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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
In a certain code, ELEPHANT is written as TNPEAHLE, the CROCODILE will be written as ?
Correct
Answer : B
Explanation:
Type – Simple Arrangement (Swap Coding) Positions of T and E and L and N are swapped. Also, positions of second E and P and H and A are swapped.
Therefore, for CROCODILE the code after swapping in the same pattern is ELOCIDRC.
Incorrect
Answer : B
Explanation:
Type – Simple Arrangement (Swap Coding) Positions of T and E and L and N are swapped. Also, positions of second E and P and H and A are swapped.
Therefore, for CROCODILE the code after swapping in the same pattern is ELOCIDRC.
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Question 2 of 5
2. Question
Each of two women and three men is to occupy one chair out of eight chairs, each of which numbered from 1 to 8. First, women are to occupy any two chairs from those numbered 1 to 4; and then the three men would occupy any, three chairs out of the remaining six chairs. What is the maximum number of different ways in which this can be done?
Correct
Ans : C
Explanation:
2 Women can occupy 2 chairs out of the first four chairs in 4P2 ways. 3 men can be arranged in the remaining 6 chairs in 6P3 ways. Hence, total no. of ways = 4P2 × 6P3 = 1440
Incorrect
Ans : C
Explanation:
2 Women can occupy 2 chairs out of the first four chairs in 4P2 ways. 3 men can be arranged in the remaining 6 chairs in 6P3 ways. Hence, total no. of ways = 4P2 × 6P3 = 1440
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Question 3 of 5
3. Question
Pipe A can fill a tank in 10 min and pipe B can empty it in 15 min. If both the pipes are opened in an empty tank, the time taken to make it full is
Correct
Answer : C
Answer Justification :
Part filled by pipe A in 1 min = 1/10 Part empty by pipe B in 1 min = 1/15 Total tank filled in minutes =
1/10 – 1/15 = 1/30
Hence, the tank will be filled in 30 min.
Incorrect
Answer : C
Answer Justification :
Part filled by pipe A in 1 min = 1/10 Part empty by pipe B in 1 min = 1/15 Total tank filled in minutes =
1/10 – 1/15 = 1/30
Hence, the tank will be filled in 30 min.
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Question 4 of 5
4. Question
In a chess competition involving some boys and girls of a school, every student had to play exactly one game with every other student. It was found that in 45 games both the players were girls and in 190 games both were boys. The number of games in which one player was a boy and the other was a girl is
Correct
Answer: A
Explanation:
Let number of girls = x
The number of boys = y
45 games in which both the players were girls xC2 = 45
x! / 2!(x-2)! = x(x-1) = 90
Therefore, x = 10.
190 games, where both the players were boys.
yC2 = 190 = y(y – 1) = 380
y = 20
Total Marks : 200 Mark Scored : 0
Hence the total number of games in which one player was a boy and the other was a girl = 10 × 20 = 200
Incorrect
Answer: A
Explanation:
Let number of girls = x
The number of boys = y
45 games in which both the players were girls xC2 = 45
x! / 2!(x-2)! = x(x-1) = 90
Therefore, x = 10.
190 games, where both the players were boys.
yC2 = 190 = y(y – 1) = 380
y = 20
Total Marks : 200 Mark Scored : 0
Hence the total number of games in which one player was a boy and the other was a girl = 10 × 20 = 200
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Question 5 of 5
5. Question
There are 6 tasks and 6 people. Task 1 cannot be assigned either to person 1 or to person 2; task 2 must be assigned to either person 3 or person 4. Every person is to be assigned one task. In how many ways can the assignment be done?
Correct
Answer : A
Explanation:
Task 1 can not be assigned to either person 1 or 2 i.e. there are 4 options. Task 2 can be assigned to 3 or 4.
So, there are only 2 options for task 2.
So required no. of ways =
2 options for task 2
3 options for task 1
4 options for task 3
3 options for task 4
2 options for task 5
1 option for task 6.
Total ways = 2 × 3 × 4 × 3 × 2 × 1 = 144
Incorrect
Answer : A
Explanation:
Task 1 can not be assigned to either person 1 or 2 i.e. there are 4 options. Task 2 can be assigned to 3 or 4.
So, there are only 2 options for task 2.
So required no. of ways =
2 options for task 2
3 options for task 1
4 options for task 3
3 options for task 4
2 options for task 5
1 option for task 6.
Total ways = 2 × 3 × 4 × 3 × 2 × 1 = 144