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Question 1 of 5
1. Question
In a family, the father took of the cake and he had 3 times as much as each of the other members had. The total number of family members is
Correct
Answer : c
Let there be (x + 1) members. Then,
Father’s share 1/4 share of each other member 3/4
∴ 3 (3/4x) = 1/4
4x = 36
X = 9
Hence, total number of family members = 10.
Incorrect
Answer : c
Let there be (x + 1) members. Then,
Father’s share 1/4 share of each other member 3/4
∴ 3 (3/4x) = 1/4
4x = 36
X = 9
Hence, total number of family members = 10.
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Question 2 of 5
2. Question
A waiter’s salary consists of his salary and tips. During one week his tips were of his salary. What fraction of his income came from tips?
Correct
Answer : d
Let salary = Rs. x. Then tips = Rs. (5/4)x Total income = Rs. (x+(5/4)x) = Rs. (9x/4)
∴Required fraction = ((5x/4)* (4/9x)) = 5/9
Incorrect
Answer : d
Let salary = Rs. x. Then tips = Rs. (5/4)x Total income = Rs. (x+(5/4)x) = Rs. (9x/4)
∴Required fraction = ((5x/4)* (4/9x)) = 5/9
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Question 3 of 5
3. Question
Three friends had dinner at a restaurant. When the bill was received, Amita paid 2/5 as much as Veena paid and Veena paid ½ as much as Tanya paid. What fraction of the bill did Veena pay?
Correct
Answer : b
Let Tany’s share = Rs. x
Then, Veena’s share = Rs. (x/2)
Amita’s share = Rs. ((2/3) *(x/2)) = Rs. (x/3)
Total bill = Rs. (x+(x/2)+(x/3)) = Rs. (11x/6)
∴Required fraction = ((x/2)(6/11x)) = 3/11
Incorrect
Answer : b
Let Tany’s share = Rs. x
Then, Veena’s share = Rs. (x/2)
Amita’s share = Rs. ((2/3) *(x/2)) = Rs. (x/3)
Total bill = Rs. (x+(x/2)+(x/3)) = Rs. (11x/6)
∴Required fraction = ((x/2)(6/11x)) = 3/11
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Question 4 of 5
4. Question
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete?
Correct
Answer : a
Out of 5 girls, 1 took part in fete. Out of8 boys, 1 took part in fete.
∴Out of 13 students, 2 took part in fete.
Hence,2/13 of the total number took part in fete.
Incorrect
Answer : a
Out of 5 girls, 1 took part in fete. Out of8 boys, 1 took part in fete.
∴Out of 13 students, 2 took part in fete.
Hence,2/13 of the total number took part in fete.
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Question 5 of 5
5. Question
In a class, 3/5 of the students are girls and rest are boys. If 2/9 of the girls and of the boys are absent, what part of the total number of students is present?
Correct
Answer : c
Girls = 3/5, Boys = (1-(3/5)= 2/5
Fraction of students absent = 2/3 of 3/5+1/4 of 2/5 = 6/45 + 1/10 = 21/90 = 7/30
∴Fraction of students present = (1-(7/30))=23/30.
Incorrect
Answer : c
Girls = 3/5, Boys = (1-(3/5)= 2/5
Fraction of students absent = 2/3 of 3/5+1/4 of 2/5 = 6/45 + 1/10 = 21/90 = 7/30
∴Fraction of students present = (1-(7/30))=23/30.
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