[Mission 2023] Insta–DART (Daily Aptitude and Reasoning Test) 02 August 2022
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
How many three-digit numbers can be formed from numbers 0, 2, 4, 6 and 8 which are
divisible by 5 or 2 (repetition of numbers is allowed).
Correct
Answer : D
Explanation:
Among given numbers, only when ‘0’ comes at the unit digit, that particular 3 digit number is
divisible by 5. In this condition even that 3 digit number is divisible by 2 also because it ends
with 0.
Now, we can find out the numbers divisible by 2 units place can be occupied by 0, 2, 4, 6 and 8.
Therefore 5 ways Hundred’s place can be occupied by all numbers except ‘0’ i.e., 4 ways
Ten’s place can be occupied by any given number that is, 5 ways.
Therefore, number of numbers with the given condition are,
5×4×5=100.
Incorrect
Answer : D
Explanation:
Among given numbers, only when ‘0’ comes at the unit digit, that particular 3 digit number is
divisible by 5. In this condition even that 3 digit number is divisible by 2 also because it ends
with 0.
Now, we can find out the numbers divisible by 2 units place can be occupied by 0, 2, 4, 6 and 8.
Therefore 5 ways Hundred’s place can be occupied by all numbers except ‘0’ i.e., 4 ways
Ten’s place can be occupied by any given number that is, 5 ways.
Therefore, number of numbers with the given condition are,
5×4×5=100.
Question 2 of 5
2. Question
A pair of dice is thrown simultaneously, find the probability that the sum is obtained 9 when there is an odd number on the first side.
Correct
Answer : D
There are 3 ways the first dice reads odd number i.e. 1, 3 or 5.
When first dice reads, the second dice can read any of the numbers from 1 to 6.
Number of possibilities = 3 × 6 =18.
But the sum of 9 can be obtained on two occasions i.e. (3,6) and (5,4).
Hence, the probability = 2/18 = 1/9.
Incorrect
Answer : D
There are 3 ways the first dice reads odd number i.e. 1, 3 or 5.
When first dice reads, the second dice can read any of the numbers from 1 to 6.
Number of possibilities = 3 × 6 =18.
But the sum of 9 can be obtained on two occasions i.e. (3,6) and (5,4).
Hence, the probability = 2/18 = 1/9.
Question 3 of 5
3. Question
A principle of Rs.1000 is being charged at 50% per annum. What is the interest for
3rd year at compound interest?
Correct
Answer – A
Since compound interest rate is 50%, then the principle will earn half of it every year.
So, simple interest or compound for the first year = 50% of Rs.1000 = Rs.500
Principle for the second year = Rs.1000 + Rs.500 = Rs.1500
Incorrect
Answer – A
Since compound interest rate is 50%, then the principle will earn half of it every year.
So, simple interest or compound for the first year = 50% of Rs.1000 = Rs.500
Principle for the second year = Rs.1000 + Rs.500 = Rs.1500
Question 4 of 5
4. Question
A, B and C invest in the ratio of 3:4:5. The percentage of return on their investments are 6%, 5% and 4% respectively. Find the total earnings, if B earns Rs.250 more than A
Correct
Answer : B
Let the investments of A, B and C be 3x, 4x and 5x respectively.
The earnings of A = 6% of 3x = 0.18x
The earnings of B = 5% of 4x = 0.2x
The earnings of C = 4% of 5x = 0.2x
B earns Rs.250 more than A i.e. 0.2x – 0.18x = 0.02x = Rs.250
