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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
840, ?, 420, 140, 35, 7
Correct
Answer : b
Series pattern ÷ ¸÷1, ¸÷2, ¸÷3, ¸÷4, ¸÷5
∴Missing term = (840/1) = 840
Incorrect
Answer : b
Series pattern ÷ ¸÷1, ¸÷2, ¸÷3, ¸÷4, ¸÷5
∴Missing term = (840/1) = 840
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Question 2 of 5
2. Question
13, 35, 57, 79, 911, ?
Correct
Answer : a
Series pattern
The elements of the given series are the
numbers formed by joining together
consecutive odd numbers in order,
i.e., 1 and 3, 3 and 5, 5 and 7, 7 and 9,
9 and 11, ..
∴Missing term = Number formed by
joining 11 and 13 = 1113
Incorrect
Answer : a
Series pattern
The elements of the given series are the
numbers formed by joining together
consecutive odd numbers in order,
i.e., 1 and 3, 3 and 5, 5 and 7, 7 and 9,
9 and 11, ..
∴Missing term = Number formed by
joining 11 and 13 = 1113
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Question 3 of 5
3. Question
4 goats or sheeps can graze a field in 50 days. 2 goats and 9 sheeps can graze the field in
Correct
Answer : d
Part of field grazed by 4 goats in 1 day = (1/50)
Part of field grazed by 1 goat in 1 day = (1/(50 ´4)=(1/200)
4g=6s [here, g=goats, and s= sheeps ]
1s = (4/6)g=(2/3)g
Now, 2g + 6g=8g
∴8 goats can graze the field in
[(1/8) /200]= 25 days
Incorrect
Answer : d
Part of field grazed by 4 goats in 1 day = (1/50)
Part of field grazed by 1 goat in 1 day = (1/(50 ´4)=(1/200)
4g=6s [here, g=goats, and s= sheeps ]
1s = (4/6)g=(2/3)g
Now, 2g + 6g=8g
∴8 goats can graze the field in
[(1/8) /200]= 25 days
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Question 4 of 5
4. Question
23, 42.2, 80.6, 157.4, 311?
Correct
Answer : a
∴Missing term = 618.2
Incorrect
Answer : a
∴Missing term = 618.2
-
Question 5 of 5
5. Question
1, 2, 6, 21, 88, 445, ?
Correct
Answer : b
Series pattern
1×1+1 = 2
2×2+ 2 = 6
6×3+3 = 21
21 x4 + 4 = 88
88 x5+5 = 445
445 x6+6 = 2676
should come in place of ‘?’
Incorrect
Answer : b
Series pattern
1×1+1 = 2
2×2+ 2 = 6
6×3+3 = 21
21 x4 + 4 = 88
88 x5+5 = 445
445 x6+6 = 2676
should come in place of ‘?’
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