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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
A dealer sold a TV at a loss of 2.5%. Had he sold it for Rs. 100 more, he would have gained 7.5%. To gain 12.5% he should sell it for:
Correct
Answer: D
Explanation – Let C.P be Rs.x then,(107.5 % of x) – (97.5 % of x) = 100 => 10% of x = 100 => x =1000 ∴ desired S.P = 112.5 % of Rs. 100 = Rs.(225/2 x 1/100 x 1000) =Rs. 1125
Incorrect
Answer: D
Explanation – Let C.P be Rs.x then,(107.5 % of x) – (97.5 % of x) = 100 => 10% of x = 100 => x =1000 ∴ desired S.P = 112.5 % of Rs. 100 = Rs.(225/2 x 1/100 x 1000) =Rs. 1125
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Question 2 of 5
2. Question
Rakesh rows to the place 80 km away and back in 20 hours. He finds that he can row 8 km downstream in the same time as 4 km upstream. The speed of the boat in stillwater is
Correct
Answer : A
Explanation: If Rakesh moves 8 km downstream in X hours Downstream speed = 8/X kmph upstream speed = 4/X kmph Now 80/(8/X) + 80/(4/X)=20 X=2/3 downstream Speed = 8/(2/3)= 12 kmph upstream Speed = 4/(2/3)= 6 kmph Rate of the stream = (12+6)/2= 9 kmph
Incorrect
Answer : A
Explanation: If Rakesh moves 8 km downstream in X hours Downstream speed = 8/X kmph upstream speed = 4/X kmph Now 80/(8/X) + 80/(4/X)=20 X=2/3 downstream Speed = 8/(2/3)= 12 kmph upstream Speed = 4/(2/3)= 6 kmph Rate of the stream = (12+6)/2= 9 kmph
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Question 3 of 5
3. Question
A man purchased wheat worth Rs. 400. He sold 3/4 at a loss of 10% and the reminder at a gain of 10%. On the whole he gets:
Correct
Answer : A
Explanation – C.P of 3/4th = Rs. (3/4 x 400) = Rs. 300, C.P of 1/4th = Rs. 100 ∴ Total S.P = (90% of Rs. 300 + 110% of Rs. 100) = Rs. 380, Loss = (20/400 x 100)% = 5%
Incorrect
Answer : A
Explanation – C.P of 3/4th = Rs. (3/4 x 400) = Rs. 300, C.P of 1/4th = Rs. 100 ∴ Total S.P = (90% of Rs. 300 + 110% of Rs. 100) = Rs. 380, Loss = (20/400 x 100)% = 5%
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Question 4 of 5
4. Question
The present ages of three persons are in the ratio 4:7:9. Eight years ago, the sum of their ages was 56. Find their present (ages in years)?
Correct
Answer : B
Explanation: Let the ages of three persons be 4x, 7x and 9x respectively. Eight years ago, their ages were (4x-8), (7x-8) and (9x-8). The sum of their ages eight years ago = 4x – 8 + 7x – 8 + 9x – 8 = 20x – 24 = 56. 20x = 80 x = 4 Therefore, their respective ages are 16, 28 and 36 years.
Incorrect
Answer : B
Explanation: Let the ages of three persons be 4x, 7x and 9x respectively. Eight years ago, their ages were (4x-8), (7x-8) and (9x-8). The sum of their ages eight years ago = 4x – 8 + 7x – 8 + 9x – 8 = 20x – 24 = 56. 20x = 80 x = 4 Therefore, their respective ages are 16, 28 and 36 years.
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Question 5 of 5
5. Question
Find the least number which when divided by 10, 11, 15 and 22 leaves 3, 4, 8 and 15 as remainders, respectively.
Correct
Answer : B
Explanation: Least number which when divided by 10, 11, 15 and 22 so as to leave 3, 4, 8 and 15 as remainders, respectively will be equal to [LCM (10, 11, 15, 22) –7] Since, LCM of 10, 11, 15 and 22 is 330 ∴ The required number = 330 – 7 = 323
Incorrect
Answer : B
Explanation: Least number which when divided by 10, 11, 15 and 22 so as to leave 3, 4, 8 and 15 as remainders, respectively will be equal to [LCM (10, 11, 15, 22) –7] Since, LCM of 10, 11, 15 and 22 is 330 ∴ The required number = 330 – 7 = 323
