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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Four friends, A, B, C and D distribute some money among themselves in such a manner that A get one less than B, C gets 5 more than D, D gets 3 more than B. Who gets the smallest amount?
Correct
Answer : A
Answer Justification : Solution: A gets one less than B. So, A < B C gets 5 more than D. So, D < C, D gets 3 more than B. So, B < D Combine all three inequalities, A < B < D < C…… B, C and D have more money than somebody else. So, A has the smallest amount.
Incorrect
Answer : A
Answer Justification : Solution: A gets one less than B. So, A < B C gets 5 more than D. So, D < C, D gets 3 more than B. So, B < D Combine all three inequalities, A < B < D < C…… B, C and D have more money than somebody else. So, A has the smallest amount.
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Question 2 of 5
2. Question
The average expenditure of Sharma for the January to June is Rs. 4200 and he spent Rs. 1200 in January and Rs.1500 in July. The average expenditure for the months of February to July is:
Correct
Answer : C
Explanation: Total Expenditure (Jan – June) = 4200 * 6 = 25200 Total Expenditure (Feb – June) = 25200 – 1200 = 24000 Total Expenditure (Feb – July) = 24000 + 1500 = 25500/6 = 4250
Incorrect
Answer : C
Explanation: Total Expenditure (Jan – June) = 4200 * 6 = 25200 Total Expenditure (Feb – June) = 25200 – 1200 = 24000 Total Expenditure (Feb – July) = 24000 + 1500 = 25500/6 = 4250
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Question 3 of 5
3. Question
40% of the students like Mathematics, 50% like English and 10% like both Mathematics and English. What % of the students like neither English nor Mathematics?
Correct
Answer : C
: Explanation: n(M or E) = n(M) + n(E) – n(M and E) n(M or E) = 40+50-10 = 80 So % of the students who like neither English nor Mathematics = 100 – 80 = 20%
Incorrect
Answer : C
: Explanation: n(M or E) = n(M) + n(E) – n(M and E) n(M or E) = 40+50-10 = 80 So % of the students who like neither English nor Mathematics = 100 – 80 = 20%
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Question 4 of 5
4. Question
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Correct
Answer : C
Explanation: Let their marks be (x + 9) and x. Then, x + 9 = 56/100(x + 9 + x) 25(x + 9) = 14(2x + 9) 3x = 99 x = 33 So, their marks are 42 and 33.
Incorrect
Answer : C
Explanation: Let their marks be (x + 9) and x. Then, x + 9 = 56/100(x + 9 + x) 25(x + 9) = 14(2x + 9) 3x = 99 x = 33 So, their marks are 42 and 33.
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Question 5 of 5
5. Question
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Correct
Answer : A
Answer Justification : Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 5x = 20 x = 4. Age of the youngest child = x = 4 years.
Incorrect
Answer : A
Answer Justification : Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 5x = 20 x = 4. Age of the youngest child = x = 4 years.
