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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The tragedy of specialisation is that it leads members of the knowledge industry to see little beyond their bulwarks. And indeed, the world views of highly specialised domains are often so distinct that they have created not only disparate paradigms but distinct worlds. It, therefore, becomes difficult or impossible for an economist to appreciate the importance and value of biodiversity or why its loss is a major casualty (unless he or she tries to monetise it), or for an engineer to understand why decentralised solar power that allows greater democratisation among local communities is an opportunity to be grabbed instead of installing large solar parks by mega-corporations. It also makes it near impossible for a molecular biologist to understand that more targeted and improved ways to cut and paste DNA is not the point being made by those concerned about genetically modified organisms. It is about ownership, biodiversity, science and soils — cross-cutting domains that super-specialists will not be able to see.
Which of the following is the most logical and critical inference of the passage?
Correct
Ans. B. A is also a logical inference, however it is not the most accurate as the focus of the passage is on explaining that super specialists are unable to look beyond their immediate field of interest which means that they end up developing tunnel vision. Hence B is the most accurate answer.
Incorrect
Ans. B. A is also a logical inference, however it is not the most accurate as the focus of the passage is on explaining that super specialists are unable to look beyond their immediate field of interest which means that they end up developing tunnel vision. Hence B is the most accurate answer.
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Question 2 of 5
2. Question
A shopkeeper had 750 kg of rice. He sold a portion of it at a certain profit percentage. The remaining 2/5th part of the whole lot was infested by pests and had to be sold at a loss of 15%. If for the entire 750 kg rice, the shopkeeper had no profit no loss, then what was the profit percentage at which the first
part of rice was sold?Correct
Solution: C
Let’s assume the cost price of rice be Rs. 100 per kg.
Therefore, total cost price = Quantity of Rice × Price per kg = 750 × 100 = Rs. 75,000.
It is given that, the remaining part is 2/5 th of the total and was sold at 15% loss. Thus, the first part is 3/5th of the total.Let us assume that 3/5th part is sold at x% profit.
Therefore, Net profit on this part = 3/5 × 75000 × x/100 = Rs. 450x.
Net loss on 2/5th part = 2/5 × 75000 × 15/100 = Rs. 4,500.
According to the question, there is no net profit or loss. So, the profit made on 3/5th part must be equal to the loss made on 2/5th part.Therefore, 450x = 4500.
Or x = 10%Hence, option(c) is correct.
Directions for the following 2 (two) questions.
Read the information given below and answer following two questions.
A bag contains 4 red, 4 green and 4 blue balls.
Two balls are drawn at random without replacement.Incorrect
Solution: C
Let’s assume the cost price of rice be Rs. 100 per kg.
Therefore, total cost price = Quantity of Rice × Price per kg = 750 × 100 = Rs. 75,000.
It is given that, the remaining part is 2/5 th of the total and was sold at 15% loss. Thus, the first part is 3/5th of the total.Let us assume that 3/5th part is sold at x% profit.
Therefore, Net profit on this part = 3/5 × 75000 × x/100 = Rs. 450x.
Net loss on 2/5th part = 2/5 × 75000 × 15/100 = Rs. 4,500.
According to the question, there is no net profit or loss. So, the profit made on 3/5th part must be equal to the loss made on 2/5th part.Therefore, 450x = 4500.
Or x = 10%Hence, option(c) is correct.
Directions for the following 2 (two) questions.
Read the information given below and answer following two questions.
A bag contains 4 red, 4 green and 4 blue balls.
Two balls are drawn at random without replacement. -
Question 3 of 5
3. Question
What is the probability that none of the balls drawn is green?
Correct
Solution: B
Total non-green balls = 8; hence chance of getting one in first draw = 8/12
After first successful draw, non-green balls = 7, also total balls is now 11
Hence, probability of getting non green = 7/11
Final probability = 8/12 × 7/11 = 14/33Hence, option(b) is correct.
Incorrect
Solution: B
Total non-green balls = 8; hence chance of getting one in first draw = 8/12
After first successful draw, non-green balls = 7, also total balls is now 11
Hence, probability of getting non green = 7/11
Final probability = 8/12 × 7/11 = 14/33Hence, option(b) is correct.
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Question 4 of 5
4. Question
What is the probability that one ball is blue and other green?
Correct
Solution: D
Blue balls = 4, green balls = 4
Probability = 2 × 4/12 × 4/11 = 8/33 (multiplied by 2 as there are two possibilities – green ball 1st and blue ball 1st)Hence, option(d) is correct.
Incorrect
Solution: D
Blue balls = 4, green balls = 4
Probability = 2 × 4/12 × 4/11 = 8/33 (multiplied by 2 as there are two possibilities – green ball 1st and blue ball 1st)Hence, option(d) is correct.
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Question 5 of 5
5. Question
One third of Ramesh’s marks in Arithmetic is equal to half his marks in English. If he gets a total of 150 marks in both the subjects, how many marks has he got in English?
Correct
Solution: A
Let the marks obtained in Arithmetic and English be x and y respectively.
According to the given condition,1/3 *x = y/2
==> 2x – 3y = 0 ….(i)
==> x+y= 150….(ii)
From (i) and (ii) we get,
y= 60.
Thus, the number of marks obtained in English = 60
Hence, option (a) is the correct.Incorrect
Solution: A
Let the marks obtained in Arithmetic and English be x and y respectively.
According to the given condition,1/3 *x = y/2
==> 2x – 3y = 0 ….(i)
==> x+y= 150….(ii)
From (i) and (ii) we get,
y= 60.
Thus, the number of marks obtained in English = 60
Hence, option (a) is the correct.
