Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
A boat takes 26 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 4 km/hr and the speed of the boat in still water is 10 km/hr, what is the distance between A and B?
Correct
Solution: D
As per the given information, the velocity of the stream is 4 km/hr.
The speed of the boat in still water is 10 km/hr.
Therefore, speed of boat in downstream = (10+4) = 14 km/hr.
The speed of boat in upstream = (10-4) = 6 km/hr.
Let the distance between A and B be ‘x’. As C is in the midway between A and B, distance between B and C is x/2.
Total time taken to reach is 26 hours.
Therefore, x/14 + (x/2)/6 = 26
- x/14 + x/12 = 26
- (7x+6x)/84 = 26
- 13 x /84 = 26
- x/84 = 2
- x = 168.
The distance between A and B is 168 km.
Hence, option (d) is correct.
Incorrect
Solution: D
As per the given information, the velocity of the stream is 4 km/hr.
The speed of the boat in still water is 10 km/hr.
Therefore, speed of boat in downstream = (10+4) = 14 km/hr.
The speed of boat in upstream = (10-4) = 6 km/hr.
Let the distance between A and B be ‘x’. As C is in the midway between A and B, distance between B and C is x/2.
Total time taken to reach is 26 hours.
Therefore, x/14 + (x/2)/6 = 26
- x/14 + x/12 = 26
- (7x+6x)/84 = 26
- 13 x /84 = 26
- x/84 = 2
- x = 168.
The distance between A and B is 168 km.
Hence, option (d) is correct.
-
Question 2 of 5
2. Question
Four persons are chosen at random from a group of 3 men, 5 women and 4 children. What is the probability of exactly two of them being men?
Correct
Solution: B
Total sample size of selecting 4 people out of 12 people (3 men, 5 women and 4 children) = 12c4= 495.
Various possibilities of having exactly two men in the group of four are:
(2 men AND 2 women) OR (2 men AND 2 children) OR (2 men AND 1 woman and 1 child)
Thus, it can be written in formula: (3c2 * 5c2) + (3c2 * 4c2) + (3c2 *5c1 *4c1)
è (3*10) + (3 * 6) + (3 *5*4) = 30+18+60 = 108.
Therefore, probability of exactly two of them being men is 108/495 = 12/55
Hence, option (b) is correct.
Incorrect
Solution: B
Total sample size of selecting 4 people out of 12 people (3 men, 5 women and 4 children) = 12c4= 495.
Various possibilities of having exactly two men in the group of four are:
(2 men AND 2 women) OR (2 men AND 2 children) OR (2 men AND 1 woman and 1 child)
Thus, it can be written in formula: (3c2 * 5c2) + (3c2 * 4c2) + (3c2 *5c1 *4c1)
è (3*10) + (3 * 6) + (3 *5*4) = 30+18+60 = 108.
Therefore, probability of exactly two of them being men is 108/495 = 12/55
Hence, option (b) is correct.
-
Question 3 of 5
3. Question
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in?
Correct
Solution: C
From the given data, we can get
A’s one day work = 1/24,
B’s one day work = 1/9 and
Cs one day work = 1/12.
Since, B and C start the work and left after 3 days, the work done by B and C is 3 *((1/9) +(1/12)) = 7/12.
Therefore, remaining work = 1- 7/12 =5/12.
Time taken by A to complete the remaining work = 24 * 5/12 =10 days.
Hence, option (c) is correct.
Incorrect
Solution: C
From the given data, we can get
A’s one day work = 1/24,
B’s one day work = 1/9 and
Cs one day work = 1/12.
Since, B and C start the work and left after 3 days, the work done by B and C is 3 *((1/9) +(1/12)) = 7/12.
Therefore, remaining work = 1- 7/12 =5/12.
Time taken by A to complete the remaining work = 24 * 5/12 =10 days.
Hence, option (c) is correct.
-
Question 4 of 5
4. Question
How many words of 4 letters with or without meaning be made from the letters of the word ‘NUMBER’, when repetition of letters is not allowed?
Correct
Solution: D
To form the word we use arrangement.
The word NUMBER have 6 alphabets.
Therefore, to form 4 letter word from the word NUMBER is 6P4= 6!/2!
- 6*5*4*3* 2!/2!
- 360
Hence, option (d) is correct.
Incorrect
Solution: D
To form the word we use arrangement.
The word NUMBER have 6 alphabets.
Therefore, to form 4 letter word from the word NUMBER is 6P4= 6!/2!
- 6*5*4*3* 2!/2!
- 360
Hence, option (d) is correct.
-
Question 5 of 5
5. Question
Tina goes to school from her house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If she takes 5 hours in total, then what is the distance between her house and school?
Correct
Solution: A
Let the distance between Tina’s house and school be ‘x’ km.
Therefore, time to cover the distance from her house to school =
(Distance/ speed) = (x/3) hours.
Similarly, time to cover the distance from her school to house = (x/2) hours.
It is given that total time taken for whole journey= 5 hours.
Thus, (x/3 + x/2)= 5
- ((2x+3x)/6)= 5
- (5x/6)=5
- 5x=30 or x=6
Thus, distance between her house and school is 6 km.
Hence, option (a) is correct
Incorrect
Solution: A
Let the distance between Tina’s house and school be ‘x’ km.
Therefore, time to cover the distance from her house to school =
(Distance/ speed) = (x/3) hours.
Similarly, time to cover the distance from her school to house = (x/2) hours.
It is given that total time taken for whole journey= 5 hours.
Thus, (x/3 + x/2)= 5
- ((2x+3x)/6)= 5
- (5x/6)=5
- 5x=30 or x=6
Thus, distance between her house and school is 6 km.
Hence, option (a) is correct