sundays and Mondays , year has to be started with Sunday.
So maximum required days = 52 * 2 + 2 = 106.Hence, option (a) is correct.
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Question 5 of 5
5. Question
If total 66 handshakes occurred when each student shakes hand with every other student inside a classroom, how many students are there in the classroom?
Correct
Solution: B
It is given that total number of handshakes = 66
Let the number of students be n.
Then, total handshakes = n (n-1)/2
Therefore, n (n-1) = 66 *2
- n^2 – n =132
- n^2 – n – 132 = 0
- By solving quadratic equation we get, n= 12.
Hence, option (b) is correct.
Incorrect
Solution: B
It is given that total number of handshakes = 66
Let the number of students be n.
Then, total handshakes = n (n-1)/2
Therefore, n (n-1) = 66 *2
- n^2 – n =132
- n^2 – n – 132 = 0
- By solving quadratic equation we get, n= 12.
Hence, option (b) is correct.
