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Question 1 of 5
1. Question
Two pipes can fill a tank in 8 hrs & 6 hrs respectively. If they are opened on alternate hours and if pipe A gets opened first, then in how many hours, the tank will be full?
Correct
answer: (b)
Explanation
Pipe A’s work in 1 hr = 1/8
Pipe B’s work in 1 hr = 1/6Pipes (A+B)’s work in first 2 hrs when they are opened alternately = 1/8 + 1/6 = 7 /24
Now,
In 4 hrs they fill : 2 X (7/24) = 7/12
In 6 hrs they fill : 3 X (7/24) = 7/8After 6 hrs, part left empty = 1/8
Now it is A’s turn to open up.
In one hr it fills 1/8 of the tank
So, the tank will be full in = 6 hrs + 1 hr = 7 hrs
Incorrect
answer: (b)
Explanation
Pipe A’s work in 1 hr = 1/8
Pipe B’s work in 1 hr = 1/6Pipes (A+B)’s work in first 2 hrs when they are opened alternately = 1/8 + 1/6 = 7 /24
Now,
In 4 hrs they fill : 2 X (7/24) = 7/12
In 6 hrs they fill : 3 X (7/24) = 7/8After 6 hrs, part left empty = 1/8
Now it is A’s turn to open up.
In one hr it fills 1/8 of the tank
So, the tank will be full in = 6 hrs + 1 hr = 7 hrs
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Question 2 of 5
2. Question
Two pipes A & B can fill a tank in 5 min & 10 min respectively. Both the pipes are opened together but after 2 min, pipe A is turned off. What is the total time required to fill the tank?
Correct
Correct answer (b)
Hint:
Assume the total time required = x + 2 min
Part filled by pipe A in 1min = 1/5 & part filled by B in 1 min = 1/10
After 2 min, part filed by A & B together = 2 [ 1/5 + 1/10] = 3/5Remaining part = 1 – 3/5 = 2/5
Part filled by pipe B in 1 min = 1/10As pipe A is turned off after 2 minutes, we get the relation as,
Part filled by (A + B) in 1 hr :: Total part filled Remaining part Time taken 1/10 : 2/5 :: 1: x
x = (2/5) x 1 x 10 = 4 min
Tank will be full in ( 2 min + 4 min) = 6 min
Incorrect
Correct answer (b)
Hint:
Assume the total time required = x + 2 min
Part filled by pipe A in 1min = 1/5 & part filled by B in 1 min = 1/10
After 2 min, part filed by A & B together = 2 [ 1/5 + 1/10] = 3/5Remaining part = 1 – 3/5 = 2/5
Part filled by pipe B in 1 min = 1/10As pipe A is turned off after 2 minutes, we get the relation as,
Part filled by (A + B) in 1 hr :: Total part filled Remaining part Time taken 1/10 : 2/5 :: 1: x
x = (2/5) x 1 x 10 = 4 min
Tank will be full in ( 2 min + 4 min) = 6 min
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Question 3 of 5
3. Question
It is observed that the pipe A can fill the tank in 15 hrs and the same tank is filled by pipe B in 20 hrs. The third pipe C can vacant the tank in 25 hrs. If all the pipes get opened initially and after 10 hrs, the pipe C is closed, then how long will it take to fill the tank?
Correct
Correct answer: (c)
Hint:
Assume that the tank will be full in ’10 + x’ hrs.Part filled by pipe A in 1 hr = 1/15
Part filled by pipe B in 1 hr = 1/20
Part emptied by pipe C in 1 hr = 1/ 25(A+ B)’s part filled in 1 hr = 1/15 + 1/20 = 7 /60
As Pipe C is closed after 10 hours, let us find the part of tank filled in 10 hrs.
Tank filled in 10 hrs = 10 (part filled by A in 1 hr + part filled by B in 1 hr– part emptied by C in 1 hr)
= 10 [1/15 + 1/20 – 1/25] = 23 /30Remaining part = 1 – part filled in 10 hours
= 1 – 23/30 = 7/30We know that,
Part filled by (A + B) in 1 hr :: Total part filled Remaining part Time taken So, we get the ratio as ,
7/60 : 7/30 :: 1 : x
So, the value of x = 2/30 x 1 x 60/7 = 2 hrs.
