Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
Direction for the following 5 (five) items: Consider the given information and answer the five items that follow:
Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different years
What was the respective ratio between the number of candidates who appeared from school C in the year 2006 and the number of candidates who passed in the exam from school D in the year 2009?
Correct
Solution: A
The number of candidates who appeared from school C in the year 2006= 693.
The number of candidates who passed in the exam from school D in the year 2009 = 252.
Therefore, the required ratio = 693/252 = 11/4
Hence, option (a) is correct.
Incorrect
Solution: A
The number of candidates who appeared from school C in the year 2006= 693.
The number of candidates who passed in the exam from school D in the year 2009 = 252.
Therefore, the required ratio = 693/252 = 11/4
Hence, option (a) is correct.
-
Question 2 of 5
2. Question
Direction for the following 5 (five) items: Consider the given information and answer the five items that follow:
Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different yearsNumber of candidates who passed in the exam from school B in the year 2005 was approximately what per cent of number of candidates who appeared from school A in the year 2008?
Correct
Solution: A
Number of candidates who passed from school B in the year 2005 = 435.
Number of candidates who appeared from school A in the year 2008 = 546.
Therefore, the required percent= (435/546) * 100 = 79. 6% or approximately 80%.
Hence, option (a) is correct.
Incorrect
Solution: A
Number of candidates who passed from school B in the year 2005 = 435.
Number of candidates who appeared from school A in the year 2008 = 546.
Therefore, the required percent= (435/546) * 100 = 79. 6% or approximately 80%.
Hence, option (a) is correct.
-
Question 3 of 5
3. Question
Direction for the following 5 (five) items: Consider the given information and answer the five items that follow:
Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different yearsWhat was the approximate percent increase in the number of candidates who passed in the exam from school A in the year 2009 as compared to the previous year?
Correct
Solution: C
Number of candidates who passed from school A in the year 2009 = 435.
Number of candidates who passed from school A in the year 2008 = 346.
Thus, required percent = ((435-346)/346) * 100 = 25. 7
Or approximately 26%.
Hence, option (c) is correct.
Incorrect
Solution: C
Number of candidates who passed from school A in the year 2009 = 435.
Number of candidates who passed from school A in the year 2008 = 346.
Thus, required percent = ((435-346)/346) * 100 = 25. 7
Or approximately 26%.
Hence, option (c) is correct.
-
Question 4 of 5
4. Question
From a pack of 52 cards, 1 card is chosen at random. What is the probability of the card being diamond or queen?
Correct
Solution: C
In 52 cards, there are 13 diamond cards and 4 queens.
1 card is chosen at random:
For 1 diamond card, probability = 13/52
For 1 queen, probability = 4/52
For cards which are both diamond and queen, probability = 1/52
So required probability = 13/52 + 4/52 – 1/52 = 16/52 = 4/13Hence, option (c) is correct.
Incorrect
Solution: C
In 52 cards, there are 13 diamond cards and 4 queens.
1 card is chosen at random:
For 1 diamond card, probability = 13/52
For 1 queen, probability = 4/52
For cards which are both diamond and queen, probability = 1/52
So required probability = 13/52 + 4/52 – 1/52 = 16/52 = 4/13Hence, option (c) is correct.
-
Question 5 of 5
5. Question
If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 32 minutes, then the slower pipe alone will be able to fill the tank in?
Correct
Solution: A
Let, the time is taken by pipe A = x
Then, time is taken by pipe B = x/3By substituting these values, we get:
1/x + 3/x = 1/32
x = 128 minutesHence, option (a) is correct.
Incorrect
Solution: A
Let, the time is taken by pipe A = x
Then, time is taken by pipe B = x/3By substituting these values, we get:
1/x + 3/x = 1/32
x = 128 minutesHence, option (a) is correct.
