[Mission 2023] Insta–DART (Daily Aptitude and Reasoning Test) 21 March 2023

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

Direction for the following 5 (five) items: Consider the given information and answer the five items that follow:

Study the table carefully to answer the questions that follow: Candidates who appeared and passed in the test from four schools in six different years

What was the respective ratio between the number of candidates who appeared from school C in the year 2006 and the number of candidates who passed in the exam from school D in the year 2009?

Correct

Solution: A

The number of candidates who appeared from school C in the year 2006= 693.

The number of candidates who passed in the exam from school D in the year 2009 = 252.

Therefore, the required ratio = 693/252 = 11/4

Hence, option (a) is correct.

Incorrect

Solution: A

The number of candidates who appeared from school C in the year 2006= 693.

The number of candidates who passed in the exam from school D in the year 2009 = 252.

Therefore, the required ratio = 693/252 = 11/4

Hence, option (a) is correct.

Question 2 of 5

2. Question

Direction for the following 5 (five) items: Consider the given information and answer the five items that follow:

Study the table carefully to answer the questions that follow: Candidates who appeared and passed in the test from four schools in six different years

Number of candidates who passed in the exam from school B in the year 2005 was approximately what per cent of number of candidates who appeared from school A in the year 2008?

Correct

Solution: A

Number of candidates who passed from school B in the year 2005 = 435.

Number of candidates who appeared from school A in the year 2008 = 546.

Therefore, the required percent= (435/546) * 100 = 79. 6% or approximately 80%.

Hence, option (a) is correct.

Incorrect

Solution: A

Number of candidates who passed from school B in the year 2005 = 435.

Number of candidates who appeared from school A in the year 2008 = 546.

Therefore, the required percent= (435/546) * 100 = 79. 6% or approximately 80%.

Hence, option (a) is correct.

Question 3 of 5

3. Question

Direction for the following 5 (five) items: Consider the given information and answer the five items that follow:

Study the table carefully to answer the questions that follow: Candidates who appeared and passed in the test from four schools in six different years

What was the approximate percent increase in the number of candidates who passed in the exam from school A in the year 2009 as compared to the previous year?

Correct

Solution: C

Number of candidates who passed from school A in the year 2009 = 435.

Number of candidates who passed from school A in the year 2008 = 346.

From a pack of 52 cards, 1 card is chosen at random. What is the probability of the card being diamond or queen?

Correct

Solution: C

In 52 cards, there are 13 diamond cards and 4 queens. 1 card is chosen at random: For 1 diamond card, probability = 13/52 For 1 queen, probability = 4/52 For cards which are both diamond and queen, probability = 1/52 So required probability = 13/52 + 4/52 – 1/52 = 16/52 = 4/13

Hence, option (c) is correct.

Incorrect

Solution: C

In 52 cards, there are 13 diamond cards and 4 queens. 1 card is chosen at random: For 1 diamond card, probability = 13/52 For 1 queen, probability = 4/52 For cards which are both diamond and queen, probability = 1/52 So required probability = 13/52 + 4/52 – 1/52 = 16/52 = 4/13

Hence, option (c) is correct.

Question 5 of 5

5. Question

If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 32 minutes, then the slower pipe alone will be able to fill the tank in?

Correct

Solution: A

Let, the time is taken by pipe A = x Then, time is taken by pipe B = x/3

By substituting these values, we get: 1/x + 3/x = 1/32 x = 128 minutes

Hence, option (a) is correct.

Incorrect

Solution: A

Let, the time is taken by pipe A = x Then, time is taken by pipe B = x/3

By substituting these values, we get: 1/x + 3/x = 1/32 x = 128 minutes