Hence, the tank will be full in x + 2 = 10 + 2 hrs = 12 hrs
Incorrect
Correct answer: (c)
Hint:
Assume that the tank will be full in ’10 + x’ hrs.Part filled by pipe A in 1 hr = 1/15
Part filled by pipe B in 1 hr = 1/20
Part emptied by pipe C in 1 hr = 1/ 25(A+ B)’s part filled in 1 hr = 1/15 + 1/20 = 7 /60
As Pipe C is closed after 10 hours, let us find the part of tank filled in 10 hrs.
Tank filled in 10 hrs = 10 (part filled by A in 1 hr + part filled by B in 1 hr– part emptied by C in 1 hr)
= 10 [1/15 + 1/20 – 1/25] = 23 /30Remaining part = 1 – part filled in 10 hours
= 1 – 23/30 = 7/30We know that,
Part filled by (A + B) in 1 hr :: Total part filled Remaining part Time taken So, we get the ratio as ,
7/60 : 7/30 :: 1 : x
So, the value of x = 2/30 x 1 x 60/7 = 2 hrs.
Hence, the tank will be full in x + 2 = 10 + 2 hrs = 12 hrs
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Question 4 of 5
4. Question
Two pipes fills a cistern in 15 hrs and 20 hrs respectively. The pipes are opened simultaneously and it is observed that it took 26 min more to fill the cistern because of leakage at the bottom. If the cistern is full, then in what time will the leak empty it?
Correct
Correct answer: (c)
Hint: Consider a pipe fills the tank in ‘x’ hrs. If there is a leakage in the bottom, the tank is filled in ‘y’ hrs.
The time taken by the leak to empty the full tank = xy hrs y – x But, direct values of x & y are not given. So, we need to find the work done by the two pipes in 1 hr = (1/15) + (1/20) = 7/60
Hence, the time taken by these pipes to fill the tank = 60/7 hrs = 8 .57 hrs = 8 hrs 34 min ——–( by multiplying ‘0.57’ hrs x 60 = 34 minutes)
Due to leakage, time taken = 8 hrs 34 min + 26 min = 8 hrs 60 min = 9 hrs ———-( because 60 min = 1 hr)
Thus, work done by (two pipes + leak) in 1 hr = 1/9
Hence, work done by leak in 1 hr = work done by two pipes – 1/9
= 7 /60 – 1/9 = 3/ 540 = 1/180Therefore, leak will empty the full cistern in 180 hours
Incorrect
Correct answer: (c)
Hint: Consider a pipe fills the tank in ‘x’ hrs. If there is a leakage in the bottom, the tank is filled in ‘y’ hrs.
The time taken by the leak to empty the full tank = xy hrs y – x But, direct values of x & y are not given. So, we need to find the work done by the two pipes in 1 hr = (1/15) + (1/20) = 7/60
Hence, the time taken by these pipes to fill the tank = 60/7 hrs = 8 .57 hrs = 8 hrs 34 min ——–( by multiplying ‘0.57’ hrs x 60 = 34 minutes)
Due to leakage, time taken = 8 hrs 34 min + 26 min = 8 hrs 60 min = 9 hrs ———-( because 60 min = 1 hr)
Thus, work done by (two pipes + leak) in 1 hr = 1/9
Hence, work done by leak in 1 hr = work done by two pipes – 1/9
= 7 /60 – 1/9 = 3/ 540 = 1/180Therefore, leak will empty the full cistern in 180 hours
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Question 5 of 5
5. Question
Passage
Having turned a blind eye to its responsibilities and duties, a large portion of the media is busy poisoning the minds of people. It is leaving no stone unturned in creating rioters instead of responsible citizens. It is an era when the difference between a journalist and a spokesperson of a party or the government has faded away. Communalism brews in news studios round the clock. The issues of the public are different from what is reflected in the media.
- Which of the following is the most logical, accurate and critical inference that can be drawn from the passage?
Correct
Your Answer : Correct Answer : B
The passage is a general commentary on the state of the media. The passage is not focussed on explaining the reason behind the fall in media standards, hence c is wrong. D is a generalist statement not conveying the sense of the passage. B is more accurate as compared to A because it is specific about the situation being highlighted in the passage
Incorrect
Your Answer : Correct Answer : B
The passage is a general commentary on the state of the media. The passage is not focussed on explaining the reason behind the fall in media standards, hence c is wrong. D is a generalist statement not conveying the sense of the passage. B is more accurate as compared to A because it is specific about the situation being highlighted in the passage
