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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
If 4 (A’s capital) = 6 (B’s capital) = 10 (C’s capital), then out of a profit of Rs. 4650, C will receive
Correct
Answer : C
Let 4A = 6B = 1OC = k.
Then, A=k/4, B=k/6, and C=k/10
A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6. Hence, C’s share (4650×6)/31 = Rs 900.
Incorrect
Answer : C
Let 4A = 6B = 1OC = k.
Then, A=k/4, B=k/6, and C=k/10
A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6. Hence, C’s share (4650×6)/31 = Rs 900.
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Question 2 of 5
2. Question
A vessel of capacity 2 litre has 25% alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of mixture?
Correct
Answer : D
Amount of alcohol in first vessel = 0.25 x 2 = 0.5 litre,…
Amount of alcohol in second vessel = 0.4 / 6 = 2.4 litre..
Total amount of alcohol out of 10 litres of mixture is 0.5 + 2.4 = 2.9 litre ..
Hence, the concentration of the mixture is 29% =(2.9/10 x 100 )
Incorrect
Answer : D
Amount of alcohol in first vessel = 0.25 x 2 = 0.5 litre,…
Amount of alcohol in second vessel = 0.4 / 6 = 2.4 litre..
Total amount of alcohol out of 10 litres of mixture is 0.5 + 2.4 = 2.9 litre ..
Hence, the concentration of the mixture is 29% =(2.9/10 x 100 )
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Question 3 of 5
3. Question
How many degrees will the minute-hand move in 40 minutes?
Correct
Answer : D
The minute-hand moves 360° in 1 hour. Hence, in 40 minutes the minute-hand moves (360°/60°∗40)° = 240°
Incorrect
Answer : D
The minute-hand moves 360° in 1 hour. Hence, in 40 minutes the minute-hand moves (360°/60°∗40)° = 240°
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Question 4 of 5
4. Question
When the numerator of a fraction is decreased by 25% and its denominator is decreased by 20%, the new fraction obtained is 3/4. Find the original fraction?
Correct
Answer : B
Explanation:
Let the fraction be x/y. When the numerator decreased by 25% and the denominator decreased by 20% (x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5
Incorrect
Answer : B
Explanation:
Let the fraction be x/y. When the numerator decreased by 25% and the denominator decreased by 20% (x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5
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Question 5 of 5
5. Question
Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 3000 for 2 years at 10% per annum. The sum placed on simple interest is:
Correct
Answer : A
Compound interest = [P (1 + r/100)^t – P]
= [3000 (1 + 10/100)^2 – 3000] = 630 From data,Simple interest is half of compound interest Therefore, SI = 630/2 = 315 Time = 4 years, rate of interest = 5% pa Therefore Sum = [ (315*100) / (4*5)] = ₹1575
Incorrect
Answer : A
Compound interest = [P (1 + r/100)^t – P]
= [3000 (1 + 10/100)^2 – 3000] = 630 From data,Simple interest is half of compound interest Therefore, SI = 630/2 = 315 Time = 4 years, rate of interest = 5% pa Therefore Sum = [ (315*100) / (4*5)] = ₹1575
