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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
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Question 1 of 5
1. Question
A village having a population of 4000 requires 150 litres of water per head per day. It has a tank measuring 20 m x 15 m x 6 m. The water of this tank will last for
Correct
Ans: (b)
Total volume = l * b * h
= 20 x 15 x 6
= 1800 m3
= 1800000 litres
One day consumption of water to
= 4000 x 150
= 600000 litres
So, number of days required to empty tank
1800000/600000=3days
Incorrect
Ans: (b)
Total volume = l * b * h
= 20 x 15 x 6
= 1800 m3
= 1800000 litres
One day consumption of water to
= 4000 x 150
= 600000 litres
So, number of days required to empty tank
1800000/600000=3days
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Question 2 of 5
2. Question
The diameters of two circular coins are in the ratio of 1:3. The smaller coin is, made to roll around the bigger coin till it returns to the position from where the process of rolling started. How many times the smaller coin rolled around the bigger coin?
Correct
Ans: (c)
Ratios of perimeter of bigger coin to smaller coin
= 27 x (3): 211 x (1)
= 3:1
Hence, smaller coin will roll 3 times around the bigger coin.
Incorrect
Ans: (c)
Ratios of perimeter of bigger coin to smaller coin
= 27 x (3): 211 x (1)
= 3:1
Hence, smaller coin will roll 3 times around the bigger coin.
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Question 3 of 5
3. Question
An equilateral triangular plate is to be cut into n number of identical small equilateral triangular plates. Which of the following can be possible value of n?
Correct
Ans: (b)
An equilateral triangle whenever divided into equal parts, gives rise to 4 equilateral triangles. Hence, it is always in powers of 4, whenever it is equally divided further. Thus, 44 = 256 small equilateral triangles are possible.
Incorrect
Ans: (b)
An equilateral triangle whenever divided into equal parts, gives rise to 4 equilateral triangles. Hence, it is always in powers of 4, whenever it is equally divided further. Thus, 44 = 256 small equilateral triangles are possible.
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Question 4 of 5
4. Question
Consider the volumes of the following.
- A parallelopiped of length 5 cm, breadth 3 cm and height 4 cm
- A cube of each side 4 cm
- A cylinder of radius 3 cm and length 3 cm
- A sphere of radius 3 cm
The volumes of these in the decreasing order is
Correct
Ans: (d)
Volume of parallelopiped =l* b* h= 5 * 3 * 4 = 60 cm3
Volume of cube = (side)3 = 4(3) = 64 cm3.
Volume of cylinder = r2h = 3.14 x 3(2 )x 3 = 84.78 cm3.
Volume of sphere= 4/3r3=4×3.14×3(2) = 113.04 cm3.
Thus, the correct decreasing order is 4, 3, 2, 1.
Incorrect
Ans: (d)
Volume of parallelopiped =l* b* h= 5 * 3 * 4 = 60 cm3
Volume of cube = (side)3 = 4(3) = 64 cm3.
Volume of cylinder = r2h = 3.14 x 3(2 )x 3 = 84.78 cm3.
Volume of sphere= 4/3r3=4×3.14×3(2) = 113.04 cm3.
Thus, the correct decreasing order is 4, 3, 2, 1.
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Question 5 of 5
5. Question
What is the maximum number of pieces of 5 cm´ 5 cm x 10 cm of cake that can be cut from a big cake of 5 cm x 30 cm x 30 cm size?
Correct
Ans: (C)
Let the maximum number of small pieces of cake be n. Now,
nx (5 * 5 * 10) = 5 x 30 x 30
n = (5x 30 x 30)/5×5×10 = 18
Incorrect
Ans: (C)
Let the maximum number of small pieces of cake be n. Now,
nx (5 * 5 * 10) = 5 x 30 x 30
n = (5x 30 x 30)/5×5×10 = 18
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