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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
When water heats up, it takes up more space. That means as oceans warm, sea levels rise. The study says this effect alone could make sea levels rise 30cm (12 inches) by the end of the century.
“That doesn’t sound like much, but there are many large cities around the world, much built on reclaimed land, that are not more than 30cm above sea level,” says Stephen Simpson, associate professor in marine biology and global change at the University of Exeter, in the UK. “Millions and millions of people would be displaced.” But on top of that, warming oceans are causing polar ice sheets to melt faster, which will make sea levels rise even more.
Which of the following is the most logical and critical corollary to the above passage?
Correct
Ans. A. The passage states that coastal cities built on reclaimed land need to worry. However the last line also says that sea levels could rise much more than 30cm. This means that the logical corollary is for all coastal cities to safeguard themselves against rising sea level.
Incorrect
Ans. A. The passage states that coastal cities built on reclaimed land need to worry. However the last line also says that sea levels could rise much more than 30cm. This means that the logical corollary is for all coastal cities to safeguard themselves against rising sea level.
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Question 2 of 5
2. Question
The age of Abhay is twice that of Dolly. The age of Shyam is 10 years more than that of Akash. Akash is 5 years older than Dolly. If the combined age of all the four is 70 years, what is the ratio of the age of Abhay and Akash?
Correct
Solution: D
Let the age of Dolly be x. Then age of Abhay is 2x. Age of Akash is x+5 and that of Shyam is x+15.
Therefore, x+ 2x+ x+5+ x+15 =70. Solving, we get x= 10.So, the age of Abhay is 20 years and that of Akash is 15 years. Hence, the ratio of the age of Abhay to that of Akash is 20 : 15 i.e. 4:3.
Hence, option(d) is correct.
Incorrect
Solution: D
Let the age of Dolly be x. Then age of Abhay is 2x. Age of Akash is x+5 and that of Shyam is x+15.
Therefore, x+ 2x+ x+5+ x+15 =70. Solving, we get x= 10.So, the age of Abhay is 20 years and that of Akash is 15 years. Hence, the ratio of the age of Abhay to that of Akash is 20 : 15 i.e. 4:3.
Hence, option(d) is correct.
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Question 3 of 5
3. Question
There are 256 girls and 192 boys in a school, having separate classes for girls and boys. Find the minimum possible total number of classes, if each class in the school has the same number of students?
Correct
Solution: C
The number of classes will be minimum, if the number of students in each class is the highest possible.
Now, 256 = 2^8 and 192 = 2^6 * 3
Hence, the HCF of the above two numbers is 2^6 = 64.
Hence, the minimum possible total number of classes = 256/64 + 192/64 = 4 + 3 = 7.Hence, option (c) is correct.
Incorrect
Solution: C
The number of classes will be minimum, if the number of students in each class is the highest possible.
Now, 256 = 2^8 and 192 = 2^6 * 3
Hence, the HCF of the above two numbers is 2^6 = 64.
Hence, the minimum possible total number of classes = 256/64 + 192/64 = 4 + 3 = 7.Hence, option (c) is correct.
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Question 4 of 5
4. Question
In a competition, four ladies step off together. Their steps measure 36 cm, 48 cm, 21 cm and 28 cm respectively. What is the minimum distance each should walk so that all can cover the same distance in complete steps?
Correct
Solution: A
The distance walked by each of them is same as well as minimum possible to ensure that everyone has taken complete steps. The ‘minimum’ word in the question indicates that we need to find the least common multiple (LCM).
The LCM of 36 cm, 48 cm, 21 cm and 28 cm = 1008 cm.
So, the required minimum distance = 1008 cm.Hence, option(a) is correct.
Incorrect
Solution: A
The distance walked by each of them is same as well as minimum possible to ensure that everyone has taken complete steps. The ‘minimum’ word in the question indicates that we need to find the least common multiple (LCM).
The LCM of 36 cm, 48 cm, 21 cm and 28 cm = 1008 cm.
So, the required minimum distance = 1008 cm.Hence, option(a) is correct.
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Question 5 of 5
5. Question
In a group of 130 husbands, 70 can make tea and 50 can make both tea and coffee. If every husband can make at least one drink out of tea and coffee, then how many husbands can make only tea and only coffee respectively?
Correct
Solution: B
Let T and C be the number of husbands who can make tea and coffee respectively.
Now, T = 70, T Ո C= 50 and T U C= 130
T U C = T + C – (T Ո C)
130= 70+ C – 50
C= 110
Husbands who can make only tea= T – (T Ո C) = 70- 50= 20
Husbands who can make only coffee= C – (T Ո C) = 110- 50= 60Hence, option(b) is correct.
Incorrect
Solution: B
Let T and C be the number of husbands who can make tea and coffee respectively.
Now, T = 70, T Ո C= 50 and T U C= 130
T U C = T + C – (T Ո C)
130= 70+ C – 50
C= 110
Husbands who can make only tea= T – (T Ո C) = 70- 50= 20
Husbands who can make only coffee= C – (T Ո C) = 110- 50= 60Hence, option(b) is correct.
